**Answer simple quiz at the end of the blog post and –**

** Every day one winner from India will get Joes 2 Pros Volume 2.**

** Every day one winner from United States will get Joes 2 Pros Volume 2.**

## Ranking Functions (Part 1)

There are four ranking functions in SQL server. Today we will look at RANK( ), DENSE_RANK( ), and ROW_NUMBER( ).These functions all have the same basic behavior. Where they differ is in the handling of tie values. These three functions produce identical results, until a tying value in your data is present.

Until the tie data is encountered, the results are identical (see Josh and Kevin’s score of 9.6. We will explain more on this later. Let’s look at RANK( ) using a Grant table example sorted by largest to smallest grant amount (descending sort order).

A smart way to begin your ranking functions is to first write a SELECT statement with an ORDER BY clause. Every ranking function retrieves your sort order from the ORDER BY clause. In this case, the item is grant amount arranged in descending order. Add RANK( ) to the SELECT list. Remember that all ranking functions need an OVER( ) clause. If you then SQL Server reminds you as you can see from the error message below.

All ranking functions need an OVER( ) clause and SQL Server provides another syntax clue for the ORDER BY clause. Ranking functions need the ORDER BY information to appear as an argument of the OVER( ) clause Move the ORDER BY clause inside the parentheses of OVER( ) clause.

Now we can look at how RANK() works with ties. The Grant table ranked over the Amount column, showing 2 pairs of tied amounts. There is a 2 way tie for 4th place so both the grants of $21,000 get a rank of 4. After that there is no 5^{th} place grant. There is a 6^{th} place grant so after ties you get a gap to match the numbered order. Observe that no ORDER BY clause follows the FROM clause, since we moved it in into the OVER( ) clause. Examine what the RANK( ) function has done here. We see straightforward rankings of 1, 2, and 3 for the first three unique amount values. Notice the tie for fourth place. Then there’s another tie for the next place, which is ranked as 6. After that we get to 8^{th} place as seen in the figure below.

How about Dense_Rank? After the 2 way tie for 4^{th} place the next value will get 5^{th} place. There will be no gaps after the tie with the DENSE_RANK(). DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence.

*Note*: If you want to setup the sample JProCo database on your system you can watch this video. For this post you will want to run the SQLQueriesChapter7.0Setup.sql script from Volume 2.

## Question 12

The figure below shows the scores of 6 contest winners. Tom is the highest

and Eric made 6^{th} place. There were 6 people but only 5 distinct scores.

9.9 9.9 9.8 9.8 9.7 9.7 9.6 9.6 9.6 9.2 |

You are writing a query to list the 5 highest distinct scores. The Ranked field should be called ScoreRating. You have written the following code.

SELECT * FROM (SELECT *More code here.FROM [Contestants]) AS ContestantFinal WHERE ScoreRating <= 5

What code will achieve this goal?

- SUM(*) OVER(ORDER BY Score DESC) as ScoreRating
- RANK( ) OVER(ORDER BY Score DESC) as ScoreRating
- COUNT(*) OVER(ORDER BY Score DESC) as ScoreRating
- DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

**Rules:**

Please leave your answer in comment section below with correct option, explanation and your country of resident.

Every day one winner will be announced from United States.

Every day one winner will be announced from India.

**A valid answer must contain country of residence of answerer.**

Please check my **facebook page** for winners name and correct answer.

Winner from United States will get **Joes 2 Pros Volume 2**.

Winner from India will get **Joes 2 Pros Volume 2**.

The contest is open till next blog post shows up at http://blog.sqlauthority.com which is next day GTM+2.5.

Reference: Pinal Dave (**http://blog.SQLAuthority.com****)**

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Chetan – USA

LikeLike

Correct answer is No. 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

as we want to get the five highest distinct amounts.

