SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Wildcard Basics Recap – Day 1 of 35

Answer simple quiz at the end of the blog post and –
Every day one winner from India will get Joes 2 Pros Volume 1.
Every day one winner from United States will get Joes 2 Pros Volume 1.

Wildcard ranges

If you have ever been to a convention where they have a morning registration desk that must handle thousands of people in a short time you know they must put some pre-planning thought into how to handle this burst of volume. In fact often they will have many registration desks running in parallel to make things run faster. The first registration desk might handle all customer last names starting from A to K. Desk 2 will handle names from L to Q and the third desk will handle from R to Z.

With my last name being Morelan I would naturally head to registration desk #2 knowing that desk has the list with my name on it and the other desks don’t. Now let’s say you are in charge of creating these three separate lists and sending them out to the right registration workers. You know how to sort but how can you separate this lists using wildcards?

Wildcard Basics Recap

Lets start off with something most of us know already. Most SQL folks understand the usefulness and power of the basic uses of wildcards. Using wildcards allows you to do pattern matches in a column. In this case our criteria does not want to use the = sign to find a pattern match. The operator that allows you to do approximate predicates is LIKE. The LIKE operator allows you to do special relative searches to filter your result set.

--Find all LastNames that start with the letter A
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'

To find everyone whose last name starts with the letter B, you need “B” to be the first letter. After the letter B you can have any number of characters. Using B% in single quotes after the LIKE operator gets all last names starting with the letter B.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'B%'

Wildcard ranges or set specifiers

If you want to find all LastName values starting with the letters A or B you can use two predicates in your WHERE clause. You need to separate them with the OR operator.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'

Finding names beginning with A or B is easy. How about the registration desk example where want the names ranging from A-K? This works well until you want a range of A-K as in the example below:

--Find all LastNames ranging from A-K
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'
OR LastName LIKE 'C%'
OR LastName LIKE 'D%'
OR LastName LIKE 'E%'
OR LastName LIKE 'F%'
OR LastName LIKE 'G%'
OR LastName LIKE 'H%'
OR LastName LIKE 'I%'
OR LastName LIKE 'J%'
OR LastName LIKE 'K%'

The previous query does find LastName values starting from A-K. However, if you need a range of letters, the LIKE operator has many better options. We only really care about the first letter of the last name and there a several first letters that fit with what were looking for. The first letter of the last name can be A,B,C,D,E,F,G,H,I,J or K. Simply list all the choices you want for the first letter inside a set of square brackets.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[ABCDEFGHIJK]%'

Square brackets with wildcards enclose ranges or sets for 1 position. In this case the first position is a set of 11 different possible letters. This is not a series of letter but a multiple choice of letters. For example this works regardless of the order you put your letters in. This code sample below does the exact same thing.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[KBCDEFGHIJA]%'

Again the set is how many letters you put in the square brackets. The code below is a logical mistake where you won’t get A to K but you just get A or K for the first letter.

--Find all LastNames starting with A or K (Mistake
SELECT *
FROM Employee
WHERE LastName LIKE '[AK]%'

Since we’re looking for the first letter to be within a range  from A to K, we specify that range in square brackets. This is even easier than using a set. The wildcard after the brackets allows any number of characters after the range.

--LastNames ranging from A to K using a range
SELECT *
FROM Employee
WHERE LastName LIKE '[A-K]%'

Note: this range will not work if your LIKE was changed to an equal (=) sign. The following code will not return any records to your result set:

--Bad query (it won’t error but returns no records)
SELECT *
FROM Employee
WHERE LastName = '[A-K]%'

Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 1

Q. 1) You want to find all first names that start with the letters A-M in your Customer table. Which SQL code would you use?

  1. SELECT * FROM Customer
    WHERE Firstname <= ‘m%’
  2. SELECT * FROM Customer
    WHERE Firstname  = ‘a-m%’
  3. SELECT * FROM Customer
    WHERE Firstname like ‘a-m%’
  4. SELECT * FROM Customer
    WHERE Firstname  = ‘[a-m]% ‘
  5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

Please post your answer in comment section to win Joes 2 Pros books.

Rules:

Please leave your answer in comment section below with correct option, explanation and your country of resident.
Every day one winner will be announced from United States.
Every day one winner will be announced from India.
A valid answer must contain country of residence of answerer.
Please check my facebook page for winners name and correct answer.
Winner from United States will get Joes 2 Pros Volume 1.
Winner from India will get Joes 2 Pros Volume 1.
The contest is open till next blog post shows up at which is next day GTM+2.5.

