CID FNAME MIN MAX COM
A OP1 0 23 5
A OP1 24 35 2
A OP1 36 99 1

A OP2 0 23 5
A OP2 24 35 2
A OP2 36 99 0

A OP3 0 23 5
A OP3 24 35 2
A OP3 36 99 1

B OP1 0 23 9
B OP1 24 99 2

B OP2 0 23 9
B OP2 24 99 2

B OP3 0 23 7
B OP3 24 35 3
B OP3 36 99 1

The expected duplicate results i need are:
A OP1
A OP3
B OP1
B OP2

SELECT SUM (row_count) AS total_number_of_rows
FROM sys.dm_db_partition_stats
WHERE object_id=OBJECT_ID(‘HumanResources.Employee’) AND (index_id=0 or index_id=1);

That query handles multiple partitions, and handles the schema name correctly. It will show the results for a heap, or a table with a primary key. This has been mentioned in the comments a few times, and you say “thanks”, but it would help if you could update the article itself! The code in the article is not quite correct.

David Walker

Using your above query, it gives duplicate table names if the tables are partitioned.

How about the below one..

SELECT
OBJECT_NAME(P.[object_id]) AS [Table Name]
,SUM(rows) AS [No. of rows]

FROM sys.partitions AS P
INNER JOIN sys.tables AS T
ON T.[object_id] = P.[object_id]

WHERE index_id IN (0,1) AND T.[type] = ‘U’
GROUP BY P.[object_id]
ORDER BY 2 DESC

Thank you..

Thank you

Your query does not take account of the Schema name. There can be tables having same name but different schema in a database. Also if a table is partitioned, you want to get one row of result 1.e; sum of rows in different partitions. So I have a modified query that I use.

select sc.name +’.'+ ta.name
,sum(pa.rows) — Approximate value, oh well
from sys.tables ta
inner join sys.partitions pa
on pa.object_id = ta.object_id
inner join sys.schemas sc
on ta.schema_id = sc.schema_id
where ta.is_ms_shipped = 0 AND pa.index_id IN (1,0)
group by sc.name,ta.name
ORDER BY sum(pa.rows) DESC

DBCC updateusage(dbname)

for correct result

See this
http://beyondrelational.com/blogs/madhivanan/archive/2007/11/02/different-ways-to-count-rows-from-a-table.aspx

Update table
Set Grade=NULL