# SQL SERVER – T-SQL Script for FizzBuzz Logic

Following is quite common Interview Question asked in many interview questions. FizzBuzz is popular but very simple puzzle and have been very popular to solve. FizzBuzz problem can be attempted in any programming language. Let us attempt it in T-SQL.

Definition of FizzBuzz Puzzle : Write a program that prints the numbers from 1 to 100. But for multiples of three print “Fizz” instead of the number and for the multiples of five print “Buzz”. For numbers which are multiples of both three and five print “FizzBuzz”.

`DECLARE @counter INT DECLARE @output VARCHAR(8) SET @counter = 1 WHILE @counter < 101 BEGIN SET @output = '' IF @counter % 3 = 0 SET @output = 'Fizz' IF @counter % 5 = 0 SET @output = @output + 'Buzz' IF @output = '' SET @output = @counter PRINT @output SET @counter = @counter + 1 END`

Reference : Pinal Dave (https://blog.sqlauthority.com)

## SQL SERVER – Check Database Integrity for All Databases of Server – DBCC CHECKDB

#### 17 Comments.Leave new

• I would take a set-based approach:

CREATE TABLE ##nums
(
number int IDENTITY(1,1),
nothing int null
)

INSERT ##nums (nothing)
SELECT TOP(100) OBJECT_ID FROM sys.all_columns

SELECT ‘FizzBuzz’ =
CASE
WHEN ((number % 3 = 0) AND (number % 5 = 0)) THEN ‘FizzBuzz’
WHEN (number % 5 = 0) THEN ‘Buzz’
WHEN (number % 3 = 0) THEN ‘Fizz’
ELSE CAST(number AS CHAR(3))
END
FROM ##nums

• Zod,

Good Script. Let us see what else we get from other exports.

Kind Regards,
Pinal

• Following code maybe a little bit dummy but seems more readable?

DECLARE @counter varchar(5)
SET @counter = 1
WHILE @counter < 101
BEGIN

print case
when @counter%3=0 and @counter %5 !=0 then ‘Fizz’
when @counter %3 !=0 and @counter%5=0 then ‘Buzz’
when @counter%3=0 and @counter%5=0 then ‘FizzBuzz’
else @counter end

SET @counter = @counter + 1

END

• since we gonna do it in sql server, i suppose the result would be better to display in table:

WITH CTE (Col1)
AS
(
SELECT 1 AS Col1
UNION ALL
SELECT Col1 + 1 FROM CTE
WHERE Col1 < 100
)
SELECT
CASE
WHEN Col1%3 = 0 AND Col1%5 = 0 THEN ‘FizzBuzz’
WHEN Col1%3 = 0 THEN ‘Fizz’
WHEN COl1%5 = 0 THEN ‘Buzz’
ELSE CONVERT(VARCHAR(3), Col1)
END
FROM CTE

• declare @v1 varchar(100)
declare @v2 varchar(100)
select @v1=0
while (@v1<100)
begin
select @v1=@v1+1
–select @v2=((@v1%3)=0 and (@v1%5)=0)
if ((@v1%3=0) and (@v1%5=0))
print ‘fizzbuzz’
if(@v1%3)=0
print ‘fizz’
else
if(@v1%5)=0
print ‘buzz’
else
print @v1
end

• Declare @num as int
set @num = 1
while @num <= 100
Begin
if(@num%15=0)
print ‘FizzBuzz’
else if(@num%5=0)
print ‘Buzz’
else if(@num%3=0)
print ‘Fizz’
else
print @num
set @num=@num+1;
end

• Here’s another qay, very similar to howyue:

WITH
Number
AS
(
SELECT 1 A UNION ALL
SELECT A + 1 FROM Number WHERE A 0 AND A%5 > 0 THEN CAST(A AS VARCHAR) ELSE ” END
FROM
Number;

• Pinal, thanx.

The query did not seem to come through well. Here it is again:

WITH
Number
AS
(
SELECT 1 A UNION ALL
SELECT A + 1 FROM Number WHERE A 0 AND A%5 > 0 THEN CAST(A AS VARCHAR) ELSE ” END
FROM
Number;

• I’m not sure if you have any time limit on these posts….

