SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Wildcard Basics Recap – Day 1 of 35

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Wildcard ranges

If you have ever been to a convention where they have a morning registration desk that must handle thousands of people in a short time you know they must put some pre-planning thought into how to handle this burst of volume. In fact often they will have many registration desks running in parallel to make things run faster. The first registration desk might handle all customer last names starting from A to K. Desk 2 will handle names from L to Q and the third desk will handle from R to Z.

With my last name being Morelan I would naturally head to registration desk #2 knowing that desk has the list with my name on it and the other desks don’t. Now let’s say you are in charge of creating these three separate lists and sending them out to the right registration workers. You know how to sort but how can you separate this lists using wildcards?

Wildcard Basics Recap

Lets start off with something most of us know already. Most SQL folks understand the usefulness and power of the basic uses of wildcards. Using wildcards allows you to do pattern matches in a column. In this case our criteria does not want to use the = sign to find a pattern match. The operator that allows you to do approximate predicates is LIKE. The LIKE operator allows you to do special relative searches to filter your result set.

--Find all LastNames that start with the letter A
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'

To find everyone whose last name starts with the letter B, you need “B” to be the first letter. After the letter B you can have any number of characters. Using B% in single quotes after the LIKE operator gets all last names starting with the letter B.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'B%'

Wildcard ranges or set specifiers

If you want to find all LastName values starting with the letters A or B you can use two predicates in your WHERE clause. You need to separate them with the OR operator.

--Find all LastNames that start with the letter B
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'

Finding names beginning with A or B is easy. How about the registration desk example where want the names ranging from A-K? This works well until you want a range of A-K as in the example below:

--Find all LastNames ranging from A-K
SELECT *
FROM Employee
WHERE LastName LIKE 'A%'
OR LastName LIKE 'B%'
OR LastName LIKE 'C%'
OR LastName LIKE 'D%'
OR LastName LIKE 'E%'
OR LastName LIKE 'F%'
OR LastName LIKE 'G%'
OR LastName LIKE 'H%'
OR LastName LIKE 'I%'
OR LastName LIKE 'J%'
OR LastName LIKE 'K%'

The previous query does find LastName values starting from A-K. However, if you need a range of letters, the LIKE operator has many better options. We only really care about the first letter of the last name and there a several first letters that fit with what were looking for. The first letter of the last name can be A,B,C,D,E,F,G,H,I,J or K. Simply list all the choices you want for the first letter inside a set of square brackets.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[ABCDEFGHIJK]%'

Square brackets with wildcards enclose ranges or sets for 1 position. In this case the first position is a set of 11 different possible letters. This is not a series of letter but a multiple choice of letters. For example this works regardless of the order you put your letters in. This code sample below does the exact same thing.

--LastNames ranging from A to K using a set of 11 letters
SELECT *
FROM Employee
WHERE LastName LIKE '[KBCDEFGHIJA]%'

Again the set is how many letters you put in the square brackets. The code below is a logical mistake where you won’t get A to K but you just get A or K for the first letter.

--Find all LastNames starting with A or K (Mistake
SELECT *
FROM Employee
WHERE LastName LIKE '[AK]%'

Since we’re looking for the first letter to be within a range  from A to K, we specify that range in square brackets. This is even easier than using a set. The wildcard after the brackets allows any number of characters after the range.

--LastNames ranging from A to K using a range
SELECT *
FROM Employee
WHERE LastName LIKE '[A-K]%'

Note: this range will not work if your LIKE was changed to an equal (=) sign. The following code will not return any records to your result set:

--Bad query (it won’t error but returns no records)
SELECT *
FROM Employee
WHERE LastName = '[A-K]%'

Note: If you want to setup the sample JProCo database on your system you can watch this video.

Question 1

Q. 1) You want to find all first names that start with the letters A-M in your Customer table. Which SQL code would you use?

  1. SELECT * FROM Customer
    WHERE Firstname <= ‘m%’
  2. SELECT * FROM Customer
    WHERE Firstname  = ‘a-m%’
  3. SELECT * FROM Customer
    WHERE Firstname like ‘a-m%’
  4. SELECT * FROM Customer
    WHERE Firstname  = ‘[a-m]% ‘
  5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

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Rules:

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A valid answer must contain country of residence of answerer.
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Reference:  Pinal Dave (https://blog.sqlauthority.com)

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334 Comments. Leave new

  • sachin kulshreshtha
    August 3, 2011 11:19 pm

    Answer : Option 5
    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Country : India

    Reply
  • I assume there is no case sensitivity. with that answer is #5.

    SELECT * FROM Customer
    WHERE Firstname like ‘[A-M]%’

    Since we’re looking for the first letter to be within a range from A to M, we specify that range in square brackets. The wildcard after the brackets allows any number of characters after the range.

    -Priti Shah
    USA.

    Reply
  • Ramesh Muthukrishnan
    August 4, 2011 12:08 am

    Answer : Option 5.

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Country : USA

    Reply
  • Vaibhav Mathur
    August 4, 2011 12:08 am

    It should be 5. – SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Regards,
    Vaibhav Mathur

    Reply
  • Q. 1) You want to find all first names that start with the letters A-M in your Customer table. Which SQL code would you use?

    In the question, you mentioned that first names that start with the letters A-M. But not range from. So i am assuming that you are looking for all first names with starting A-M.
    then my option3 is right

    Though i know that no person’s firstname starts with A-M but only range from A-M.

    else

    option 5 if you are looking for range of values from A-M.

    I live in United States. I dont work in this field but interested to learn.

    5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Reply
  • Answer: Option 5
    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Country: USA

    Reply
  • it is hardly 5PM here in USA and your contest is closed. Also, what is the point of posting all the answers visible which is very easy to figure out the correct or it is just a fun to see how many people participate and log into your page.

    Reply
  • Gerardo Melendrez (@payini)
    August 4, 2011 8:09 am

    Answer is: 5. SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’
    Residence: USA

    Reply
  • Answer: Option 5
    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    FROM: Philippines

    Reply
  • Answer is option 5

    My Name: J M Arun

    Country: India

    Explaination:
    This range will not work if your LIKE was changed to an equal (=) sign. The following code will not return any records to your result set:

    Reply
  • Saurabh Sontakke
    August 4, 2011 9:03 am

    5.SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    Answer is option 5

    Reply
  • Howdy from Texas, Pinal. It’s 5, as every regexp student knows.

    Reply
  • Rafael Garcia
    August 4, 2011 9:24 am

    Answer is option number 5. Actually I use this logic to eliminate or filter values in my where statements.

    Ex: select order_number from table where not(upper(order_number)) like ‘[A-Z]%’.

    Why? Because we have test order numbers in our data base that look like this: 0004217afv or 000345TEST. Real orders are numeric only.

    Reply
  • Answer 5
    Jaipur India

    Reply
  • Vanthiya Thevan. N
    August 4, 2011 10:14 am

    The answer is Option 5.

    SELECT * FROM Customer
    WHERE Firstname like ‘[a-m]%’

    India

    Reply
  • Dhruval Shahuval Shah
    August 4, 2011 10:20 am

    Correnct Answer is : Option 5

    SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Thanks
    Dhruval Shah, India.

    Reply
  • Dhruval Vikram Shah
    August 4, 2011 10:21 am

    Correnct Answer is : Option 5

    SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Thanks
    Dhruval Shah, India.

    Reply
  • Option #5
    India

    Reply
  • Option 5. SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’

    Country : India

    Ganesh Kumar

    Reply
  • SELECT * FROM Customer WHERE Firstname like ‘[a-m]%’ , sir this will find your names from A to M alphabets.

    Reply

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