Rene Castro

El Salvador

LikeLike

Correct option is 4.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

New Delhi

LikeLike

This time I guess you have a typo. For the five highest distinct scores none of your choices give the answer mostly because of typo in main body of the question. 2) and 4) are syntactically correct

4) is the one closest to the solution as it presents only the distinct values of scores

The question should have

“WHERE ScoreRating <= 5" instead of "WHERE ScoreRating = 5"

SELECT * FROM

(SELECT *, DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating <= 5

Leo Pius

USA

LikeLike

The correct option is #4

DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

DENSE_RANK provides distinct scores.

LikeLike

Forgot to add in my prev. reply – I’m from USA

The correct option is #4

DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

DENSE_RANK provides distinct scores.

LikeLike

Correct answer is option #4

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

becuase as explained in the article above DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence.

Thanks.

Country – India

LikeLike

Actually, when I think a bit more, the question asked is quite tricky.

If we want to list just the five distinct top scores, we can do:

;with Scores as (select Score, dense_rank() over (partition by Score DESC) as [ScoreRank] from ContestantFinal)

select Distinct Score from Scores where ScoreRank <=5

———————————————————————-

With the query #4

SELECT * FROM

(SELECT *, DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

we will get all people who were on the 5th place.

I am from USA

LikeLike

Question 12

Ans : DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Chennai, INDIA

LikeLike

Answer : option 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Nikhildas

Cochin,INDIA

LikeLike

The correct ans is #4

LikeLike

What code will achieve this goal?

Main query is itself wrong

as where condition looking for ScoreRating=5

This wont give Correct result

Does not give any distinct values.

If In where condition ScoreRating<6 then we can use option 4 in sub-query

Answer is 4

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Gives but does not give the distinct ratings.

wrong:

1. SUM(*) OVER(ORDER BY Score DESC) as ScoreRating

Because * can not be used in Sum Function

2. RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Because Misses the rank numbers

3. COUNT(*) OVER(ORDER BY Score DESC) as ScoreRating

count(*) will count for all rows..this result we are not expecting and

LikeLike

Option 4 is correct.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

As we need to return the scorerating 5, it is only possible if we use DENSE_RANK here.

INDIA

LikeLike

correct answer is option 4

India

LikeLike

Answer 4:

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

as we want to get the five highest distinct amounts.

India

LikeLike

4th option.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Arjun

India.

LikeLike

Question 12

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

LikeLike

a query to list the 5 highest distinct scores write the following code.

SELECT * FROM

(SELECT * , DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating <=5

Ans :DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Krishnakant Joshi

India

LikeLike

Correct answer is 4 as

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Varinder Sandhu (India)

LikeLike

Hi,

Option 4 is correct Answer:

“DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating”

Thanks…

Rajneesh Verma

(INDIA)

LikeLike

Ans is 4:

4: SELECT * FROM

(SELECT *, DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

Partha

India

LikeLike

The correct answer is option 4 that is

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

So your code will now look like this

SELECT * FROM

(

SELECT * , DENSE_RANK( )

OVER(ORDER BY Score DESC

) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

This will give you the desired result

Mahmad Khoja

INDIA

AHMEDABAD

LikeLike

Answer : 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

India

LikeLike

Correct option is 4.

Shilpa

India

LikeLike

Option-4 is the Correct Answer

Thanks,

Narendra(India)

LikeLike

Pingback: SQL SERVER – Win a Book a Day – Contest Rules – Day 0 of 35 Journey to SQLAuthority

Correct answer is 4

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

City: Baroda

Country: INDIA

Thanks

GurjitSingh

LikeLike

The correct answer : Option 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

The actual Query is like this

SELECT * FROM

(SELECT * , DENSE_RANK( ) OVER(ORDER BY Score DESC) ‘ScoreRating’

FROM [Contestants]) AS ContestantFinal WHERE ScoreRating = 5

— GVPrabu || Bangalore || India

LikeLike

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating is Correct one..

Thanks.

