IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(‘Format’) AND type in (N’FN’, N’IF’, N’TF’, N’FS’, N’FT’)) DROP FUNCTION Format
GO

Create Function Format(@Date DateTime,@Fmt Char(30)) Returns Char(30) as
Begin
– @Fmt can be dd/mm/yyyy, yyyy-mm-dd, dd-mmm-yyyy, dd/mm/yy, ddd dd/mm/yyyy, dddd dd-mmmm-yyyy, dddd mmmm dd, yyyy etc
– @Fmt can also include HH:mm, HH:mm:ss, HH:mm:ss:ttt formats – always in 24 hour format at this stage
– FD is First Day-of-month, LD is Last Day-of-month, FYYY is financial year, FM is month in financial year, MN is minutes of hour

Select @Fmt=Replace(@Fmt,’FD’,’01′);
Select @Fmt=Replace(@Fmt,’LD’,right(rtrim(cast(100+Day(DateAdd(Day,-1,DateAdd(Month,1,DateAdd(Day,1-Day(@Date),@Date)))) as Char(3))),2));
Select @Fmt=Replace(@Fmt,’FM’,Right(RTrim(Cast(100+Case When Month(@Date)>6 then Month(@Date)-6 else Month(@Date)+6 End as char(3))),2));
Select @Fmt=Replace(@Fmt,’FYYY’,Right(RTrim(Cast(10000+Case When Month(@Date)>6 then Year(@Date) else Year(@Date)-1 End as char(5))),4));
Select @Fmt=Replace(@Fmt,’FY’,Right(RTrim(Cast(10000+Case When Month(@Date)>6 then Year(@Date) else Year(@Date)-1 End as char(5))),2));
Select @Fmt=Replace(@Fmt,’HH’,left(Cast(Cast(@Date as Time) as char(10)),2));
Select @Fmt=Replace(@Fmt,’:MM’,SubString(Cast(Cast(@Date as Time) as char(12)),3,3));
Select @Fmt=Replace(@Fmt,’MN’,SubString(Cast(Cast(@Date as Time) as char(12)),4,2));
Select @Fmt=Replace(@Fmt,’SS’,SubString(Cast(Cast(@Date as Time) as char(12)),7,2));
Select @Fmt=Replace(@Fmt,’TTT’,SubString(Cast(Cast(@Date as Time) as char(12)),10,3));
Select @Fmt=Replace(@Fmt,’TT’,SubString(Cast(Cast(@Date as Time) as char(12)),10,2));
Select @Fmt=Replace(@Fmt,’DDDD’,DATENAME(dw,@Date));
Select @Fmt=Replace(@Fmt,’DDD’,Left(DATENAME(dw,@Date),3));
Select @Fmt=Replace(@Fmt,’DD’,Right(Rtrim(cast(100+day(@Date) as Char(3))),2));
Select @Fmt=Replace(@Fmt,’MMMM’,DATENAME(month,@Date));
Select @Fmt=Replace(@Fmt,’MMM’,Left(DATENAME(month,@Date),3));
Select @Fmt=Replace(@Fmt,’MM’,Right(Rtrim(cast(100+month(@Date) as Char(3))),2));
Select @Fmt=Replace(@Fmt,’YYYY’,Right(Rtrim(cast(10000+Year(@Date) as Char(5))),4));
Select @Fmt=Replace(@Fmt,’YY’,Right(Rtrim(cast(10000+Year(@Date) as Char(6))),2));
Return ltrim(rtrim(@Fmt));
End
GO
SELECT getdate(),
dbo.Format(getDate(),’ddd dd-mmm-yyyy HH:mm:ss.ttt’),
dbo.Format(getDate(),’HH:mn’),
dbo.Format(getDate(),’fd-mmm-yyyy’),
dbo.Format(getDate(),’LD-mmm-yyyy’),
dbo.Format(GetDate(),’FYYY-FM’);

Result

ID TimeDiff
1 03:44:30.0000000

CREATE FUNCTION dbo.TimeDiff (@STARTDATE datetime,@ENDDATE datetime)

RETURNS @TIMEDIFF TABLE (ID int IDENTITY(1, 1) NOT NULL, TimeDiff TIME NULL) AS

BEGIN

DECLARE @24DATE DATETIME
SET @24DATE = ’23:59:59.000′

IF (@STARTDATE > @ENDDATE)
INSERT INTO @TIMEDIFF
SELECT DATEADD (SECOND,1, CONVERT(TIME(0), ( @24DATE -(@ENDDATE – @STARTDATE))))
ELSE
INSERT INTO @TIMEDIFF
SELECT CONVERT(TIME(0), ( (@ENDDATE – @STARTDATE)))

RETURN
END

GO

output =’2013-01-15 11:00:00.000′
Please help.

Can any one help me,

i have two columns of one table as @ABC as DateTime and @xyz as DateTime – Datatype

i want to subtract only time and i am trying like this

for ABC = 21/02/2012 6:10:00 PM and XYZ = 01/01/2001 12:00:00 AM -> 1st Row

CONVERT(varchar(10), dbo.checkingtime.ABC – dbo.checkingtime.XYZ, 108)

and i am getting the result as 18:10 but i want the result as 05:50 in Hours and Minutes only

is it possible ? ? ?

Awaiting from the HelpingNature People

Result will be : 08/23/12 4:16 PM

I have :

where TIME_STAMP >= cast(floor(cast(GETDATE() as float)) as datetime)
and LEFT(CONVERT(TIME(2),TIME_STAMP) ,5) > ’10:15′

which works fine in SQL Server 10, but our prod database is SQL Server 9.

Any ideas on an efficient way to do this?

SELECT RIGHT(LTRIM(RIGHT(Convert(varchar,GETDATE(),100),8)),8) AS ONLY_TIME

declare @startTime varchar(10),@endTime varchar(10)
select @startTime =’10:00 AM’, @endtime =’7:30 PM’
select convert(varchar(10),@endtime-cast(@starttime as datetime),108)

and as an added bonus that converting a date/time value to VarChar does not offer, you can still add this result with time…(above +10 mins below)

SELECT
LEFT(DATEADD(mi, 10, (CONVERT(TIME(0),GETDATE()))),5) AS [HourMinuteSecond]
GO
/*
HourMinuteSecond
————————
10:58
*/

Daniel S. Gurrola II
No Acronyms, Affiliations, Certifications or other Nausea – it’s just…me.

Values are 10:00 AM and 7:30 PM
I need to find the difference between these two times. How to do that? I tried the above said query but that gives only the difference in hours. I need the time also. In this case I need 09:30 as result.

Please help. Thanks

Once again you have come through with the goods. You are the man.

i typed in SQL server 2005,
SELECT CONVERT(VARCHAR(10),GETDATE(),101) as Date

Any idea????