SQL Server Journey with SQL Authority

Yesterday I wrote about SQL SERVER – Find Table in Every Database of SQL Server. Today we will see another method how we can achieve the same result using Information_Schema view. Refer my previous article here for additional information.

CREATE PROCEDURE usp_FindTableNameInAllDatabase
@TableName VARCHAR(256)
AS
DECLARE @DBName VARCHAR(256)
DECLARE @varSQL VARCHAR(512)
DECLARE @getDBName CURSOR
SET @getDBName = CURSOR FOR
SELECT name
FROM sys.databases
CREATE TABLE #TmpTable (TABLE_CATALOG VARCHAR(128), TABLE_SCHEMA VARCHAR(128), TABLE_NAME VARCHAR(256), TABLE_TYPE VARCHAR(10))
OPEN @getDBName
FETCH NEXT
FROM @getDBName INTO @DBName
WHILE @@FETCH_STATUS = 0
BEGIN
SET @varSQL = 'USE ' + @DBName + ';
INSERT INTO #TmpTable
SELECT *
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME LIKE ''%' + @TableName + '%'''
EXEC (@varSQL)
FETCH NEXT
FROM @getDBName INTO @DBName
END
CLOSE @getDBName
DEALLOCATE @getDBName
SELECT *
FROM #TmpTable
DROP TABLE #TmpTable
GO
EXEC usp_FindTableNameInAllDatabase 'Address'
GO

Reference : Pinal Dave (http://blog.SQLAuthority.com)