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	<title>Comments on: SQLAuthority News &#8211; Programming &amp; Development For Microsoft SQL Server 2008</title>
	<atom:link href="http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/feed/" rel="self" type="application/rss+xml" />
	<link>http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/</link>
	<description>Personal Notes of Pinal Dave</description>
	<lastBuildDate>Fri, 17 May 2013 15:26:57 +0000</lastBuildDate>
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	<item>
		<title>By: itrentals.co.uk</title>
		<link>http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/#comment-280838</link>
		<dc:creator><![CDATA[itrentals.co.uk]]></dc:creator>
		<pubDate>Mon, 30 Apr 2012 15:21:29 +0000</pubDate>
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		<description><![CDATA[I liked it, and agree with your wife.]]></description>
		<content:encoded><![CDATA[<p>I liked it, and agree with your wife.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: poshendra</title>
		<link>http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/#comment-174164</link>
		<dc:creator><![CDATA[poshendra]]></dc:creator>
		<pubDate>Sun, 02 Oct 2011 10:35:14 +0000</pubDate>
		<guid isPermaLink="false">http://blog.sqlauthority.com/?p=14170#comment-174164</guid>
		<description><![CDATA[Good Answer]]></description>
		<content:encoded><![CDATA[<p>Good Answer</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Boris Mitchenko</title>
		<link>http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/#comment-165179</link>
		<dc:creator><![CDATA[Boris Mitchenko]]></dc:creator>
		<pubDate>Sat, 03 Sep 2011 17:21:29 +0000</pubDate>
		<guid isPermaLink="false">http://blog.sqlauthority.com/?p=14170#comment-165179</guid>
		<description><![CDATA[SELECT [Status], COUNT(*)
FROM [dbo].[Table]
GROUP BY [Status]]]></description>
		<content:encoded><![CDATA[<p>SELECT [Status], COUNT(*)<br />
FROM [dbo].[Table]<br />
GROUP BY [Status]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Dhruval</title>
		<link>http://blog.sqlauthority.com/2011/09/02/sqlauthority-news-programming-development-for-microsoft-sql-server-2008/#comment-164703</link>
		<dc:creator><![CDATA[Dhruval]]></dc:creator>
		<pubDate>Fri, 02 Sep 2011 09:10:05 +0000</pubDate>
		<guid isPermaLink="false">http://blog.sqlauthority.com/?p=14170#comment-164703</guid>
		<description><![CDATA[Hi Sql Team,
I Need Your Help.

I Have One Table In Which I Have one Column Having name &#039;Status&#039;.
In Which I Have Stored &#039;Match&#039; and &#039;UnMatch&#039;. Value.

I Want the Total Num. Of match and Unmatch Values.]]></description>
		<content:encoded><![CDATA[<p>Hi Sql Team,<br />
I Need Your Help.</p>
<p>I Have One Table In Which I Have one Column Having name &#8216;Status&#8217;.<br />
In Which I Have Stored &#8216;Match&#8217; and &#8216;UnMatch&#8217;. Value.</p>
<p>I Want the Total Num. Of match and Unmatch Values.</p>
]]></content:encoded>
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