with CI AS (SELECT t.name,t.object_id,count(t.object_id) CI
FROM sys.indexes i inner join sys.tables t
on i.object_id = t.object_id
where t.type like ‘u’ and i.type_desc like ‘CLUSTERED’
group by t.name,t.object_id)
, NCI AS (SELECT t.name,t.object_id,count(t.object_id) NCI
FROM sys.indexes i inner join sys.tables t
on i.object_id = t.object_id
where t.type like ‘u’ and i.type_desc like ‘NONCLUSTERED’
group by t.name,t.object_id)
SELECT t.name,CI.CI,NCI.NCI,CI.CI + NCI.NCI TI
FROM sys.tables t inner join CI on CI.Object_id = t.object_id
inner join NCI on NCI.object_id = t.object_id
where t.type like ‘u’
order by TI desc

select t.name,count(i.index_id)
from sys.tables t inner join sys.indexes i on i.object_id = t.object_id
where i.type_desc in (‘CLUSTERED’,'NONCLUSTERED’)
group by t.name
order by 2 desc

I have to use table valued function twice in a same SELECT statement. So will l SQL retrieve data once or twice if the same function is used in two places?

If it retrieves twice will CET resolves it?
Thank you!

in this table id is the primarykey, i have a column called parentkey in this table, in this table records having parent-child relation

ex:- id Name PrentKey
1 test -3
2 test2 1

-3 is the parentkey here, 1 vlaue in the parentkey is the child of id 1,

here if i give child id key i want to get the all names of that child n parent fileds. example :- if i give ’2′ as input parament i want out put like below :

ID Path
1-2 test-test2

for this i m trying below query :-

WITH Emp_CTE ( id,ParentKey,ContentType,Path,Level)
AS (

SELECT id , ParentKey,ContentType,
CONVERT(varchar(1000),DocName) , 0 Level
FROM test S
WHERE id = 2

UNION ALL

SELECT SS.ID , SS.ParentKey,SS.ContentType,
CONVERT(varchar(1000), ISNULL(SS.DocName,”)+’|'+ISNULL(Path,”) )
,Level +1
FROM test SS
INNER JOIN Emp_CTE ecte ON ecte.ParentKey = SS.ID
)

SELECT CASE WHEN Path IS NULL THEN ” ELSE ‘|’ END + Path as folderpath,
* FROM Emp_CTE WHERE ContentType = ‘Folder’ AND ParentKey = -3

ablove query is giving output as below :-

ID Path
1 test|test2

here i want to display all the IDs , but i am able to append all the docnames from table , how to achive id’s like 1-2?

PRINT’List all Wiz DBs; Lar_Names, DB_Name, Types, CensusYear’

SELECT
NodeName,
NodeId,
LEN(NodePath) – LEN(REPLACE(NodePath, ‘.’, ”)) AS DCount,
NodePath,
Left(objectstore..LAR_Tree.NodeName,40)AS Lar_Name,
Left(objectstore..LAR_Items.DatabaseName,10) AS Database_Name,
objectstore..LAR_Items.LARType, objectstore..LAR_Items.CensusYear
INTO #tbl_Temp
FROM objectstore..LAR_Tree
Left JOIN objectstore..LAR_Items
ON objectstore..LAR_Tree.NodeId = objectstore..LAR_Items.ItemId
ORDER BY Database_Name

SELECT
NodePath,
CensusYear,
Database_Name,
(CASE
WHEN DCount = 3 THEN (CASE
WHEN LEN(NodePath) = 5 THEN
(SELECT NodeName
FROM objectstore..LAR_Tree
WHERE NodeId = CAST(SUBSTRING(NodePath,4,1)AS INT))
WHEN LEN(NodePath) = 6 THEN
(SELECT NodeName
FROM objectstore..LAR_Tree
WHERE NodeId = CAST(SUBSTRING(NodePath,4,2)AS INT))
WHEN LEN(NodePath) = 7 THEN
(SELECT NodeName
FROM objectstore..LAR_Tree
WHERE NodeId = CAST(SUBSTRING(NodePath,4,3)AS INT))
WHEN LEN(NodePath) = 8 THEN
(SELECT NodeName
FROM objectstore..LAR_Tree
WHERE NodeId = CAST(SUBSTRING(NodePath,4,4)AS INT))
END)

