Answer simple quiz at the end of the blog post and –
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Finding Apostrophes in string and text
For the last two days we have been using wildcard examples from the Beginning SQL Joes 2 Pros Volume 1 book. Today is our last wildcard example. Please take one more look all the records in the Grant table of the JProCo database. Notice GrantID 004 and 005 have a single quote (apostrophe) in the name. See figure below:
What if you want to find grants that have an apostrophe (single quote) in their names such as Norman’s Outreach? Everything inside single quotes after the LIKE evaluates every record to give you your final result set.
The first single quote starts the string and it ends with the second single quote. Everything between the single quotes is part of the search string. Everything before the first single quote and after the second single quote is not part of the search string. The single quote encompasses or delimits the pattern you are searching. A new challenge arises here. The following query produces a syntax error.
--Bad query results in an error. SELECT * FROM [GRANT] WHERE GrantName LIKE '%'%'
'Msg 105, Level 15, State 1, Line 4
Unclosed quotation mark after the character string ‘
The problem lies in the fact that SQL Server assumes the predicate is done after the second single quote. SQL Server sees everything after that second single quote as an error in your SQL code. Your intentions were lost or misunderstood. To forego the special meaning of the single quote, precede it with another single quote. The code and results are seen in the figure below.
Using two single quotes filters your result set for a grant name with an apostrophe. You now have two records with a single quote in your result set. To view all names without a single quote you would simply change the LIKE to NOT LIKE in the WHERE clause.
--Find GrantNames without a single quote SELECT * FROM [GRANT] WHERE GrantName NOT LIKE '%''%'
Note: If you want to setup the sample JProCo database on your system you can watch this video.
Question 3:
Q 3:You want to find all first names that have an apostrophe anywhere in the name. Which SQL code would you use?
- SELECT * FROM Employee
WHERE Firstname like ‘_’% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘_”% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘_[‘]% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%’% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘ - SELECT * FROM Employee
WHERE Firstname like ‘%[‘]% ‘
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Reference: Pinal Dave (https://blog.sqlauthority.com)
191 Comments. Leave new
Should be –> SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Vaibhav Mathur
India
Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%‘
Hi Pinal Sir,
The correct answer for the above question is Option No. 5.
SELECT * FROM Employee WHERE Firstname like ‘%”%‘
Explanation
We need to find Persons name that have an apostrophe anywhere in the name ,so it can be anywhere from starting till the end anywhere.
1) In above option LIke operator suggests that we have some criteria and what all satisfy will be selected.
2) % operator : it can be 0 to many characters from start till end.
3) ” two single quotes tells the sql server that we need at least one apostrophe in the name.
4) % operator : it can be 0 to many characters from start till end.
NOTE 1) Make Sure that there is no space anywhere in the searching formula otherwise sql will look for apostrophe and space specified before/ after as specified then the answer or the result set will be surprising.
The remaining options are in correct because:
Option 1: SELECT * FROM Employee WHERE Firstname like ‘_’% ‘
Unclosed quotation mark after the character string,Incorrect syntax near ‘ .
Option 2: SELECT * FROM Employee WHERE Firstname like ‘_”% ‘
Underscore is used instead of %, No results are returned wrong Query.
Option 3: SELECT * FROM Employee WHERE Firstname like ‘_[‘]% ‘
Incorrect syntax near ‘]’, Incorrect pattern we are searching the apostrophe anywhere in the string not only from second and also syntax error.
Option 4: SELECT * FROM Employee WHERE Firstname like ‘%’% ‘
Unclosed quotation mark after the character string, error raised Wrong Option.
Option 6: SELECT * FROM Employee WHERE Firstname like ‘%[‘]% ‘
Incorrect syntax near ‘]’, Query not formed properly.
Hope to see more challenging one in next post, this is a good initiative taken by Pinal sir where in all are learning something new and useful I am happy that I am a part of this.
Dilip Kumar Jena – INDIA
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
kkmishra (jss academy of technical education noida)
India
Correct answer is option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%
Manoj ,New Delhi
Answer: Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”%‘
SQL Server sees everything after that second single quote as an error in SQL code. To forego the special meaning of the single quote, precede it with another single quote.
USA
SELECT * FROM EMPLOYEE
WHERE Firstname like ‘%”%’
The correct answer is option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Nikhil from Tampa, FL, USA
answer i s option 5
Good Post,
sandhya
Boston,usa
The correct answer is #5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
I’m from USA
Answer 5: SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Residence: USA
Correct Answer: 5.
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Redmond, WA [USA]
Number 5 would be the correct answer.
Jason
USA
5.SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Yup, Number 5, I’ve had to do that enough with Dynamic SQL. Texas, USA.
Correct Answer is : Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Thanks,
Dhruval Shah, Ahmadabad, India.
Answer : Option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Thanks
Riyas.V.K
Option 5 Is correct
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Correct Answer is Option 5:
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
India
Correct answer is option 5
SELECT * FROM Employee
WHERE Firstname like ‘%”% ‘
Thanks
Rupesh Tiwary(India)