SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Wildcard Basics Recap – Day 1 of 35

Answer simple quiz at the end of the blog post and –
Every day one winner from India will get Joes 2 Pros Volume 1.
Every day one winner from United States will get Joes 2 Pros Volume 1.

Wildcard ranges

If you have ever been to a convention where they have a morning registration desk that must handle thousands of people in a short time you know they must put some pre-planning thought into how to handle this burst of volume. In fact often they will have many registration desks running in parallel to make things run faster. The first registration desk might handle all customer last names starting from A to K. Desk 2 will handle names from L to Q and the third desk will handle from R to Z.

With my last name being Morelan I would naturally head to registration desk #2 knowing that desk has the list with my name on it and the other desks don’t. Now let’s say you are in charge of creating these three separate lists and sending them out to the right registration workers. You know how to sort but how can you separate this lists using wildcards?

Wildcard Basics Recap

Lets start off with something most of us know already. Most SQL folks understand the usefulness and power of the basic uses of wildcards. Using wildcards allows you to do pattern matches in a column. In this case our criteria does not want to use the = sign to find a pattern match. The operator that allows you to do approximate predicates is LIKE. The LIKE operator allows you to do special relative searches to filter your result set.

--Find all LastNames that start with the letter A
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'

To find everyone whose last name starts with the letter B, you need “B” to be the first letter. After the letter B you can have any number of characters. Using B% in single quotes after the LIKE operator gets all last names starting with the letter B.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'B%'

Wildcard ranges or set specifiers

If you want to find all LastName values starting with the letters A or B you can use two predicates in your WHERE clause. You need to separate them with the OR operator.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'

Finding names beginning with A or B is easy. How about the registration desk example where want the names ranging from A-K? This works well until you want a range of A-K as in the example below:

--Find all LastNames ranging from A-K
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'
OR LastName LIKE 'C%'
OR LastName LIKE 'D%'
OR LastName LIKE 'E%'
OR LastName LIKE 'F%'
OR LastName LIKE 'G%'
OR LastName LIKE 'H%'
OR LastName LIKE 'I%'
OR LastName LIKE 'J%'
OR LastName LIKE 'K%'

The previous query does find LastName values starting from A-K. However, if you need a range of letters, the LIKE operator has many better options. We only really care about the first letter of the last name and there a several first letters that fit with what were looking for. The first letter of the last name can be A,B,C,D,E,F,G,H,I,J or K. Simply list all the choices you want for the first letter inside a set of square brackets.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[ABCDEFGHIJK]%'

Square brackets with wildcards enclose ranges or sets for 1 position. In this case the first position is a set of 11 different possible letters. This is not a series of letter but a multiple choice of letters. For example this works regardless of the order you put your letters in. This code sample below does the exact same thing.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[KBCDEFGHIJA]%'

Again the set is how many letters you put in the square brackets. The code below is a logical mistake where you won’t get A to K but you just get A or K for the first letter.

--Find all LastNames starting with A or K (Mistake
SELECT *
FROM Employee
WHERE LastName LIKE '[AK]%'

Since we’re looking for the first letter to be within a range  from A to K, we specify that range in square brackets. This is even easier than using a set. The wildcard after the brackets allows any number of characters after the range.

--LastNames ranging from A to K using a range
SELECT *
FROM Employee
WHERE LastName LIKE '[A-K]%'

Note: this range will not work if your LIKE was changed to an equal (=) sign. The following code will not return any records to your result set:

--Bad query (it won’t error but returns no records)
SELECT *
FROM Employee
WHERE LastName = '[A-K]%'

Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 1

Q. 1) You want to find all first names that start with the letters A-M in your Customer table. Which SQL code would you use?

  1. SELECT * FROM Customer
    WHERE Firstname <= ‘m%’
  2. SELECT * FROM Customer
    WHERE Firstname  = ‘a-m%’
  3. SELECT * FROM Customer
    WHERE Firstname like ‘a-m%’
  4. SELECT * FROM Customer
    WHERE Firstname  = ‘[a-m]% ‘
  5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

Please post your answer in comment section to win Joes 2 Pros books.

