SQL SERVER – Tips from the SQL Development Series – Wildcard – Querying Special Characters – Day 2 of 35

In this blog post we will learn various tips related to Querying Special Characters with the help of wildcard in SQL Server.

Querying Special Characters

Some special characters can be tricky to pattern match since they themselves can represent different values at different times. Let’s look at some examples. Here is a quick look at all the records in the [Grant] table of the JProCo database. Note: Since [Grant] is also a keyword it must be enclosed in square brackets or double quotes to designate it as the [Grant] table and now the keyword. Take a look at many of the names in the Grant Name field and notice we have many names with special symbols in them. See figure below:

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_1

Finding literal % signs with wildcards

We learned about special characters in yesterdays post called wildcards. When using the percentage sign % or the underscore _ we can do relative searches. We have a grant called “92 Purr_Scents %% team” which has a percentage symbol in the name. We have other grants with percentages in their names. How do you search for a percentage sign with two wildcards on either side? It would appear to SQL that you’re looking for three wildcards as seen in the query below:

--Bad query pattern logic (finds all Grant records)
SELECT *
FROM [GRANT]
WHERE GrantName LIKE '%%%'

We have three special characters and no literal percent symbol. Help is on the way again with the square brackets. Take the wild card you want to use as a literal percentage symbol and surround it with square brackets. You see two grants having a percentage symbol within their names. In this example the square brackets give you the literal percentage symbol. In this figure you see just the two grants that have a % sign in the name.

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_2

Finding literal _ signs with wildcards

You may know that the underscore is also a wildcard. We can use this to find a specific second letter. How many Grants have the letter A for the second letter can be found with the following query:

--Find Grants where A is the 2nd letter.
SELECT *
FROM [GRANT]
WHERE GrantName LIKE '_A%'
GrantIDGrantNameEmpIDAmount
6TALTA_Kishan International318100
10Call Mom @Com5750

In this  example by asking for one character before the letter A and any amount afterward, we names like “TALTA_Kishan International” and “Call Mom @Com”. The % symbol wildcard can represent many characters while the _ symbol wildcard always represents exactly one.

To find the Grants with underscores in the name we do the same technique we used with the % wildcard. Again, we take the wildcard that you want to evaluate and put it in square brackets.

You see three grants having underscores in their names (Figure 2.20). In this example the square brackets tell SQL you are looking for a literal underscore character.

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_3

Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 2:

Q 2.) You want to find all grant names that have an Underscore as the second letter. Which SQL code would you use?

  1. SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘
  2. SELECT * FROM [Grant] WHERE GrantName like ‘[_]_% ‘
  3. SELECT * FROM [Grant] WHERE GrantName like ‘_%[_]%_ ‘
  4. SELECT * FROM [Grant] WHERE GrantName = ‘_[_]% ‘
  5. SELECT * FROM [Grant] WHERE GrantName = ‘[_]_% ‘
  6. SELECT * FROM [Grant] WHERE GrantName = ‘_%[_]%_ ‘

Please post your answer in the comment section to win Joes 2 Pros books.

Rules:

Please leave your answer in the comment section below with correct option, explanation and your country of resident.
Every day one winner will be announced from the United States.
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A valid answer must contain country of residence of answerer.
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The contest is open till next blog post shows up at which is next day GTM+2.5.

Reference:  Pinal Dave (https://blog.sqlauthority.com)

Joes 2 Pros, SQL Scripts, SQL Search, SQL Server
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186 Comments. Leave new

  • Uday Kumar B R
    August 2, 2011 3:53 pm

    Question 2:

    Q 2.) You want to find all grant names that have and Underscore as the second letter. Which SQL code would you use?
    Answer is
    1. SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Because ‘_[_]% ‘ represents

    _ —> Represents first character of the word that may be any character

    [_] —> ‘_’ character in ‘[”]’ square braces represents looking for this
    character the square brace will nullify(ignores) its(special character)
    meaning.

    % —> any number of character after [_]

    Reply
  • if u want display only second letter is ‘_’ then the option 1 is correct
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]%’

    if we want disply second letter as well as any where in the name ‘_’ is exists
    option 3rd is coorect
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_%[_]%_’

    country : India

    Reply
  • Dayanand Singh
    August 2, 2011 4:10 pm

    Correct Answer is Option 1

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Country – INDIA (Gujarat)

    Reply
  • if u want display only second letter is ‘_’ then the option 1 is correct
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]%’

    country : India

    Reply
  • Correct Answe is 3

    Reply
  • The options 1 and 3 are giving same result. But my vote is for Option-3
    Narendra (India)

    Reply
  • Correct answer is option 1 :

    First _ will work as wildcard character and will result all the GrantNames.
    Second _ is in Square Brackets and will result all the GrantNames having _ as Second character.

    Country – India

    Reply
  • my answer is Option 1, i.e SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    I’m from INDIA

    Reply
  • #1 is the correct answer to find all rows with GrantName having an underscore as the second character.

    Jason from USA

    Reply
  • Santosh Maurya
    August 2, 2011 5:32 pm

    Option 1
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘
    is correct.
    country: India

    Reply
  • Correct answer is:

    1.SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Country ==> United States

    Reply
  • Ron A. Farris
    August 2, 2011 5:37 pm

    1. Is the correct answer. The _ wildcard in the first position in the phrase after quotation ask SQL to litterally look for the second letter. The _ in square brackets ask SQL to sort by that symbol.

    Ron A. Farris
    Country – United States of America

    Reply
  • Elena Akhmetova
    August 2, 2011 5:50 pm

    First,
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Country Canada

    Reply
  • The answer is 1.

    SELECT * FROM [Grant] WHERE GrantName LIKE ‘_[_]%’

    Country = USA

    Reply
  • Correct answer :-

    Option 1

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    grant names that have and Underscore as the second letter find by

    ‘_[_]%’ pattern with like .. as second letter is Underscore which is wildcard
    so , put it into [ ] ..

    country: India

    Nice post …

    Reply
  • The correct answer is option 1:

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]%

    Reason: _ being a wildcard character, provides appropriate output required.

    Divya
    US

    Reply
  • Rahul Vijayapuram
    August 2, 2011 6:23 pm

    SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘


    Rahul
    Hyderabad (India)

    Reply
  • Lisa Guiffrida
    August 2, 2011 6:37 pm

    Correct answer is #1 SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘
    Thank you
    Lisa (USA)

    Reply
  • SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘

    Reply
  • Question #1 is correct.
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘


    Timmy
    TX, USA

    Reply

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