Mithil Mehta(India)

LikeLike

Correct answer is option 4

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Cheers,

Prasad Yangamuni

INDIA ( PUNE)

LikeLike

Correct option is 4.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Pratik Raval

India

LikeLike

Correct Answer is Option 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country:India

Thanks,

Fazal

LikeLike

Hi Sir,

None of the options provided are answer for the question.

1st and 3rd Option is syntactically incorrect which will throw an error.

2nd option is syntactically correct but will provide null result

as Rank() will provide 5 values of rank 1,2,3,4,4 and there is no rank which is equal to 5

SELECT * FROM

(SELECT *, RANK() OVER(ORDER BY Score DESC) as ScoreRating

FROM PlayerScore) AS ContestantFinal

WHERE ScoreRating = 5

4th Option is syntactically correct

SELECT * FROM

(SELECT *, DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM PlayerScore) AS ContestantFinal

WHERE ScoreRating = 5

This option will provide only the 5th ranked value that is

Player : Eric

Score : 9.20

ScoreRating : 5

So all the options does not satisfy the question which says to list 5 Highest distinct scores and the ranks.

The correct query is :

SELECT * FROM

(SELECT Distinct Score, DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM PlayerScore) AS ContestantFinal

WHERE ScoreRating <= 5

this will provide the required result for the question with the result

Score ScoreRating

——- ————–

9.9 1

9.8 2

9.7 3

9.6 4

9.2 5

Nice question…:)

Thanks

P.Anish Shenoy,

INDIA

LikeLike

Answer is 4

SELECT * FROM

(SELECT *, DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

DENSE_RANK() function create same rank number for same value.

Country : India

City: Ahmedabad

LikeLike

Correct Answer – 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Deepali Bhende

Country – INDIA

LikeLike

Correct Answer – 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

example code run –

SELECT * FROM

(SELECT * , DENSE_RANK() OVER(ORDER BY Score DESC) as ScoreRating

FROM Contestants) AS ContestantFinal

WHERE ScoreRating = 5

Shekhar Gurav.

Country : INDIA

LikeLike

Nice Example Sir.

LikeLike

Hi Pinal

Option 4 is correct. But need to some changes in the query

SELECT Distinct Score FROM

(SELECT Score,DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating <= 5

Rajesh Garg

India

LikeLike

Option 4 is Correct

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

India

LikeLike

U r rite rajesh..we need to use distinct over there

LikeLike

Correct answer is 4.

Country : India

City : Mumbai

LikeLike

Option No:- 4

SELECT * FROM

(SELECT *, DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

You will get all the people who were on the 5th place.

Somnath Desai

LikeLike

Somnath From India

LikeLike

Answer 4

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country : India

LikeLike

1. SUM(*) will give a syntax error. Hence Eliminated.

2. Rank will skip the next numbers after occurance of multiple values at same ranking position. Hence Eliminated.

3. Count(*) will count all the rows. Hence Eliminated.

4. DENSE_RANK() will give the ranking position without skipping any number.

Hence 4 is the correct option.

Ishan Shah

Gandhinagar,

India

LikeLike

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

as we want to get the five highest distinct amounts.

Ghanshyam

bangalore

LikeLike

Correct Answer is # 4.

DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence.

Gopalakrishnan Arthanarisamy

Unisys, India, Bangalore

LikeLike

Option 4 is the correct answer.

INDIA.

LikeLike

correct option is 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

I’m from INDIA

LikeLike

Option 4 is the correct ans.

Syntax is as follow :

(SELECT *, DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

Pritesh Mehta.

India.

LikeLike

Option : 4

DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

Above code only matches to get top 5 Score Rating.

Chennai, India

LikeLike

The correct answer is option 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

but the query needs to be changed. it should be <=5 , NOT =5 as it will return record with ScoreRating 5 only

Sumit

India

LikeLike

Answer : 4

DENSE_RANK OVER (ORDER BY Score DESC) as ScoreRating

Chennai, TamilNadu, India

LikeLike

Correct answer is: Option 4 DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country: India

LikeLike

option 4 is correct

LikeLike

As per requirement none of the option provide correct result as last option only provide the fifth highest distinct score.

