In this blog post we will learn various tips related to Querying Special Characters with the help of wildcard in SQL Server.
Querying Special Characters
Some special characters can be tricky to pattern match since they themselves can represent different values at different times. Let’s look at some examples. Here is a quick look at all the records in the [Grant] table of the JProCo database. Note: Since [Grant] is also a keyword it must be enclosed in square brackets or double quotes to designate it as the [Grant] table and now the keyword. Take a look at many of the names in the Grant Name field and notice we have many names with special symbols in them. See figure below:
Finding literal % signs with wildcards
We learned about special characters in yesterdays post called wildcards. When using the percentage sign % or the underscore _ we can do relative searches. We have a grant called “92 Purr_Scents %% team” which has a percentage symbol in the name. We have other grants with percentages in their names. How do you search for a percentage sign with two wildcards on either side? It would appear to SQL that you’re looking for three wildcards as seen in the query below:
--Bad query pattern logic (finds all Grant records) SELECT * FROM [GRANT] WHERE GrantName LIKE '%%%'
We have three special characters and no literal percent symbol. Help is on the way again with the square brackets. Take the wild card you want to use as a literal percentage symbol and surround it with square brackets. You see two grants having a percentage symbol within their names. In this example the square brackets give you the literal percentage symbol. In this figure you see just the two grants that have a % sign in the name.
Finding literal _ signs with wildcards
You may know that the underscore is also a wildcard. We can use this to find a specific second letter. How many Grants have the letter A for the second letter can be found with the following query:
--Find Grants where A is the 2nd letter. SELECT * FROM [GRANT] WHERE GrantName LIKE '_A%'
GrantID | GrantName | EmpID | Amount |
6 | TALTA_Kishan International | 3 | 18100 |
10 | Call Mom @Com | 5 | 750 |
In this example by asking for one character before the letter A and any amount afterward, we names like “TALTA_Kishan International” and “Call Mom @Com”. The % symbol wildcard can represent many characters while the _ symbol wildcard always represents exactly one.
To find the Grants with underscores in the name we do the same technique we used with the % wildcard. Again, we take the wildcard that you want to evaluate and put it in square brackets.
You see three grants having underscores in their names (Figure 2.20). In this example the square brackets tell SQL you are looking for a literal underscore character.
Note: If you want to setup the sample JProCo database on your system you can watch this video.
Question 2:
Q 2.) You want to find all grant names that have an Underscore as the second letter. Which SQL code would you use?
- SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘
- SELECT * FROM [Grant] WHERE GrantName like ‘[_]_% ‘
- SELECT * FROM [Grant] WHERE GrantName like ‘_%[_]%_ ‘
- SELECT * FROM [Grant] WHERE GrantName = ‘_[_]% ‘
- SELECT * FROM [Grant] WHERE GrantName = ‘[_]_% ‘
- SELECT * FROM [Grant] WHERE GrantName = ‘_%[_]%_ ‘
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Reference: Pinal Dave (https://blog.sqlauthority.com)
186 Comments. Leave new
Question 2:
Q 2.) You want to find all grant names that have and Underscore as the second letter. Which SQL code would you use?
Answer is
1. SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
Because ‘_[_]% ‘ represents
_ —> Represents first character of the word that may be any character
[_] —> ‘_’ character in ‘[”]’ square braces represents looking for this
character the square brace will nullify(ignores) its(special character)
meaning.
% —> any number of character after [_]
if u want display only second letter is ‘_’ then the option 1 is correct
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]%’
if we want disply second letter as well as any where in the name ‘_’ is exists
option 3rd is coorect
SELECT * FROM [Grant]
WHERE GrantName like ‘_%[_]%_’
country : India
Correct Answer is Option 1
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
Country – INDIA (Gujarat)
if u want display only second letter is ‘_’ then the option 1 is correct
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]%’
country : India
Correct Answe is 3
The options 1 and 3 are giving same result. But my vote is for Option-3
Narendra (India)
Correct answer is option 1 :
First _ will work as wildcard character and will result all the GrantNames.
Second _ is in Square Brackets and will result all the GrantNames having _ as Second character.
Country – India
my answer is Option 1, i.e SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
I’m from INDIA
#1 is the correct answer to find all rows with GrantName having an underscore as the second character.
Jason from USA
Option 1
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
is correct.
country: India
Correct answer is:
1.SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
Country ==> United States
1. Is the correct answer. The _ wildcard in the first position in the phrase after quotation ask SQL to litterally look for the second letter. The _ in square brackets ask SQL to sort by that symbol.
Ron A. Farris
Country – United States of America
First,
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
Country Canada
The answer is 1.
SELECT * FROM [Grant] WHERE GrantName LIKE ‘_[_]%’
Country = USA
Correct answer :-
Option 1
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
grant names that have and Underscore as the second letter find by
‘_[_]%’ pattern with like .. as second letter is Underscore which is wildcard
so , put it into [ ] ..
country: India
Nice post …
The correct answer is option 1:
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]%
Reason: _ being a wildcard character, provides appropriate output required.
Divya
US
SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘
–
Rahul
Hyderabad (India)
Correct answer is #1 SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
Thank you
Lisa (USA)
SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘
Question #1 is correct.
SELECT * FROM [Grant]
WHERE GrantName like ‘_[_]% ‘
—
Timmy
TX, USA