Charge ,Payment, Month, AverageCharge,AveragePayment
300 100 1 300 100
500 150 2 400 125
400 200 3 300 116.6666667
200 50 4 150 62.5
800 300 5 200 70
450 100 6 208.3333333 66.66666667
600 150 7 150 35.71428571

just like we do in excel sheet.

DECLARE @RangeStartDate DATETIME,
@RangeEndDate DATETIME;

SET @RangeStartDate = ’2008-03-01′;
–SELECT @RangeStartDate;
SET @RangeEndDate = ’2008-05-01′;
–SELECT @RangeEndDate;

CREATE PROCEDURE SP_GETMONDAYINAMONTH
@FRISTDAYOFMONTH DATETIME
AS
BEGIN
DECLARE @NOOFDAYS INT
SET @NOOFDAYS = (select datepart(dd,dateadd(dd,-1,dateadd(mm,1,cast(cast(year(@FRISTDAYOFMONTH) as varchar)+’-'+cast(month(@FRISTDAYOFMONTH) as varchar)+’-01′ as datetime)))))
SELECT DISTINCT DATEADD(d, NUMBER, @FRISTDAYOFMONTH) AS DATE ,
CASE DATEPART(dw, DATEADD(d, NUMBER, @FRISTDAYOFMONTH))
WHEN 2 THEN ‘MONDAY’
ELSE ‘WORKING DAY’
END AS [DAY OF WEAK]
FROM MASTER..SPT_VALUES
WHERE NUMBER BETWEEN 0 AND @NOOFDAYS AND (DATEPART(dw, DATEADD(d, NUMBER, @FRISTDAYOFMONTH)) = 2)
ORDER BY DATEADD(d, number, @FRISTDAYOFMONTH)
END

EXEC SP_GETMONDAYINAMONTH ’2010-04-01′

When you execute this procedure you have to pass the frist day of month in which month you want to calculate the no of Monday

EXEC SP_MONTH 24

This procedure can calculate nos of month whatever u want

Change the last SELECT statement of query in article as below:

SELECT FromDate AS Date, Dayname
FROM CTE
WHERE DayName IN (‘Monday’)

Although this querywould return all mondays of current year but it can be modified to retreive records only for a month.

Regards,
Pinal Dave

can anybody give me the query for retriving only monday of every month

http://www.simple-talk.com/sql/t-sql-programming/sql-server-2005-common-table-expressions/

Thanks
Ebin

I have table named Holidaylist .
with columns Hid,Hname,date,month,year.I want to retrieve
secondworking day of the current month that includes
saturday and sunday as holidays

Provide me the solution

thankx in advance

SET
@weekDay = DATEPART(dw,’2010′)

SELECT
@daySaturday = DATEADD(dd,7-@weekDay,’2010′),
@daySunday = DATEADD(dd,7-@weekDay+1,’2010′)

SELECT
DATEADD(dd,(number-1)*7,@daySaturday) ‘SATURDAY’,
DATEADD(dd,(number-1)*7,@daySunday) ‘SATURDAY’
FROM
dbo.tally
WHERE
number < = 53 AND
DATEADD(dd,(number-1)*7,@daySunday) <= '01/01/2011'

it is very helpful to query

i have another problem

DECLARE @date DATETIME;
SET @date = ’2006-10-15′;
Select datename(MONTH,DateAdd(mm,-12,@date)),datename(year,DateAdd(mm,-12,@date)) union all
select datename(MONTH,DateAdd(mm,-11,@date)),datename(year,DateAdd(mm,-11,@date))

union all
select datename(MONTH,DateAdd(mm,-10,@date)),datename(year,DateAdd(mm,-10,@date)) union all
select datename(MONTH,DateAdd(mm,-09,@date)),datename(year,DateAdd(mm,-09,@date)) union all
select datename(MONTH,DateAdd(mm,-08,@date)),datename(year,DateAdd(mm,-08,@date)) union all
select datename(MONTH,DateAdd(mm,-07,@date)),datename(year,DateAdd(mm,-07,@date)) union all
select datename(MONTH,DateAdd(mm,-06,@date)),datename(year,DateAdd(mm,-06,@date)) union all
select datename(MONTH,DateAdd(mm,-05,@date)),datename(year,DateAdd(mm,-05,@date)) union all
select datename(MONTH,DateAdd(mm,-04,@date)),datename(year,DateAdd(mm,-04,@date)) union all
select datename(MONTH,DateAdd(mm,-03,@date)),datename(year,DateAdd(mm,-03,@date)) union all
select datename(MONTH,DateAdd(mm,-02,@date)),datename(year,DateAdd(mm,-02,@date)) union all
select datename(MONTH,DateAdd(mm,-01,@date)),datename(year,DateAdd(mm,-01,@date))
This is the query that retrieves data for past one year with month .
But if we want to retrieve more than past 24 months and more its not easier to query.

Is there any other solution for this comments

can anybody give me the query for retriving previous year and month details.

-Shan

MAXRECURSION query hint in common table expression is used to recursively execute the last statement in CTE that is joined using UNION, UNION ALL, INTERSECT or EXCEPT.
Here The number 370 is used to keep recursion under the number of days in a year (365).

Regards,
Pinal Dave

It wont work in non-English servers
So better usage is

SELECT FromDate AS Date, Dayname
FROM CTE
WHERE datepart(weekday,Fromdate) in (7,1)

Can some one explain me how
OPTION (MAXRECURSION 370); works?, Also how do you arrive at this number – 370. I am trying to understand from BoL but still not able to get it. Any help in this regard with be great.

When talk comes to date script, I would also like to share one of the script to find out first and last Friday of the years. starting from Jan-06 to Dec-2020. Actually I have got this request from one of the forums and created this very quickly.

WITH CTE AS
(
select CONVERT(datetime,’01/06/2006′) as dt, datename(dw,CONVERT(datetime,’01/06/2006′)) as dy,datename(mm,CONVERT(datetime,’01/06/2006′)) as mn, YEAR(CONVERT(datetime,’01/06/2006′)) AS yr
union all
select s.dt+7 as dts,datename(dw,dt+7) as dy ,datename(mm,dt+7) as dy, YEAR(dt+7) AS yr
from cte s
where s.dt<CONVERT(datetime,'12/31/2020')
)
select MAX(dt) as dt,dy,mn,yr from cte
group by dy,mn,yr
UNION
select MIN(dt) as dt,dy,mn,yr from cte
group by dy,mn,yr
ORDER BY dt
OPTION (MaxRecursion 0)