END) AS GUI_Path
FROM #tbl_Temp

Select DocNUm
,left(DocEntry,len(DocEntry)-1)DocEntry
from(
Select distinct DocNum
,(
Select Cast(DocEntry as varchar)+’,’ from Doc B where A.DocNum=B.DocNum for xml path(”)
)DocEntry from Doc A
)C

I have a requirment where the hierarchy structure is defined in the below way.

QA Sponsor
QA Fund 1
QA Fund 2
QA Fund 3
QA Fund 4

QA Fund 5
QA Fund 1

Below is the proposed db design.

Child Id Level Parent
QA Sponsor 1
QA Fund1 2 QA Sponsor
QA Fund 2 3 QA Fund1
QA Fund 3 4 QA Fund 2
QA Fund 4 5 QA Fund 3

QA Fund 5 2 QA Sponsor
QA Fund1 2 QA Fund 5

I have written the below CTE code and which provide me the o/p which is mentioned after the code.

;WITH cte AS
(
SELECT CAST(” + Name AS VARCHAR(100)) as ‘Name’, ID
FROM dbo.RELATION
WHERE PARENT_ID =”

UNION ALL

SELECT CAST(cte.Name + ‘—>’ + t.Name AS VARCHAR(100)), t.ID
FROM dbo.RELATION t
INNER JOIN cte ON t.parent_id = cte.id
)
SELECT Name FROM cte
ORDER BY ID

O/P
—

QA SPONSOR
QA SPONSOR—>QA FUND1
QA SPONSOR—>QA FUND1—>QA FUND2
QA SPONSOR—>QA FUND1—>QA FUND2—>QA FUND3
QA SPONSOR—>QA FUND1—>QA FUND2—>QA FUND3—>QA FUND4
QA SPONSOR—>QA FUND5
QA SPONSOR—>QA FUND5—>QA FUND1

Everything looks ok however but since QA Fund 1 has fund 2,3,and 4 inside it. there should be one more line i.e. QA SPONSOR—>QA FUND5—>QA FUND1—>QA FUND2—>QA FUND3—>QA FUND4

I am stuck and not sure what should i do to get around this problem. Please help me in this.

GO

Jogo,Casa,Coluna1,Coluna2,Coluna3
255,1,C1:,NULL,NULL
255,2,A1:,B1:,C1:
255,3,A1:,NULL,NULL
255,4,A1:,C1:,NULL
255,5,A1:,NULL,NULL
255,6,C1:,B1:,NULL
255,7,A1:,C1:,NULL
255,8,A1:,NULL,NULL
255,9,A1:,NULL,NULL
255,10,A1:,B1:,C1:
255,11,A1:,NULL,NULL
255,12,C1:,NULL,NULL
255,13,A1:,NULL,NULL
255,14,A1:,C1:,NULL
255,15,A1:,NULL,NULL

Jogo Casa Coluna1 Coluna2 Coluna3
255 1 C1: NULL NULL
255 2 A1: B1: C1:
255 3 A1: NULL NULL
255 4 A1: C1: NULL
255 5 A1: NULL NULL
255 6 C1: B1: NULL
255 7 A1: C1: NULL
255 8 A1: NULL NULL
255 9 A1: NULL NULL
255 10 A1: B1: C1:
255 11 A1: NULL NULL
255 12 C1: NULL NULL
255 13 A1: NULL NULL
255 14 A1: C1: NULL
255 15 A1: NULL NULL

Using SQL generate all possible between the columns 1, 2 and 3.
This is an example of practical utilization of query recurssive applied to sports lottery (loteca).
The result should be 144 bet as element 15 in the column should be based on CASA.

