Comments on: SQL SERVER – Selecting Domain from Email Address

By: Rashmita

Rashmita — Tue, 05 Jun 2012 13:49:47 +0000

How to get sub string from a string:
input:-
1. /documents/subDocuments/test_123.txt (required result ‘test’)
2. /documents/subDocuments/test_def_45ddd.txt (required result ‘test_def’)

I want the sub string between last index of ‘/’ and last index of ‘_’

Thanks,
Rashmita

By: Amit Patel

Amit Patel — Tue, 28 Jun 2011 10:59:20 +0000

Hi Pinal,

we need add email validation check in this script because this script is working on @ but some invalid email entered in database table then this scriot is not working as expected.

I have modified it as below.

SELECT RIGHT(Email, LEN(Email) – CHARINDEX(‘@’, email)) Domain ,
COUNT(Email) EmailCount
FROM dbo.email
WHERE LEN(Email) > 0 and CHARINDEX(‘@’, email) > 0
GROUP BY RIGHT(Email, LEN(Email) – CHARINDEX(‘@’, email))
ORDER BY EmailCount DESC

By: SQLAuthority News – Monthly list of Puzzles and Solutions on SQLAuthority.com Journey to SQLAuthority

Tue, 28 Jun 2011 03:08:23 +0000

[...] SQL SERVER – Selecting Domain from Email Address [...]

By: Jeetendra

Jeetendra — Mon, 27 Jun 2011 19:45:59 +0000

Hi Pinal,
With minimal operation I think we can achieve this with below code and it can handle multiple @ scenario
Code:

SELECT
RIGHT(email,CHARINDEX(‘@’,REVERSE(email))-1) AS Domain,
COUNT(*) AS [No]
FROM @t
WHERE len(ISNULL(email,”)) > 1
GROUP BY RIGHT(email,CHARINDEX(‘@’,REVERSE(email))-1)

By: Krishna

Krishna — Mon, 20 Jun 2011 10:30:26 +0000

SELECT ISNULL(SUBSTRING(Email,CHARINDEX(‘@’,isnull(email,”)) + 1,LEN(Email) – CHARINDEX(‘@’,isnull(email,”))),”),COUNT(*) as overallcount
FROM @t
WHERE ISNULL(Email,”) ”
GROUP BY
ISNULL(SUBSTRING(Email,CHARINDEX(‘@’,isnull(email,”)) + 1,LEN(Email) – CHARINDEX(‘@’,isnull(email,”))),”)
ORDER BY
overallcount DESC

By: Vinay Kumar

Vinay Kumar — Mon, 20 Jun 2011 06:17:29 +0000

select SUBSTRING(EmailAddress,PATINDEX(‘%@%’,EmailAddress)+1,100),COUNT(1) from Person.Contact
GROUP BY SUBSTRING(EmailAddress,PATINDEX(‘%@%’,EmailAddress)+1,100)
ORDER BY 2 DESC

Try This query.

By: James

James — Sat, 18 Jun 2011 16:53:46 +0000

I have something like that. Which was separating the username and domain parts of the address. I am using it in a computed column. See below

(left([EMailAddress],charindex(‘@’,[EMailAddress])-(1)))
and
(right([EMailAddress],len([EMailAddress])-charindex(‘@’,[EMailAddress])))

However I was not able to solve a problem with it crashing when reading the table with invalid email’s which did not contain an @ symbol.

By: Jason

Jason — Sat, 18 Jun 2011 15:28:46 +0000

I would also guess that using “WHERE LEN(email) > 0″ is not SARGable, and not using an index if it’s available.

By: Jason

Jason — Sat, 18 Jun 2011 14:54:59 +0000

According to RFC’s 5322 and 5321, a quoted string can be used to allow invalid characters… such that “pinal@home”@sqlauthority.com would be a valid email address. However, it’s rare to see a quoted string used for email.

By: Manish Sharma

Manish Sharma — Sat, 18 Jun 2011 12:43:09 +0000

Hi Pinal,

Recently I have used the same method for one of my shopping cart project. I was asked to show approx 50 characters for a product description followed by 4 dots and it should not cut last word. So I used the same method. here is my query

SELECT productID, productName, LEFT(productDescription, CHARINDEX(” ”, productDescription, 50))+”….” as productDescription, ….
FROM tbl_Products

Thanks

By: vishaldobariya

vishaldobariya — Sat, 18 Jun 2011 10:05:19 +0000

good one

By: jatinkacha

jatinkacha — Sat, 18 Jun 2011 06:03:55 +0000

Thanks for share. Good script

By: Ashok

Ashok — Sat, 18 Jun 2011 05:10:49 +0000

Hi;
Mr. Pinaldave

It’s Excellent and very much use full

Thanks a lot

By: ashishrao

ashishrao — Sat, 18 Jun 2011 05:04:04 +0000

select substring(emailid,charindex(‘@’,emailid)+1,len(emailid)) as Domain,count(emailid) as EmailCount
from email
where len(emailid)>0
group by substring(emailid,charindex(‘@’,emailid)+1,len(emailid))
order by Emailcount desc

By: Aneel Mehta

Aneel Mehta — Sat, 18 Jun 2011 05:02:58 +0000

Cant we use “substring” instead if “right” here ?
like

select substring(Email , CHARINDEX(‘@’, Email )+ 1,len(Email)) Domain ,
count(Email ) EmailCount
from dbo.data
where len(isnull(Email ,”)) > 0
group by substring(Email , CHARINDEX(‘@’, Email )+ 1,len(Email))
order by Emailcount desc

By: praveen

praveen — Sat, 18 Jun 2011 05:02:41 +0000

Thanks sir, good articles to learn

By: haile

haile — Sat, 18 Jun 2011 04:28:18 +0000

you can also use the substring function to get the domain part of the email
substring(email, charindex(‘@’, email) + 1, len(email))

By: Suman Balguri

Suman Balguri — Sat, 18 Jun 2011 02:51:31 +0000

SELECT RIGHT(Email, CHARINDEX(‘@’, REVERSE(email))-1) as Domain ,
COUNT(Email) as EmailCount
FROM dbo.email
WHERE LEN(Email) > 0
GROUP BY RIGHT(Email, CHARINDEX(‘@’, REVERSE(email))-1)
ORDER BY EmailCount DESC