That behavior is in SQL Server 2008, not 2005.

INSERT INTO PersonColors (Name,ColorCode)
VALUES (‘Tom’,'Red’),(‘Tom’,'Blue’),(‘Tom’,'Green’),(‘Tom’,'Brown’),
(‘Mike’,'Red’),(‘Mike’,'Blue’),
(‘James’,'Green’),(‘James’,'Brown’),
(‘Joe’,'Red’),(‘Joe’,'Blue’),(‘Joe’,'Green’),
(‘Matt’,'Brown’)
GO

This way it gives error

Msg 102, Level 15, State 1, Line 2
Incorrect syntax near ‘,’.

Thanks
Rahul

What exactly is the problem. Can you show a statement that generates an error?

To insert i used your way

CREATE TABLE PersonColors (Name VARCHAR(100), ColorCode VARCHAR(100))
GO
INSERT INTO PersonColors ([Name],ColorCode)
SELECT ‘Tom’,'Blue’
UNION ALL
SELECT ‘Tom’,'Green’
UNION ALL
SELECT ‘Tom’,'Brown’
UNION ALL
SELECT’Mike’,'Red’
UNION ALL
SELECT ‘Mike’,'Blue’
UNION ALL
SELECT’James’,'Green’
UNION ALL
SELECT’James’,'Brown’
UNION ALL
SELECT ‘Joe’,'Red’
UNION ALL
SELECT ‘Joe’,'Blue’
UNION ALL
SELECT’Joe’,'Green’
UNION ALL
SELECT ‘Matt’,'Brown’
GO
SELECT *
FROM PersonColors
GO
/*Create Second Table SelectedColors*/
CREATE TABLE SelectedColors (ColorCode VARCHAR(100))
GO
INSERT INTO SelectedColors (ColorCode)
SELECT ‘Red’
UNION ALL
SELECT ‘Blue’
UNION ALL .
SELECT ‘Green’
SELECT *
FROM PersonColors
SELECT *
FROM SelectedColors
GO

You are correct, we will get TOM in that case.

But please read post, there is already note like:

UPDATE: Following solution is written with assumption that in SelectedColors table Name and ColorCode are Primary Key. This requirement was not specified in original question.

Thanks,

Tejas

SELECT Name

FROM PersonColors pc

INNER JOIN SelectedColors sc ON sc.ColorCode = pc.ColorCode

GROUP BY pc.Name

HAVING COUNT(distinct pc.ColorCode) >= (SELECT COUNT(distinct ColorCode) FROM SelectedColors)

There’s always room for improvement. :)

Thanx for your contribution.

Sorry, I missed that. But assuming that there ia no need to have the greater or equal comparison here: COUNT(pc.ColorCode) >= (SELECT COUNT(ColorCode) FROM SelectedColors). Assuming that “hidden” key (:-p) we can use just the equal comparison like this: COUNT(pc.ColorCode) = (SELECT COUNT(ColorCode) FROM SelectedColors).

Just a tinny little tune up…

Cheers,
Leandro Nunes

“Following solution is written with assumption that in SelectedColors table Name and ColorCode are Primary Key. This requirement was not specified in original question.”

pinaldave sorry to say but your answer is not correct…

Take a look:

If you run this:

delete from personcolors where name=’Tom’ and ColorCode=’Red’;
insert into personcolors values(‘Tom’, ‘Blue’);

The person Tom has three colors: green, brown and blue. Right now this user should not appear on the result set because he’s missing red color. Guess what? Running your query he is still shown on the result set (because he has two blue lines) :(

For this query to work it should be written like this:

SELECT Name
FROM PersonColors pc
INNER JOIN SelectedColors sc ON sc.ColorCode = pc.ColorCode
GROUP BY pc.Name
HAVING COUNT(distinct pc.ColorCode) = (SELECT COUNT(ColorCode) FROM SelectedColors)

The only difference is that i’m using COUNT(distinct pc.ColorCode).

My first solution was pretty much like yours, but after awhile I relized that it was not correct :-D

I’m a great fan of your blog
Greetings from Portugal ;-)

Leandro Nunes

) Q

select name from PersonColors
where colorcode in(select colorcode from SelectedColors)
group by name

is it correct please reply…

i got same answer, please give me some more this type of question so that i can improve my knowledge.

That is an interesting puzzle, I’ve never had that sort of problem before “in real life” but it was fun.

I’m a newer reader to your blog, but do you have additional T-SQL puzzles like that (or in general)?

Thank you!

I just looked into the site and recognized the style of insertion into the table like this

INSERT INTO PersonColors (Name,ColorCode)
VALUES (‘Tom’,‘Red’),(‘Tom’,‘Blue’),(‘Tom’,‘Green’),(‘Tom’,‘Brown’),
(‘Mike’,‘Red’),(‘Mike’,‘Blue’),
(‘James’,‘Green’),(‘James’,‘Brown’),
(‘Joe’,‘Red’),(‘Joe’,‘Blue’),(‘Joe’,‘Green’),
(‘Matt’,‘Brown’)

As all in my past I used to insert only one record at a time. And I was amazed at looking this that we can insert multiple records with in a single insert statement. But sadly, my it failed in my machine. The more interesting is I accidentally inserted a duplicate record into the SelectedColors table with the value ‘Red’ two times. I tried to delete only the duplicate. But cannot do that without deleting the ‘Red’ items. I tried in the GUI grid also to delete only one record. That failed to do this. Is there any work around for this rather than deleting all the records.