SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Finding Apostrophes in String and Text – Day 3 of 35

Answer simple quiz at the end of the blog post and –
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Every day one winner from United States will get Joes 2 Pros Volume 1.

Finding Apostrophes in string and text

For the last two days we have been using wildcard examples from the Beginning SQL Joes 2 Pros Volume 1 book. Today is our last wildcard example. Please take one more look all the records in the Grant table of the JProCo database. Notice GrantID 004 and 005 have a single quote (apostrophe) in the name. See figure below:

SQL SERVER - Tips from the SQL Joes 2 Pros Development Series - Finding Apostrophes in String and Text - Day 3 of 35 j2p_3_1

What if you want to find grants that have an apostrophe (single quote) in their names such as Norman’s Outreach? Everything inside single quotes after the LIKE evaluates every record to give you your final result set.

The first single quote starts the string and it ends with the second single quote. Everything between the single quotes is part of the search string. Everything before the first single quote and after the second single quote is not part of the search string. The single quote encompasses or delimits the pattern you are searching. A new challenge arises here. The following query produces a syntax error.

--Bad query results in an error.
SELECT *
FROM [GRANT]
WHERE GrantName LIKE '%'%'

'Msg 105, Level 15, State 1, Line 4
Unclosed quotation mark after the character string ‘

The problem lies in the fact that SQL Server assumes the predicate is done after the second single quote. SQL Server sees everything after that second single quote as an error in your SQL code. Your intentions were lost or misunderstood. To forego the special meaning of the single quote, precede it with another single quote. The code and results are seen in the figure below.

SQL SERVER - Tips from the SQL Joes 2 Pros Development Series - Finding Apostrophes in String and Text - Day 3 of 35 j2p_3_2

Using two single quotes filters your result set for a grant name with an apostrophe. You now have two records with a single quote in your result set. To view all names without a single quote you would simply change the LIKE to NOT LIKE in the WHERE clause.

--Find GrantNames without a single quote
SELECT *
FROM [GRANT]
WHERE GrantName NOT LIKE '%''%'


Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 3:

Q 3:You want to find all first names that have an apostrophe anywhere in the name. Which SQL code would you use?

  1. SELECT * FROM Employee
    WHERE Firstname like ‘_’% ‘
  2. SELECT * FROM Employee
    WHERE Firstname like ‘_”% ‘
  3. SELECT * FROM Employee
    WHERE Firstname like ‘_[‘]% ‘
  4. SELECT * FROM Employee
    WHERE Firstname like ‘%’% ‘
  5. SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘
  6. SELECT * FROM Employee
    WHERE Firstname like ‘%[‘]% ‘

Please post your answer in comment section to win Joes 2 Pros books.

Rules:

Please leave your answer in comment section below with correct option, explanation and your country of resident.
Every day one winner will be announced from United States.
Every day one winner will be announced from India.
A valid answer must contain country of residence of answerer.
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Reference:  Pinal Dave (https://blog.sqlauthority.com)

Joes 2 Pros, SQL Scripts, SQL Server
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SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Efficient Query Writing Strategy – Day 4 of 35

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191 Comments. Leave new

  • Vijayakumar .P
    August 3, 2011 3:12 pm

    This correct option is 5

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Thanks
    Vijayakumar .P [Kochi] India

    Reply
  • Polly Pran Bora
    August 3, 2011 3:16 pm

    From India:

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘
    Option 5 is answer.

    Reply
  • The answer will 5th. ie.,

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    From India

    Reply
  • Correct Answer is – 5

    You will get no record if you run 2. Also you will get the syntax error for the rest because quote are not in the right usage.

    Country – UK

    Reply
  • Correct answer is
    5. SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Reply
  • Bhargav Mistry
    August 3, 2011 3:43 pm

    To find all the names having an apostophe will require two ” for sql server to understand and making two % signs on both side will result all the names having an apostrophe in any position..

    Hence, answer 5 is correct.

    Bhargav Mistri, INDIA

    Reply
  • Hiren Bavishi
    August 3, 2011 3:52 pm

    Correct Answer is option 5

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Hiren Bavishi
    India

    Reply
  • Correct answer is 5.

    Reply
  • None of the above is correct:
    Many of them have replied as option 5 but what i see is , it is a double quote(“) not a single quote.

    The correct answer is : SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    The reason for this is :
    Two single quotes in a row signify an escape sequence from the normal interpretation of the single quote character. When two single quotes appear together, they are interpreted by SQL as one literal single quote.

    Santosh.s
    Bangalore – India

    Reply
  • Correct Answer is Option 5 :
    SELECT * FROM Employee WHERE Firstname like ‘%”% ‘

    Ahmedabad, INDIA

    Reply
  • oops!!! I am sorry.. i mistaked it to double quotes.

    option 5 is correct.
    The reason for this is :
    Two single quotes in a row signify an escape sequence from the normal interpretation of the single quote character. When two single quotes appear together, they are interpreted by SQL as one literal single quote.

    Santosh.s
    Bangalore – India

    Reply
  • The answer is option 5 :

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘
    we need to use single quote twice if we want to use as a filter

    Reply
  • Again the answer is 5

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Reply
  • jagdish prajapati
    August 3, 2011 4:30 pm

    Hi,
    option -5 is correct

    Reply
  • Correct answer is
    5. SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Country : India

    Madhivanan

    Reply
  • Correct Answer is Option 5 :
    SELECT * FROM Employee WHERE Firstname like ‘%”% ‘

    Reply
  • The Correct option is 6. SELECT * FROM Employee
    WHERE Firstname like ‘%[‘]% ‘
    Because since apostrophe is a reserve key letter in SQL you would have to use escape character [‘] to let SQL recognize it as literal and since it could be anywhere in the firstname then the correct option is 6.

    [I am from Nigeria.]

    Reply
  • Answer is option 5
    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Country: India

    Reply
  • shilpa sharma
    August 3, 2011 5:04 pm

    Correct answer is option 5.

    SELECT * FROM Employee
    WHERE Firstname like ‘%”% ‘

    Country : India

    Shilpa Sharma

    Reply
  • Ritesh B choksi
    August 3, 2011 5:08 pm

    Answer is option 5
    Ritesh
    vadodara India

    Reply

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