Rules:

Please leave your answer in comment section below with correct option, explanation and your country of resident.
Every day one winner will be announced from United States.
Every day one winner will be announced from India.
A valid answer must contain country of residence of answerer.
Please check my facebook page for winners name and correct answer.
Winner from United States will get Joes 2 Pros Volume 1.
Winner from India will get Joes 2 Pros Volume 1.
The contest is open till next blog post shows up at which is next day GTM+2.5.

Reference:  Pinal Dave (https://blog.sqlauthority.com)

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334 Comments. Leave new

  • Hi Pinal,

    Correct answer is option 5. it gives correct result.
    Country-India

    Thanks & Regards,
    Fazal Vahora

    Reply
  • My answer is option 5. as said above we can specify the range in [ ] with like operator. so option 5 will work. option 1 shows upto ‘L’ but not ‘M’ I am from India,

    Reply
  • Nikhil Mahajan
    August 1, 2011 12:15 pm

    the correct answer is “answer 5”
    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    it will return all record of range “a to m”.
    i am from india

    Reply
  • Option 5 is the correct answer.

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Returns all the record that starts with range of character specified in charlist [a-m] (i.e)[abcdefghijklm] from the Customer table.

    by
    Yasodha.N (India)

    Reply
  • SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • To find all first names that start with the letters A-M in Customer table. Which we will use below SQL code:

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • To retrieve names starting with A – M from Customer table you would need to use: Option 5

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Using a char list wildcard in a square bracket ensures that the query returns any single character in range of char list (in this case names starting with ‘A’ through ‘M’)

    Using a ‘<=' and '=' instead of LIKE would not work so the Option 1 , 2 & 4 is out of question.

    Option 3 does not return results as its missing square brackets with range of choices.

    Reply
  • Option 5 is the correct answer.

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Returns all the record that starts with range of character specified in charlist [a-m] (i.e)[abcdefghijklm] from the Customer table.

    by
    Yasodha.N (India)

    Reply
  • Mostafa Elmasry
    August 1, 2011 1:44 pm

    5-SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • Nigel Clayforth
    August 1, 2011 2:36 pm

    1st comment is why do you not include Europe in your quiz?

    2nd comment should you choose to include anyone from England :-) this is the answer

    5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Regards

    Nigel

    Reply
  • Example # 5 will return the required data. It used the LIKE options that allows for relative searches. The Brackets allow for the range of the realtive search. And of course the WILDCARD allows for a Pattern match.

    Also I realy like this kind of Q&A. Good Job!

    Ron

    Reply
  • The answer will be;

    SELECT * FROM tblStudentMaster
    WHERE Firstname like ‘[a-m]%’ order by firstName

    But i little confused in Option 1 and 5. 1st option will return single value of name starts with M.

    Will you tell me the difference between 1st and 5th option.

    Reply
  • Bhargav Mistri
    August 1, 2011 6:03 pm

    Answer is 5 – SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’
    because we want firstname which is start from keyword between a-m.
    Country – INDIA

    Reply
  • Bhargav Mistry
    August 1, 2011 6:03 pm

    Answer is 5 – SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’
    because we want firstname which is start from keyword between a-m.
    Country – INDIA

    Reply
  • Pinal,

    The correct answer for today’s quiz is the 5th choice:

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    I am from the United States.

    Best Regards,

    Bill Pepping

    Reply
  • Jeffrey Davis
    August 1, 2011 7:26 pm

    I believe the answer would be: 5) SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    However, is it not case sensitive? Based on your question, should it not be SELECT * FROM Customer
    WHERE Firstname like ‘[A-M]%’ ?

    The reason is that you need to use the like operator, rather than the equal sign, when doing a wildcard search. In addition, the range needs to be in square brackets in order to work correctly on the first character of the search.

    I am from the United States (Ohio).

    Reply
  • Chintan Gandhi
    August 1, 2011 7:26 pm

    Answer is option 5 – SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’
    I’m from India

    Reply
  • After reading your post, obviously the answer is #5, because you made this topic super clear in your blog. Thanks a lot.

    Reply
  • Amit Choudhary
    August 1, 2011 10:26 pm

    SELECT * FROM Customer
    WHERE Firstname like ‘a-m%’

    Simple and straight..

    Reply
  • Correnct Answer is : choice #5
    USA

    Thanks!

    Reply

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