Thank u for the amazing SQL resource.. i am a big fan of u sir..

Regards
kirtika

Thanks
Regards,
Sneha

Thanks for everything. I appreciate your effort to provide us everything simple and accurate.
I have two questions about cursor.
Mostly we are asked to avoid cursors, is there any situation when we must have to use a cursor? and what is the most important benifit using a cursor?

I am Deepthi..This is really a very informative site..It gives good knowledge of sql server…

I have a small doubt..Can you just tell me whats the difference between a view and user defined function..in which situations each of them will be used…

really it is a good site to all type of exp person could u send me some of the important questions for my further interview

Looking forward for your replay sir

thanking you
nikesh

IN the question for difference between stored procedure and functions. Do user defined functions compile and has a plan. if not then is it wise to say that, we can use functions also in places where the SQL engine does not need to store the plan and where a logic needs to be called 1000 times but there is no need to store the plan and take procedure cache space.

select t1.Eno,t1.Ename,t2.DeptNo
from EMPP as t1 innor join Dept as t2
on t1.Eno=t2.DNo

i am working with sqlserver2008
i got one problem
in joins

select *from EMPP
select *from Dept
——————————-
select EMPP.Eno,EMPP.Ename,Dept.DeptNo
from EMPP innor join Dept
on EMPP.Eno=Dept.DNo
—————————————————

Msg 4104, Level 16, State 1, Line 4
The multi-part identifier “EMPP.Eno” could not be bound.
Msg 4104, Level 16, State 1, Line 2
The multi-part identifier “EMPP.Eno” could not be bound.
Msg 4104, Level 16, State 1, Line 2
The multi-part identifier “EMPP.Ename” could not be bound.

Plz Help me, how to avoid this Error

I am your fan,Great work !!

Nilay Shah

create table #emp_temp
(
empid int,
subid int,
name varchar(20)
)

insert into #emp_temp
select 1,2,’adam’
union all
select 2,3,’bob’
union all
select 3,null,’candy’
union all
select 4,2,’doug’
union all
select 5,3,’earl’
union all
select 6,5,’fran’

select m.name Manager, s.name Subordinate
from #emp_temp m join #emp_temp s on s.subid=m.empid

WITH
Employees(empid, empname)
AS
(
SELECT 1, ‘adam’ UNION ALL
SELECT 2, ‘bob’ UNION ALL
SELECT 3, ‘candy’ UNION ALL
SELECT 4, ‘doug’ UNION ALL
SELECT 5, ‘earl’ UNION ALL
SELECT 6, ‘fran’
),
Subordinates(empid, sub_empid)
AS
(
SELECT 3, 2 UNION ALL
SELECT 3, 5 UNION ALL
SELECT 2, 1 UNION ALL
SELECT 2, 4 UNION ALL
SELECT 5, 6
)
SELECT
Emp_1.empname Manager,
Emp_2.empname Subordinate
FROM
Employees Emp_1,
Employees Emp_2,
Subordinates
WHERE
Emp_1.empid = Subordinates.empid
AND Emp_2.empid = Subordinates.sub_empid
ORDER BY
Emp_1.empname;