FIRST LINE == B1:A1:A1:A1:A1:B1:A1:A1:A1:A1:A1:B1:A1:A1:A1:
LAST LINE == B1:B1:A1:B1:A1:CA1::B1:A1:A1:B1:A1:B1:A1:B1:A1:

I have two tables like below. This is something like parent child relationship. Table 1 have relation details and Table 2 have ids for each row.

Table 1

Col1 Col2 col3
A A1 A1.1
B B1 B1.1
B B1 B1.2
C C1 C1.1
C C2 C2.1
C C3 C3.1

Table 2
Col1 KEY
A 1
A1 2
A1.1 3
B 4
B1 5
B1.1 6
B1.2 7
C 8
C1 9
C1.1 10
C2 11
C2.1 12
C3 13
C3.1 14

Extecpted output

CHILD PARENT

14 13
12 11
10 9
13 8
11 8
9 8
7 5
6 5
5 4
3 2
2 1
NULL 1

how to get it using quyer

WITH Parts (AssemblyID, ComponentID, PerAssemblyQty, EndDate, ComponentLevel) AS
(
SELECT b.ProductAssemblyID, b.ComponentID, b.PerAssemblyQty, b.EndDate, 0 AS ComponentLevel
FROM Production.BillOfMaterials AS b
WHERE b.ProductAssemblyID = 800 AND b.EndDate IS NULL
UNION ALL
SELECT bom.ProductAssemblyID, bom.ComponentID, p.PerAssemblyQty, bom.EndDate, ComponentLevel + 1
FROM Production.BillOfMaterials AS bom
INNER JOIN Parts AS p
ON bom.ProductAssemblyID = p.ComponentID AND bom.EndDate IS NULL
)
SELECT AssemblyID, ComponentID, Name, PerAssemblyQty, EndDate,
ComponentLevel
FROM Parts AS p
INNER JOIN Production.Product AS pr
ON p.ComponentID = pr.ProductID
ORDER BY ComponentLevel, AssemblyID, ComponentID;
GO

Thank you in advance

Table has following 2 columns

DocNum DocEntry
1 234
2 324
2 746
3 876
3 764
4 100
4 387

Expected result is as follow

1 234
2 324, 746
3 876, 764
4 100, 387

create table #temp1 (rno int, points varchar(20))
INSERT INTO #temp1 VALUES (1,234)
INSERT INTO #temp1 VALUES(2,324)
INSERT INTO #temp1 VALUES(2,746)
INSERT INTO #temp1 VALUES(3,876)
INSERT INTO #temp1 VALUES(3,764)
INSERT INTO #temp1 VALUES(4,100)
INSERT INTO #temp1 VALUES(4,834)

select * from #temp1

select distinct a.rno,
substring(
(select points + ‘,’ from #temp1 b where a.rno=b.rno order by a.rno for xml path(”)),0,
LEN(
(select points + ‘,’ from #temp1 b where a.rno=b.rno order by a.rno for xml path(”)))
)
from #temp1 a

cte which i have writted is below:
with testorg as(
select oid,orgname,parentid from #organizationdtls where parentid = 0
union all
select a.oid,a.orgname,a.parentid from #organizationdtls a inner join testorg t on(a.parentid = t.oid)
)
select t.* from testorg t

Help me in achieving such output if i pass oid = 10 then it should return
empdtls:
eid staffno oid
1-99-13

Please help me !!

This will work for three levels (same table variable as before):

WITH cte AS (
SELECT
idConcept,
idParentConcept,
NULL AS ParentParent,
[Description]
FROM
@Temp
WHERE
idParentConcept IS NULL
UNION ALL
SELECT
t.idConcept,
t.idParentConcept,
cte.idParentConcept,
t.[Description]
FROM
@Temp t
INNER JOIN cte ON t.idParentConcept = cte.idConcept)
SELECT
idConcept,
idParentConcept,
[Description]
FROM
cte
ORDER BY
COALESCE(ParentParent, idParentConcept, idConcept),
CASE WHEN ParentParent IS NULL THEN idConcept ELSE idParentConcept END,
idConcept;