Reference:  Pinal Dave (https://blog.sqlauthority.com)

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334 Comments. Leave new

  • Lisa Guiffrida
    August 1, 2011 10:29 pm

    I believe the correct answer is #5. Thanks for the lessons.

    Lisa (USA)

    Reply
  • Amit Choudhary
    August 1, 2011 10:29 pm

    I missed one point for range [A-M] letters defiantly answer if 5.

    Reply
  • Dhanu Dhanapalan
    August 1, 2011 10:32 pm

    answer is #5 SELECT * FROM Customer WHERE FirstName like ‘[a-m]%’

    Reply
  • 5.SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Brent (USA)

    Reply
  • SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • Great idea for a series. I remember you mentioning Joes 2 Pros a while back and how good it was.

    The correct choice would be #5.

    5.SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    It is the only one that has includes the square brackets and the like condition.

    In the USA.

    Reply
  • Both 1 & 5 will work to find fist character. But to find out character on second or third place option 1st didn’t work. Because “<=" is comparison operator & "Like" is Logical operator.

    COUNTRY:- INDIA

    Reply
  • Option 5 is correct one.
    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Thanks
    Ram(USA)

    Reply
  • Samuel Masterson
    August 1, 2011 11:07 pm

    5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    The LIKE looks for words with those letters in them. The brackets will show those range of names that begin with those letters. The wildcard after the brackets within the single quotes will search for every name that begins with the letters in the brackets.

    Sam Masterson – USA

    Reply
  • 5. SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Reply
  • 5. SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Country > USA

    Reply
  • 5th option is my answer i.e. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    I’m from INDIA

    Reply
  • SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • 5> SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Country- USA

    Reply
  • The correct answer is:

    5.SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Country = United States

    Reply
  • Select number five is the one which gets the desired result.
    Why? Since the range from a-m in square brackets is a multiple choice of those letters if combined with the like operator. The wildcard after the square brackets allows any number of characters after the range.

    I’m from germany! But why do you include only America and India as possible winners? :-(

    By the way: excellent post. The wildcard range was new to me. Thanks for sharing you knowledge!!

    Greetings,
    Michael Mikic

    Reply
  • Rajneesh Verma
    August 1, 2011 11:45 pm

    Sorry Late but with right answer.
    Answer 5 is right.
    (because in your explanation you have already mention that like will not work with = the ans 1,2 and 4 out now come on 3 and 5 in three declaration of like words is wrong. so answer 5 is correct)
    below code from your tutorials also:

    –LastNames ranging from A to K using a range
    SELECT *
    FROM Employee
    WHERE LastName LIKE ‘[A-K]%’
    similar with question..

    Thanks for giving the chance of Learn and earn(win).

    Reply
  • 5. But I’m in .UK, so don’t qualify.

    It’s a useful thing to know, and to be reminded of, so thanks for that!

    Reply
  • The correct answer is the no 5.

    It will display all FirstName that start from letter A to letter M.

    The answer no 1 it will display all FirstName starting with letter A to letter M but not all names greather than char % i.e. FirstName = Mike won’t be displayed by the query no 1.

    Regards,
    Antonio
    Spain

    Reply
  • Option 1: The <= operator won't work on text expressions: https://docs.microsoft.com/en-us/sql/t-sql/language-elements/comparison-operators-transact-sql?view=sql-server-2017

    Option 2: returns all rows, if any, where the Firstname is exactly a-m%
    Option 3: returns all rows, if any, where the Firstname is begins with a?m, where ? can be any single character:
    https://docs.microsoft.com/en-us/sql/t-sql/language-elements/like-transact-sql?view=sql-server-2017

    Option 4: returns all rows, if any, where the Firstname is exactly [a-m]%
    Option 5: returns all rows, if any, where the Firstname is begins with any letter in the range a-m, case sensitive

    The [] is used for range, % is used for wildcards and must be used with the LIKE Operator.

    So, none of the options is right.

    Try:

    SELECT * FROM Customer
    WHERE FirstName like ‘[A-M]%’

    if you want names that is case insensitive, try:

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’ or FirstName like ‘[A-M]%’

    Country: Australia

    Reply

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