SQL SERVER – Size of Index Table for Each Index – Solution

Earlier I have posted small question on this blog and requested help from readers to participate here and provide solution. Please read the original Puzzle here.

SQL SERVER – Size of Index Table – A Puzzle to Find Index Size for Each Index on Table

The puzzle was to write a query that will return the size for each index that is on any particular table. We need a query that will return an additional column in the above listed query and it should contain the size of the index.

So far I have found two potential solutions. I have done some good amount of testing of both the script and they both are really giving accurate results 99.9% of the time. There were couple of instances where it provided incorrect results but for the most of the time, it just worked like charm. Again, it may be a bit of rounding up logic and I will not hold it against the script.

I want to thank Gaurav Sharama and Adam Hutson for their participation.

Solution from Gaurav Sharma

DECLARE @OBJECT_NAME VARCHAR(255) = 'HumanResources.Shift';
DECLARE @temp TABLE
(
indexID  BIGINT,
objectId  BIGINT,
index_name NVARCHAR(MAX),
used_page_count  BIGINT,
pages  BIGINT
)
--Insert into temp table
INSERT INTO @temp
SELECT
P.index_id,
P.OBJECT_ID ,
I.name,
SUM (used_page_count),
SUM (
CASE
WHEN (p.index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END
)
FROM sys.dm_db_partition_stats P INNER JOIN sys.indexes I ON I.index_id = P.index_id AND I.OBJECT_ID = P.OBJECT_ID
WHERE p.OBJECT_ID = OBJECT_ID(@OBJECT_NAME)
GROUP BY P.index_id, I.Name, P.OBJECT_ID;
SELECT index_name INDEX_NAME,
LTRIM (STR ((CASE WHEN used_page_count > pages THEN (used_page_count - pages) ELSE 0 END) * 8, 15, 0) + ' KB') INDEX_SIZE
FROM @temp T
GO

Solution from Adam Hutson

DECLARE
@objname NVARCHAR(776),
@id INT,
@dbname sysname
SELECT
@objname = 'HumanResources.Shift',
@dbname = ISNULL(PARSENAME(@objname, 3),DB_NAME()),
@id = OBJECT_ID(@objname)
SELECT
i.*,
CASE
WHEN ps.usedpages > ps.pages THEN (ps.usedpages - ps.pages)
ELSE 0
END * 8 indexsize
FROM sys.indexes i
INNER JOIN (
SELECT
OBJECT_ID,
index_id,
SUM (used_page_count) usedpages,
SUM (
CASE
WHEN (index_id < 2) THEN (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
ELSE lob_used_page_count + row_overflow_used_page_count
END
)pages
FROM sys.dm_db_partition_stats
WHERE OBJECT_ID = @id
GROUP BY OBJECT_ID, index_id
) ps ON i.index_id = ps.index_id
WHERE i.OBJECT_ID = @id
GO

If you have different script or have suggestions on this script, please let us know.

Reference: Pinal Dave (https://blog.sqlauthority.com)