SQL SERVER – Find Monday of the Current Week

Very Simple Script which find Monday of the Current Week

SELECT
DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0) MondayOfCurrentWeek

Reference : Pinal Dave (https://blog.sqlauthority.com)

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48 Comments. Leave new

  • Your articles are very helpful. Thanks for the public service.

    Reply
  • Your solutions are extremely useful. Thanks a ton brother

    Reply
  • Dear Pinal Dev…

    I have never found a simpler scripts in date functions any where in the world … Hats offf….

    Reply
  • Dan Richardson
    May 8, 2009 8:40 pm

    simple, to-the-point answers – perfect every time.
    Thanks a bunch! :)

    Reply
  • Awesome! Perfect solution as always! Many thanks…..

    Reply
  • This does not work. Here is an example:

    DECLARE @TODAY DATETIME
    SET @TODAY = ‘June 14, 2009’

    SELECT

    @TODAY AS TODAY,
    LAST_MONDAY = DATEADD(wk, DATEDIFF(wk,0,@TODAY), 0)

    :-)

    Reply
    • Last Monday (eg Monday of this week if it is after Monday or Monday of last week if it is Sunday)

      DATEDIFF(day, 0, CAST(@TODAY as DATETIME) – DATEDIFF(day, 0, @TODAY) %7)

      Reply
      • try this,

        declare @date datetime = ‘2015-01-8’
        select datediff(week, dateadd(week, datediff(week, 0, dateadd(month, datediff(month, 0, @date), 0)), 0), @date – 1) + 1 as ‘Current Week of this month’
        ,
        @date AS TODAY,
        LAST_MONDAY = DATEADD(wk, DATEDIFF(d, 0, @date) / 7, 0),
        [LAST_MONDAY’s SUNDAY] = DATEADD(wk, DATEDIFF(d, 0, @date) / 7, 6)

  • I believe that is because Sunday is classed as the first day of the week.

    Therefore when the date is a Sunday, the Monday of the current week is tomorow.

    :)

    Reply
  • How to find Monday of last week?

    Reply
  • @cimnil

    Find Monday of this week , and use DATEADD to subtract 7 days.

    Reply
  • Perfect job. Thanks

    Reply
    • “I believe that is because Sunday is classed as the first day of the week.”

      If I set Monday to be the first day of the week it still doesn’t work.

      SET DATEFIRST 1;
      DECLARE @TODAY DATETIME ;
      SET @TODAY = ‘June 14, 2009’ ;
      SELECT
      @TODAY AS TODAY,
      LAST_MONDAY = DATEADD(wk, DATEDIFF(wk,0,@TODAY), 0)

      returns:

      TODAY LAST_MONDAY
      2009-06-14 00:00:00.000 2009-06-15 00:00:00.000

      Reply
  • Try this:
    DATEADD(wk, DATEDIFF(d, 0, GETDATE()) / 7, 0).

    This works because 1/1/1900 (i.e. ‘0’) was a Monday so you are basically dividing the days since then by 7 days exactly.

    FYI – you can also find the day of the week based on a Monday start date (i.e. Monday = 0, Tuesday = 1, etc.) by using “% 7” instead of “/ 7”.

    Reply
  • The statement RETURN (DATEADD(wk, DATEDIFF(wk, 0,@CURRENTDATE),0))
    doesn’t return the date of last monday.

    I get the value for ,@CURRENTDATE = 11 03 2010, and the whole thing return 08 mar 2010, which is THIS monday, not the last one.

    what if I want to run a script in any time and the result must return the date of last monday, last tuesday til last friday.

    Any way to do it?

    Reply
  • The statement RETURN (DATEADD(wk, DATEDIFF(wk, 0,@CURRENTDATE),0))
    doesn’t return the date of last monday.

    I get the value for ,@CURRENTDATE = 11 03 2010, and the whole thing return 08 mar 2010, which is THIS monday, not the last one.

    Any query can give me the date of last monday til last friday, this mean I need 5 days no matter what day I run the script.

    Reply
  • Pinal Dave – Thanks SO much – I have seen your posts before but this one gave me exactly what I wanted. and so simple… a summary for the week beginning on monday was MUCH simpler with this small bit of code! you are the BEST!

    Reply
  • nice piece of script. simple yet effective!

    Reply
  • I tried to find Wednesday of the current week on the same lines, but was not successful. Can you pl. help.
    For any given date, I need the Wednesday of that week.

    Thanks in advance,
    GS

    Reply
  • Hi There,

    Dave’s tit bit is perfect for defalut date caliculations. i.e. by defauls Sunday is considerded as first day of week in US.

    if you want to consider monday as first day of the week you may use the below tit bit.

    SET DATEFIRST 1
    select (DateAdd(d, – (DatePart(dw,’2011-08-21′) -1), ‘2011-08-21’))

    Reply
  • Since you helped me out here, I’ll pass along what it was exactly you helped me with. This query builds a result set that lists all the weeks in the past year for a view or function:

    WITH CTE_PastYearinWeeks
    AS (
    select
    /* Thanks to SQL Authority for below. It gets the number of weeks between now and the beginning of (sql) time and adds it to the beginning of (sql) time, thus setting it to the first day of the week! */
    DATEADD(wk, DATEDIFF(wk,0,GETDATE()-365), 0) as DateStart
    UNION ALL
    SELECT DATEADD(WK,1,DateStart)
    FROM CTE_PastYearinWeeks
    WHERE DATEADD(WK,1,DateStart) <= GETDATE()
    –and DATEPART(YYYY,DateStart) <= DATEPART(YYYY,GETDATE())
    )
    select DATEPART(YYYY,DateStart) as YearNum
    , DATEPART(WK,DateStart) as WeekNum
    , SUBSTRING(CONVERT(varchar, DateStart, 107),1,6) + ' – ' + CONVERT(varchar, DATEADD(DD,6,DateStart), 107) as WeekTitle
    from CTE_PastYearinWeeks
    OPTION (MAXRECURSION 0);

    Reply
  • how to find next week your birthday alert using sql

    Reply
  • You ROCK !!!!!! A Big Thumbs Up

    Reply

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