SQL SERVER – Tips from the SQL Development Series – Wildcard – Querying Special Characters – Day 2 of 35

In this blog post we will learn various tips related to Querying Special Characters with the help of wildcard in SQL Server.

Querying Special Characters

Some special characters can be tricky to pattern match since they themselves can represent different values at different times. Let’s look at some examples. Here is a quick look at all the records in the [Grant] table of the JProCo database. Note: Since [Grant] is also a keyword it must be enclosed in square brackets or double quotes to designate it as the [Grant] table and now the keyword. Take a look at many of the names in the Grant Name field and notice we have many names with special symbols in them. See figure below:

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_1

Finding literal % signs with wildcards

We learned about special characters in yesterdays post called wildcards. When using the percentage sign % or the underscore _ we can do relative searches. We have a grant called “92 Purr_Scents %% team” which has a percentage symbol in the name. We have other grants with percentages in their names. How do you search for a percentage sign with two wildcards on either side? It would appear to SQL that you’re looking for three wildcards as seen in the query below:

--Bad query pattern logic (finds all Grant records)
SELECT *
FROM [GRANT]
WHERE GrantName LIKE '%%%'

We have three special characters and no literal percent symbol. Help is on the way again with the square brackets. Take the wild card you want to use as a literal percentage symbol and surround it with square brackets. You see two grants having a percentage symbol within their names. In this example the square brackets give you the literal percentage symbol. In this figure you see just the two grants that have a % sign in the name.

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_2

Finding literal _ signs with wildcards

You may know that the underscore is also a wildcard. We can use this to find a specific second letter. How many Grants have the letter A for the second letter can be found with the following query:

--Find Grants where A is the 2nd letter.
SELECT *
FROM [GRANT]
WHERE GrantName LIKE '_A%'
GrantIDGrantNameEmpIDAmount
6TALTA_Kishan International318100
10Call Mom @Com5750

In this  example by asking for one character before the letter A and any amount afterward, we names like “TALTA_Kishan International” and “Call Mom @Com”. The % symbol wildcard can represent many characters while the _ symbol wildcard always represents exactly one.

To find the Grants with underscores in the name we do the same technique we used with the % wildcard. Again, we take the wildcard that you want to evaluate and put it in square brackets.

You see three grants having underscores in their names (Figure 2.20). In this example the square brackets tell SQL you are looking for a literal underscore character.

SQL SERVER - Tips from the SQL Development Series - Wildcard - Querying Special Characters - Day 2 of 35 j2p_2_3

Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 2:

Q 2.) You want to find all grant names that have an Underscore as the second letter. Which SQL code would you use?

  1. SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘
  2. SELECT * FROM [Grant] WHERE GrantName like ‘[_]_% ‘
  3. SELECT * FROM [Grant] WHERE GrantName like ‘_%[_]%_ ‘
  4. SELECT * FROM [Grant] WHERE GrantName = ‘_[_]% ‘
  5. SELECT * FROM [Grant] WHERE GrantName = ‘[_]_% ‘
  6. SELECT * FROM [Grant] WHERE GrantName = ‘_%[_]%_ ‘

Please post your answer in the comment section to win Joes 2 Pros books.

Rules:

Please leave your answer in the comment section below with correct option, explanation and your country of resident.
Every day one winner will be announced from the United States.
Every day one winner will be announced from India.
A valid answer must contain country of residence of answerer.
Please check my Facebook page for winners name and correct answer.
Winner will get Joes 2 Pros Volume 1.
The contest is open till next blog post shows up at which is next day GTM+2.5.

Reference:  Pinal Dave (https://blog.sqlauthority.com)

Joes 2 Pros, SQL Scripts, SQL Search, SQL Server
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186 Comments. Leave new

  • Number 1 is the closest, but there is an empty space char at the end of each of the string literals, so that would cause ALL to be invalid.
    Here is the correct version:
    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]%‘
    USA

    Reply
  • Vaibhav Mathur
    August 4, 2011 12:15 am

    Correct one is —> SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Vaibhav Mathur
    India

    Reply
  • The correct answer is #1 – all other answers are obviously incorrect.
    I’m from USA

    Reply
  • Gerardo Melendrez (@payini)
    August 4, 2011 8:10 am

    Answer: 1. SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘
    Residence: USA

    Reply
  • Saurabh Sontakke
    August 4, 2011 9:04 am

    1.SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Reply
  • Option 1. Regexp for the win, even if SQL Server’s is a bit half-assed. Texas, USA. Whee!

    Reply
  • Answer: Option #1
    Explanation: The first underscore ‘_’ is treated as a single character wildcard. The second underscore in square brackets [_] is treated as a literal character to search for. Option #4 is not correct because it uses an ‘=’ instead of LIKE.
    Country: USA

    Reply
  • Dhruval Vikram Shah
    August 4, 2011 10:39 am

    Correnct Answer is : Option 1

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Thanks
    Dhruval Shah, Ahmedabad, India.

    Reply
  • Answer :Option1

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Thanks
    Riyas.V.K

    Reply
  • Vanthiya Thevan. N
    August 4, 2011 11:12 am

    Correct Answer is Option 1:

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    India

    Reply
  • Correct answer is Option 1

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]%

    Reply
  • Correct answer is

    Option 1: SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    Thanks
    Rupesh Tiwary(India)

    Reply
  • Chirag Satasiya
    August 4, 2011 4:09 pm

    Thank you pinal sir,

    Really Glad about results.
    Thank you very much.

    Reply
  • Hi dave,

    Correct answer is option 1 :

    SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘

    because the first underscore is acts as a wildcard character which signifies a single character and matches Underscore as the second letter

    From
    India

    Chitti :-)

    Reply
  • Dear Pinal sir,
    Answer is SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘

    Reply
  • Answer #1

    1. SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘

    Jason from the USA

    Reply
  • Correct answer is option 1 :

    SELECT * FROM [Grant] WHERE GrantName like ‘_[_]% ‘

    Reason: underscore is a wildcard character which signifies a single character and matches Underscore as the second letter

    Country – India

    Reply
  • The correct answer is #1.

    SELECT * FROM [Grant]
    WHERE GrantName like ‘_[_]% ‘

    As we are required to search “_” as second character, specifying and “_” before and second “_” in brackets with wild card will give you all the GrantName that has second character as “_”.

    Syed from USA.

    Reply
  • option 1 is the answer

    USA RA

    Reply
  • # 1 is the answer.

    Reply

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