Some questions are timeless and they never grow old; no matter how much they grow old their interest never dies. Earlier, I asked a simple puzzle based on a conversation on SQLAuthority Page, and have received an overwhelming response from readers. I still get emails related to this puzzle every day. Let us see a quick puzzle between SQL Join and SQL Null.
Before we move on, I suggest you read the question and its initial solution here:
Question: A Quick Puzzle on JOIN and NULL – SQL Brain Teaser
Solution: Solution – A Quick Puzzle on JOIN and NULL – SQL Brain Teaser
The puzzle had three parts and the users had to fill up the second part, which I had left it for them to complete. I received many responses, and here is another response which is absolutely valid and worthy of acknowledgment. Once again, before you read the solution, I suggest you give the puzzle a quick try. Perhaps you’d find another neat way to solve this puzzle.
The puzzle had three parts:
- Setup
- Fill in the blanks – T-SQL code
- Query and Resultset
Just like this puzzle, there are many other learning nuggets in our SQL Server Questions and Answers course online.
Complete Solution Query – SQL Join
USE TempDB GO -- Sample Table CREATE TABLE FirstTable (Col1 INT) CREATE TABLE SecondTable (Col1 INT) GO ALTER TABLE FirstTable ADD CONSTRAINT UX_FirstTable UNIQUE NONCLUSTERED (Col1); ALTER TABLE SecondTable ADD CONSTRAINT UX_SecondTable UNIQUE NONCLUSTERED (Col1); GO INSERT INTO FirstTable (Col1) VALUES (NULL) GO INSERT INTO SecondTable (Col1) VALUES (NULL) GO -------------------------------------- -- Solution SELECT st.col1 FROM FirstTable ft RIGHT JOIN SecondTable st ON st.Col1 = ft.Col1 UNION ALL SELECT st.col1 FROM FirstTable ft LEFT JOIN SecondTable st ON st.Col1 = ft.Col1 GO DROP TABLE FirstTable; DROP TABLE SecondTable; GO
Now the reason I did not select this as a valid answer is because if you notice original solution required to insert one row into the FirstTable. However, when you look at carefully, you can notice even this solution is a valid solution. There were many other solutions which require to change T-SQL which I initially provided, however, as per the puzzle that was not allowed.
Any other solution out there?
Reference:Â Pinal Dave (https://blog.sqlauthority.com)
4 Comments. Leave new
Hi Pinal
I initially wrong this but later today I run both queries and there is difference in execution plan as well, can you please explain two quries. Thanks,
SELECT st.col1
FROM FirstTable ft
Full OUTER JOIN SecondTable st ON st.Col1 = ft.Col1
Khurram
How we can call a store procedure in crystal report
Hi Pinal Sir,
Thank you for selecting this as one of the answer for puzzle.
Thank$
Chirag Satasiya