SQL SERVER – Quiz and Video – Introduction to Hierarchical Query using a Recursive CTE

This is follow up blog post of my earlier blog post on the same subject – SQL SERVER – Introduction to Hierarchical Query using a Recursive CTE – A Primer. In the article we discussed various basics terminology of the CTE. The article further covers following important concepts of common table expression.

  • What is a Common Table Expression (CTE)
  • Building a Recursive CTE
  • Identify the Anchor and Recursive Query
  • Add the Anchor and Recursive query to a CTE
  • Add an expression to track hierarchical level
  • Add a self-referencing INNER JOIN statement

Above six are the most important concepts related to CTE and SQL Server.  There are many more things one has to learn but without beginners fundamentals one can’t learn the advanced  concepts. Let us have small quiz and check how many of you get the fundamentals right.

Quiz

1) You have an employee table with the following data.

EmpID FirstName LastName MgrID
1 David Kennson 11
2 Eric Bender 11
3 Lisa Kendall 4
4 David Lonning 11
5 John Marshbank 4
6 James Newton 3
7 Sally Smith NULL

You need to write a recursive CTE that shows the EmpID, FirstName, LastName, MgrID, and employee level. The CEO should be listed at Level 1. All people who work for the CEO will be listed at Level 2. All of the people who work for those people will be listed at Level 3. Which CTE code will achieve this result?

  1. WITH EmpList AS
    (SELECT Boss.EmpID, Boss.FName, Boss.LName, Boss.MgrID,
    1 AS Lvl
    FROM Employee AS Boss WHERE Boss.MgrID IS NULL
    UNION ALL
    SELECT E.EmpID, E.FirstName, E.LastName, E.MgrID, EmpList.Lvl + 1
    FROM Employee AS E INNER JOIN EmpList
    ON E.MgrID = EmpList.EmpID)
    SELECT * FROM EmpList
  2. WITH EmpListAS
    (SELECT EmpID, FirstName, LastName, MgrID, 1 as Lvl
    FROM Employee WHERE MgrID IS NULL
    UNION ALL
    SELECT EmpID, FirstName, LastName, MgrID, 2 as Lvl )
    SELECT * FROM BossList
  3. WITH EmpList AS
    (SELECT EmpID, FirstName, LastName, MgrID, 1 as Lvl
    FROM Employee WHERE MgrID is NOT NULL
    UNION
    SELECT EmpID, FirstName, LastName, MgrID, BossList.Lvl + 1
    FROM Employee INNER JOIN EmpList BossList
    ON Employee.MgrID = BossList.EmpID)
    SELECT * FROM EmpList

2) You have a table named Employee. The EmployeeID of each employee’s manager is in the ManagerID column. You need to write a recursive query that produces a list of employees and their manager. The query must also include the employee’s level in the hierarchy. You write the following code segment:

WITH EmployeeList (EmployeeID, FullName, ManagerName, Level)
AS (
–PICK ANSWER CODE HERE
)

  1. SELECT EmployeeID, FullName, ” AS [ManagerID], 1 AS [Level]
    FROM Employee
    WHERE ManagerID IS NULL
    UNION ALL
    SELECT emp.EmployeeID, emp.FullName mgr.FullName, 1 + 1 AS [Level]
    FROM Employee emp JOIN Employee mgr
    ON emp.ManagerID = mgr.EmployeeId
  2. SELECT EmployeeID, FullName, ” AS [ManagerID], 1 AS [Level]
    FROM Employee
    WHERE ManagerID IS NULL
    UNION ALL
    SELECT emp.EmployeeID, emp.FullName, mgr.FullName, mgr.Level + 1
    FROM EmployeeList mgr JOIN Employee emp
    ON emp.ManagerID = mgr.EmployeeId

Now make sure that you write down all the answers on the piece of paper.

Watch following video and read earlier article over here. If you want to change the answer you still have chance.

Solution

1) 1

2) 2

Now compare let us check the answers and compare your answers to following answers. I am very confident you will get them correct.

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Volume: 12345

Please leave your feedback in the comment area for the quiz and video. Did you know all the answers of the quiz?

Reference: Pinal Dave (http://blog.sqlauthority.com)

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6 thoughts on “SQL SERVER – Quiz and Video – Introduction to Hierarchical Query using a Recursive CTE

  1. Hi pinal,

    I have tried the above example but its not working for me. i tried the first question. but its showing only one record. Here is my defination.

    create table #Employee
    (
    EmpID int identity(1,1),
    FirstName varchar(500),
    MgrID int
    )
    insert into #Employee
    (
    FirstName,
    MgrID
    )
    values
    (
    ‘David’,
    11
    ),(‘Eric’,11),(‘Lisa’,4),(‘David’,11),(‘John’,4),(‘James’,3),(‘Sally’,null)

    select * from #Employee

    ———–Emp with recurssion
    WITH EmpList AS
    (
    SELECT
    Boss.EmpID,
    Boss.FirstName,
    Boss.MgrID,
    1 AS Lvl
    FROM
    #Employee AS Boss
    WHERE
    MgrID IS NULL
    UNION ALL
    SELECT
    E.EmpID,
    E.FirstName,
    E.MgrID,
    EmpList.Lvl + 1
    FROM
    #Employee AS E
    INNER JOIN EmpList ON
    E.MgrID = EmpList.EmpID
    )
    SELECT distinct * FROM EmpList order by MgrID asc

    Thanks,

  2. Pingback: SQL SERVER – SQL in Sixty Seconds – 5 Videos from Joes 2 Pros Series – SQL Exam Prep Series 70-433 « SQL Server Journey with SQL Authority

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