Kevin Scharnhorst
United States

Don

SELECT Storename, StoreHours.query(‘data(/hours[@dayofWeek="Wednesday"]/@open)’)
FROM Building

A.)None is the correct answer.

Winner from USANaomi

Winner from India: Mitesh Modi

I thank you all for participating here. The permanent record of this update is posted on facebook page.

Thanks for the input.

You are correct regarding that EXIST doesn’t show all the data.

While I didn’t just see 8 am in my result set, I clearly wasn’t retrieving all of the Wednesday opening times.

Thanks for the insight.

Bill

Vaishali
Country of residence: Hyderabad, India

Thanks
Narendra(India)

SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

Mahmad Khoja
India

I agree with Naomi
Ans given by Naomi using Cross Apply which is working.

IF I run the third option I get the same error as Naomi
Msg 2396, Level 16, State 1, Line 35
XQuery [@Buildings.StoreHours.query()]: Attribute may not appear outside of an element

Error Solution
——————
Use the data() function to query attributes and resolve this problem

DECLARE @Buildings table(StoreName varchar(10), StoreHours XML)
INSERT INTO @Buildings( StoreName, StoreHours )
VALUES ( ‘A’,
‘

‘
)

INSERT INTO @Buildings( StoreName, StoreHours )
VALUES ( ‘B’,
‘

‘
)
INSERT INTO @Buildings( StoreName, StoreHours )
VALUES ( ‘C’,
‘

‘
)

–SELECT * FROM @Buildings
declare @Day varchar(20)
set @Day = ‘Wednesday’

SELECT Storename, StoreHours.query(‘data(/hours[@dayofWeek="Wednesday"]/@open)’) AS ‘WedOpenTime’
FROM @Buildings

StoreName WedOpenTime
A 6:00
B 7:00
C 8:00

Mitesh Modi
(India)

2.SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

Country:India

SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

Nikhildas
Cochin
INDIA

Regards
Rajesh
From india

Thanks Pinal for this series. I read all the questions and also tried to give answers. I won a Book also.:)

Rajneesh Verma
(INDIA)

2 ) SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

Its bit complex to choose correct answer for Day35 Blog Quiz Series.

Chennai, Tamilnadu, India

Make sure to create different store hours for every day (say, put some exotic values for Wednesday) and re-test. You’ll notice, that the second option (with the modifications) will return the first record and not the Wednesday open hours. The reason is that ‘exist’ option checks for existence of the option (in this case it checks that Wednesday exists and it’s true), but it doesn’t select that option.

So, the correct answer to this question – none of the options as presented returns the correct result.

SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

Unfortunately with it being a weekend I do not have access to sql mgmt studio to check it. I would think the space before Wed would create a problem. The third one just doesn’t look right to me and the first one might work but I’m not sure about the where clause. I know how exists works and I feel better about the second option.

USA

Challenge:
Question 35
You have a table named Buildings that has an XML column named StoreHours. This column contains the opening and closing times:

…

You need to write a query that returns a list of Buildings and their opening time for Wednesday. Which code segment should you use?

1.SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.value(‘/hours[1]/@dayofWeek’,’varchar(20)’) = @Day

2.SELECT StoreName, StoreHours. value(‘/hours[1]/@open’,’time’)
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek=" Wednesday"]‘) = 1

3.SELECT Storename, StoreHours.query(‘/hours[@dayofWeek="Wednesday"]/@open’)
FROM Buildings

Correct Answer:
The correct choice is # 2, with some slight SQL syntax modifications.

Explanation:
Besides replacing the single and double quotation marks (they were italics), the query still doesn’t return any data unless you remove the space in
” Wednesday” (use “Wednesday”). Here is what my final query looked like”:

SELECT StoreName, convert(varchar(5), StoreHours.value(‘/hours[1]/@open’,'time’), 8) + ‘ AM’ as ‘Opening Time on Wednesdays’
FROM Buildings
WHERE StoreHours.exist(‘/hours[@dayofWeek="Wednesday"]‘) = 1

Here is the data I retrieved (after creating a Buildings table and inserting StoreName (varchar) and Opening Times (XML data)):

StoreName Opening Time on Wednesdays

Super Market 08:00 AM
Sports Arena 10:00 AM
Office 08:00 AM

Country:
United States

Thanks for the knowledge!

Regards,

Bill Pepping

Gordon Kane
Allen TX
USA

If “Wednesday” exist then the opening hours will be retrieved and displayed.

I’m from USA

Country: United States