Answer simple quiz at the end of the blog post and –
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Finding Apostrophes in string and text
For the last two days we have been using wildcard examples from the Beginning SQL Joes 2 Pros Volume 1 book. Today is our last wildcard example. Please take one more look all the records in the Grant table of the JProCo database. Notice GrantID 004 and 005 have a single quote (apostrophe) in the name. See figure below:
What if you want to find grants that have an apostrophe (single quote) in their names such as Norman’s Outreach? Everything inside single quotes after the LIKE evaluates every record to give you your final result set.
The first single quote starts the string and it ends with the second single quote. Everything between the single quotes is part of the search string. Everything before the first single quote and after the second single quote is not part of the search string. The single quote encompasses or delimits the pattern you are searching. A new challenge arises here. The following query produces a syntax error.
--Bad query results in an error. SELECT * FROM [GRANT] WHERE GrantName LIKE '%'%'
'Msg 105, Level 15, State 1, Line 4
Unclosed quotation mark after the character string ‘
The problem lies in the fact that SQL Server assumes the predicate is done after the second single quote. SQL Server sees everything after that second single quote as an error in your SQL code. Your intentions were lost or misunderstood. To forego the special meaning of the single quote, precede it with another single quote. The code and results are seen in the figure below.
Using two single quotes filters your result set for a grant name with an apostrophe. You now have two records with a single quote in your result set. To view all names without a single quote you would simply change the LIKE to NOT LIKE in the WHERE clause.
--Find GrantNames without a single quote SELECT * FROM [GRANT] WHERE GrantName NOT LIKE '%''%'
Note: If you want to setup the sample JProCo database on your system you can watch this video.
Question 3:
Q 3:You want to find all first names that have an apostrophe anywhere in the name. Which SQL code would you use?
- SELECT * FROM Employee
WHERE Firstname like ‘_’% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘_”% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘_[‘]% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%’% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%[‘]% ‘
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Reference: Pinal Dave (https://blog.sqlauthority.com)
191 Comments. Leave new
The correct answer is option 5
5.SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
The correct answer is option 5
5.SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Hemant (India)
Answer: Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%’
the correct answer is
Option 5:
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Country – India
Q 3) SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Finding Apostrophes in String and Text – Day 3 of 35
When pattern matching the _ forces on letter and the % can be any number of letters (include zero letters). Since a name could start with an apostrophe we would not find just those with the underscore first so (1), (2), and (3) are all wrong. Both (4) and (6) would be delimited by the special meaning of the second apostrophe. The use of LIKE ‘%”% ‘ will treat not use the special meaning and have a % on either side so (5) is correct.
Winner from USA: Cameron
Winner from India: Madhivanan
I thank you all for participating here. The permanent record of this update is posted on facebook page.
SELECT *
FROM Employee
WHERE Firstname like ‘%[”]%’
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
The answer is #5:
SELECT * FROM Employee WHERE Firstname like ‘%”% ‘
Francisco
Miami
Correct answer is :
SELECT * FROM Employee WHERE Firstname like ‘%”%’
Correct answer is option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%
My Country is Canada
The correct choice is 5
From Canada
Correct Answer is 5.
Kapil Dev Tripathi
(Noida, India)
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Option 5
I am from India
Answer is #5
SELECT * FROM Employee
WHERE Firstname like ‘%”%
Thanks,
Wayne
answer is # 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%
i’m atul singh
and i am from india(mumbai)
Answer: Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Anjana(India)
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Option 5 is correct
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Correct Answer is 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%
Correct Answer is 5
SELECT * FROM Employee WHERE Firstname like ‘%”%
Explanation: Using two single quotes filters result set with an apostrophe
India