For getting all five distinct highest scores where clause must be ‘<=' instead of '=' .

After saying so, i will say DENSE_RANK() function provide a unique rank no to each of the unique score whereas RANK() function provide a unique rank to unique score but skips the one rank no.. if two scores were same. SUM() and COUNT() function provides sum and count of total no of scores. So, Option 1,2,3 are not at all nearer to the solution .

Hence, Only option nearer to the solution is option 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country – INDIA (Gujarat)

LikeLike

orrect Answer – 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

LikeLike

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

LikeLike

Correct answer: #4 (DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating)

Country of residence: India

LikeLike

Correct answer is:

4) DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country: India

LikeLike

Answer 4 is correct

USA

Mike Michalicek

LikeLike

Option : 4 is correct.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

As per requirement this query will return 5 distinct values.

Thanks,

Rajasekar.K

Bangalore – India.

LikeLike

Option : 4 is correct.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Dhina-India

LikeLike

Hi,

correct ans is this

4) DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

I am from India

LikeLike

SELECT * FROM

(SELECT score, DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

FROM #temp) AS ContestantFinal

WHERE ScoreRating < 5

so correct answer is :DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

and another thing is that you will have to use "ScoreRating < 5" instead of "ScoreRating = 5"

I am From INDIA

LikeLike

Of the options provided, I would think you are looking for #4 to be the answer

DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

because your article states “DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence.”

However running that query will only return those with scores equal to the 5th highest score. You’d acutally want something like this to return just the 5 highest scores…

Select * FROM

(SELECT distinct Score, DENSE_Rank() Over( Order by Score Desc) as ScoreRating

From Contestants) as ContestantFinal

where ScoreRating <= 5

from the USA

LikeLike

Option 4 is correct

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

County : India

LikeLike

Answer : 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

LikeLike

Hi Pinal,

Challenge:

Question 12

The figure below shows the scores of 6 contest winners. Tom is the highest

and Eric made 6th place. There were 6 people but only 5 distinct scores.

5 Highest Scores 5 Highest Distinct Scores

9.9 9.9

9.8 9.8

9.7 9.7

9.6 9.6

9.6 9.2

You are writing a query to list the 5 highest distinct scores. The Ranked field should be called ScoreRating. You have written the following code.

SELECT * FROM

(SELECT * More code here.

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

What code will achieve this goal?

1.SUM(*) OVER(ORDER BY Score DESC) as ScoreRating

2.RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

3.COUNT(*) OVER(ORDER BY Score DESC) as ScoreRating

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Correct Answer:

The correct answer will use #4:

SELECT * FROM

(SELECT *, DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating = 5

Explanation:

Choice #1 uses the aggregate SUM(), which will sum all the values. We don’t want the sum of the scores, so this choice is incorrect.

Choice #2 uses Rank(). It will provide the 5 highest scores, but we are looking for the 5 highest distinct scores, so this choice is also incorect.

Choice #3 uses the aggregate COUNT(), which will return the number 5. We don’t want this solution, so this choice is incorrect.

Choice #4 uses DENSE_RANK(). It will provide the 5 highest distinct scores, which is what we are trying to retrieve. This is the correct choice to complete the SQL statement above.

Country:

United States

Thanks for the knowledge!

Regards,

Bill Pepping

LikeLike

The correct answer is #4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

The DENSE_RANK() OVER() clause will select distinct scores. RANK() OVER() will retrieve duplicates in the result set.