WITH cte (x, y, z) AS
(
SELECT 0 x,
‘ ‘ y,
‘ ‘ z
UNION ALL
SELECT x+1,
CASE WHEN ((x+1)%3 = 0) THEN ‘Fizz’ ELSE NULL END,
CASE WHEN ((x+1)%5 = 0) THEN ‘Buzz’ ELSE NULL END
FROM cte WHERE x 0

• Atin Srivastava
August 5, 2009 1:05 pm

Little complicated but again thats also a way

declare @st int
declare @en int

set @st=1
set @en=100
while @st<@en
Begin
if (@st%3=0) AND (@st%5=0 )
begin
Print 'FIZZBUZZ'
end
else
begin
if @st%3=0
begin
PRint 'FIZZ'
end
else
Begin
if @st%5=0
begin
Print 'BUZZ'
end
Else
begin
Print @st
end
End
end
set @st=@st+1
end

• with FIZZBUZZ(a ,b)
AS
(
select 1 a,cast(1 as nvarchar(10))b
union all
select a+1 ,
(case when ((a+1)%3)=0 and ((a+1)%5)=0 then ‘FIZZBUZZ’
when ((a+1)%3)=0 then ‘FIZZ’
when ((a+1)%5)=0 then ‘BUZZ’
else cast(a+1 as nvarchar(10))end) as b from FIZZBUZZ
where a<100
)
select * from FIZZBUZZ

• Another method

select
case when number%15=0 then ‘FrizzBuzz’
when number%3=0 then ‘Friz’ when number%5=0 then ‘Buzz’
else cast( number as varchar(10)) end
from master..spt_values
where type=’p’ and number>0

• declare @intCount integer =1
, @Buzz varchar(15) = ”
WHILE @intCount <101

BEGIN
SELECT @Buzz = CASE WHEN (@intCount % 3 = 0 AND @intCount % 5 = 0) THEN 'FizzBuzz'
WHEN @intCount % 5 = 0 then 'Buzz'
WHEN @intCount % 3 = 0 THEN 'Fizz'
ELSE convert(varchar(4),@intCount) END

PRINT @Buzz
SET @intCount=@intCount +1

END

• A pure SQL solution without a need for loops, etc, which is also pretty portable between different flavours of SQL.

SELECT
CASE
WHEN (a.i + b.i * 10 + 1)% 3 = 0 AND (a.i + b.i * 10 + 1)% 5 = 0 THEN ‘Fizz Buzz’
WHEN (a.i + b.i * 10 + 1)% 3 = 0 THEN ‘Fizz’
WHEN (a.i + b.i * 10 + 1)% 5 = 0 THEN ‘Buzz’
ELSE CONVERT(varchar, (a.i + b.i * 10 + 1 ))
END AS FizzBuzz
FROM (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) a,
(SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) b
ORDER BY a.i + b.i * 10 + 1

• DECLARE @i INT
SET @i =1
WHILE @i <= 100
BEGIN

IF ((@i%3 = 0) and (@i%5 = 0))
BEGIN
PRINT 'fizz buzz'
END
ELSE IF(@i%3 = 0)
BEGIN
PRINT 'fizz'
END
ELSE IF (@i%5 = 0)
BEGIN
PRINT 'buzz'
END
ELSE
BEGIN
PRINT @i
END
SET @i = @i +1
END

• This was my solution. Surprised I’ve never heard of this until today.

DECLARE @Counter INT
SET @Counter = 1

WHILE @Counter <= 100
BEGIN
SELECT
@Counter,
CASE
WHEN @Counter % 3 = 0 AND @Counter % 5 = 0 THEN 'FizzBuzz'
WHEN @Counter % 3 = 0 THEN 'Fizz'
WHEN @Counter % 5 = 0 THEN 'Buzz'
ELSE CAST(@Counter AS CHAR(3)) END AS 'Out'
SET @Counter = @Counter + 1
END