SELECT ‘USA’ AS [COUNTRY];

LikeLike

The Correct Option is

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Country-India

LikeLike

Correct answer is No. 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

as it would give the five highest distinct amounts

(Sale, Nigeria)

LikeLike

Correct Answer is : option 4

Country: USA

LikeLike

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

LikeLike

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Posted to quickly (speeding towards Friday evening)

Gordon Kane

Allen TX

USA

LikeLike

The answer is #4

David

USA

LikeLike

The correct answer is #4

DENSE_RANK() OVER (ORDER BY Score DESC) as ScoreRating

Jitendra Gupta

Copenhagen,Denmark

LikeLike

the correct answer is number 4

tarek abosalem

Egypt

Assiut

LikeLike

Correct option is #4

Country – India

LikeLike

Answer: None of the above.

Answer 4 is very close to the answer and to correct that we should add with that (WHERE ScoreRating <= 5)

-Country: India

LikeLike

Answer 4, but with scorerating <=5 in where clause.

Since the current query will list all details in the table with scorerating =5.

Sddesh

USA

LikeLike

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

This is correct option.

India

-Dnyanesh

LikeLike

Answer is :

4.DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Vinay

Pune, India

LikeLike

Option 4 will yield the desired results.

Country: United States

LikeLike

Answer – 4 DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Divesh

INDIA

LikeLike

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Can be used to five highest distinct amounts with scorerating <=5 in where clause

USA

LikeLike

Answer : 4

1 -> Because * can not be used in Sum Function

2 -> Because Misses the rank numbers

3 -> count(*) will count for all rows..this result we are not expecting

Country -> USA

LikeLike

Option 4 is correct answer.

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

SELECT * FROM

(SELECT * , DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating.

FROM [Contestants]) AS ContestantFinal

WHERE ScoreRating <= 5

Thanks

Vivek Srivastava

Country:- INDIA

LikeLike

SELECT distinct * FROM

(SELECT *, Dense_Rank() OVER(ORDER BY Score DESC) as ScoreRating FROM [Rank]) AS ContestantFinal

WHERE ScoreRating <= 5

order by ScoreRating asc

This code will precisely provide the distinct score and score ranking

Rishi

USA

LikeLike

Hi Pinal Sir,

The Correct option for the above question is Option 4.

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Explanation:

We need to write a query to list the 5 highest distinct scores. The Ranked field should be called ScoreRating.

SELECT * FROM (SELECT * DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating FROM [Contestants]) AS ContestantFinal WHERE ScoreRating <= 5

The below Query just Gives that.

As, Explained by you DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence. Now what if we have similar value it repeats and then gives the next value no matter how many times it repeated the same Rank.

By the result and query the Option by far stands the correct Option.

Why Other Options are wrong:

Option 1 )SUM(*) OVER(ORDER BY Score DESC) as ScoreRating

Here we need to list the 5 highest distinct scores not the sum so ruled out.

Option 2)RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Here its a good Question I read in one of the comment it is written that this can be a good contender for correct option but how because here 9.6 is repeating if there are other option or number which repeats other than this how come Rank will return 5 highest distinct scores because on the first table it goes from 4 to 6 then 6 never less then 5 so we will have only 5 distinct values and comming to tell that Pinal sir has done a typing blunder, wrong how if we write ScoreRating = 5 the query will return only the records where ScoreRating equates to 5 it may have 1 or no record.

Here the table given by you has repeated 9.6 and we dont know how many times but will continue from where it left so last record we need to complete 5 distinct values is 9.2. Now if we write only ScoreRating <= 5 how we will get 5 th unique record because 5 is never less than 5. so it should be ScoreRating <= 5.

Hence this is completly wrong.

Option 3) COUNT(*) OVER(ORDER BY Score DESC) as ScoreRating

Here we require 5 highest distinct scores not count so ruled out.

So the correct option is 4

Dilip Kumar Jena

Country : INDIA

LikeLike

Hi Pinal Sir,

Correction :

The Correct option for the above question is Option 4.

4. DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Explanation:

We need to write a query to list the 5 highest distinct scores. The Ranked field should be called ScoreRating.

SELECT * FROM (SELECT * DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating FROM [Contestants]) AS ContestantFinal WHERE ScoreRating <= 5

The below Query just Gives that.

As, Explained by you DENSE_RANK( ) is very useful for finding the five highest distinct amounts, because it finds each amount and has no gap in its numbering sequence. Now what if we have similar value it repeats and then gives the next value no matter how many times it repeated the same Rank.

By the result and query the Option by far stands the correct Option.

Why Other Options are wrong:

Option 1 )SUM(*) OVER(ORDER BY Score DESC) as ScoreRating

Here we need to list the 5 highest distinct scores not the sum so ruled out.

Option 2)RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Here its a good Question I read in one of the comment it is written that this can be a good contender for correct option but how because here 9.6 is repeating if there are other option or number which repeats other than this how come Rank will return 5 highest distinct scores because on the first table it goes from 4 to 6 then 6 never less then 5 so we will have only 5 distinct values and comming to tell that Pinal sir has done a typing blunder, wrong how if we write ScoreRating = 5 the query will return only the records where ScoreRating equates to 5 it may have 1 or no record.

Here the table given by you has repeated 9.6 and we dont know how many times but will continue from where it left so last record we need to complete 5 distinct values is 9.2. Now if we write only ScoreRating < 5 how we will get 5 th unique record because 5 is never less than 5. so it should be ScoreRating <= 5.

Hence this is completly wrong.

Option 3) COUNT(*) OVER(ORDER BY Score DESC) as ScoreRating

Here we require 5 highest distinct scores not count so ruled out.

So the correct option is 4

Dilip Kumar Jena

Country : INDIA

LikeLike

4.

Dense_Rank returns distinct values

Dan

New Jersey USA

LikeLike

hi friend ‘s i have a question to all who belong to database pls give me ans if u know friend’s pls….. question is:- how we can retrieve four highest sallry from a table pls tell me query

LikeLike

select top 4 * from table order by salarycolumn desc

LikeLike

The correct answer is 4 DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating because it returns distinct values in case of a tie

Eric

USA

LikeLike

4)

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Location : London UK

LikeLike

Q 12) SQL SERVER – Tips from the SQL Joes 2 Pros Development Series – Ranking Functions – RANK( ), DENSE_RANK( ), and ROW_NUMBER( ) – Day 12 of 35A.) Because SUM and COUNT both expect the PARTITION BY argument in the OVER ( ) clause the code in (1) and (3) will both return ‘Incorrect syntax near the word ‘order ’’. Since RANK ( ) will skip numbers after a tie the records returned may not be distinct values making (2) incorrect too. Because DENSE_RANK assigns the rank based on distinct values (4) is the correct answer.

Winner from USA:

DebWinner from India:

Dayanand SinghI thank you all for participating here. The permanent record of this update is posted on facebook page.

LikeLike

Ans-4:

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Regards

Rajesh.M

LikeLike

Ans-4:

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Regards

Rajesh.M

From India

LikeLike

Correct answer is No. 4

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

because difference between rank() and dense_rank is dense_rank wont skip the number id there is tie between two numbers..

so correct answer is 4

India

LikeLike

Answer is #4:

DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

Thanks,

Wayne (USA)

LikeLike

Answer: DENSE_RANK( ) OVER(ORDER BY Score DESC) as ScoreRating

As the question here we are trying to get distinct highest 5 scores here with using the DENSE_RANK( ) we can get this ranking because we are getting all number as a rank without skipping any number with the tied value.

So this is the best answer for get all distinct highest five score.

LikeLike

Pingback: SQL SERVER – SQL Query Techniques For Microsoft SQL Server 2008 – Book Available for SQL Server Certification Journey to SQLAuthority

Thanks for the info. Really helped me a lot.

LikeLike

Pingback: SQL SERVER – Identity Fields – Contest Win Joes 2 Pros Combo (USD 198) – Day 2 of 5 « SQL Server Journey with SQL Authority

Pingback: SQL SERVER – Weekly Series – Memory Lane – #042 | Journey to SQL Authority with Pinal Dave