First of all answer this question : Which method of T-SQL is better for performance LEFT JOIN or NOT IN when writing query? Answer is : It depends! It all depends on what kind of data is and what kind query it is etc. In that case just for fun guess one option LEFT JOIN or NOT IN. If you need to refer the query which demonstrates the mentioned clauses, review following two queries.
USE AdventureWorks;
GO
SELECT ProductID
FROM Production.Product
WHERE ProductID
NOT IN (
SELECT ProductID
FROM Production.WorkOrder);
GO
SELECT p.ProductID
FROM Production.Product p
LEFT JOIN Production.WorkOrder w ON p.ProductID = w.ProductID
WHERE w.ProductID IS NULL;
GO
Now let us examine the actual execution plan of both the queries. Click on image to see larger image. 
You can clearly observe that first query with NOT IN takes 20% resources of execution plan and LEFT JOIN takes 80% resources of execution plan. It is better to use NOT IN clause over LEFT JOIN in this particular example. Please note that this is not generic conclusion and applies to this example only. Your results may vary on many factors. Let me know your comments if you have guessed this correct or not.
Reference : Pinal Dave (http://blog.SQLAuthority.com)
[...] recommend to read my previous article SQL SERVER – Better Performance – LEFT JOIN or NOT IN?, which describes how to convert subqueries to Joins and Joins to [...]
It looks like LEFT JOIN gives more accurate results than NOT IN function.
This query returned 0 records.
SELECT DISTINCT(A.CSN_ID) FROM TRG_LINKED_ENCS A
WHERE A.CSN_ID not in (SELECT DISTINCT(CSN_ID) FROM
TPL_TXDAYS )
This query retured 8700 records.
SELECT A.CSN_ID FROM TRG_LINKED_ENCS A
LEFT JOIN TPL_TXDAYS B ON
A.CSN_ID =B.CSN_ID
WHERE B.CSN_ID IS NULL
The table TPL_TXDAYS must be having records with CSN_ID as null
SELECT DISTINCT(A.CSN_ID) FROM TRG_LINKED_ENCS A
WHERE A.CSN_ID not in (SELECT DISTINCT(CSN_ID) FROM
TPL_TXDAYS where CSN_ID is not null )
Hi!
It is bit hard to guess which one is actually most efficient.
If you turn on the STATISTICS IO and check messages, you’ll notice that the NOT IN -query accesses significantly more data pages with more scans:
NOT IN:
Table ‘WorkOrder’. Scan count 504, logical reads 1097, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table ‘Product’. Scan count 1, logical reads 4, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
LEFT JOIN:
Table ‘WorkOrder’. Scan count 1, logical reads 101, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table ‘Product’. Scan count 1, logical reads 15, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Compare especially the Scan Count and Logical Reads -values.
Also, I tried to get the same results with using EXISTS and Query Optimizer produced exactly the same Execution Plan as for the NOT IN -query:
SELECT ProductID
FROM Production.Product p
WHERE NOT EXISTS
(SELECT ProductID
FROM Production.WorkOrder w
WHERE p.ProductID = w.ProductID);
As EXISTS -query usually outperforms JOINs, the worrying STATISTICS IO -results probably tells about badly optimized indexes for this kind of query.
Like you said: it depends on the database structure and amount of data. I also recommend not to stare only at the Execution Plans as they don’t always tell the whole truth.
Hmm. I didn’t really get anything out of that. Percentages are useful but what were the overall timings. 20% of 10s against 80% of one second or the other way around?
What are the effects at different data sizes?
More information is definitely needed before any conclusion can be made.
20% and 80% of the complete batch.
But what about this:
SELECT p.ProductID
FROM Production.Product p
LEFT JOIN Production.WorkOrder w ON p.ProductID = w.ProductID
AND w.ProductID IS NULL;
Then where should we use left join???
Looking at the example it would seem the results would vary based on the number of rows in the WordOrder table and what indexes are set up.
If ProductID is indexed wouldn’t this be a seek operation while the IN statement is reading the entire table?
Always use SET STATISTICS IO ON. The execution plan shows an “estimate” of cpu usage and those numbers are completely worthless since IO rules all.
Although the LEFT JOIN may be more processor intensive it is significantly less IO expensive which is the far more important measure.
The only time to use a subquery and play that little game of “beat the optimizer” is when the tables have normalization or index issues that you have no control over.
Very very good.
Your explanations are great! Simply Great!
Dude,
You know it well how query optimiser works. Do you work for MS cause noone can explain things like you.
NOT EXISTS/LEFT JOIN > SUBQUERY/NOT IN
That’s how I see it “most of the time”
Usually it is better to avoid correlated subselects. Looking only at only resources used is a pretty worthless method of evaluating optimization methods. The goal of optimization is to reduce run-time while still giving the correct answer.
I ran this select,
USE ttst
GO
SET SHOWPLAN_ALL ON
GO
select * from customer
where c.record_type = ‘T’
and c.customer_class_code = ‘LOCAL’
and c.customer_status_code = ‘ACTIVE’
SET SHOWPLAN_ALL OFF
GO
it gave me a error like below,
Server: Msg 1067, Level 15, State 1, Line 5
The SET SHOWPLAN statements must be the only statements in the batch.
(1 row(s) affected)
What is the correct way to use the set showplan_all on?
Jchen
Thanks! Really it is very useful for my query changes
Simple…KISS!
Oracle does not have Exists. Is there an equivalent?
Bob
USE IN or NOT IN
Thanks for such a nice tip… its really help me in MySQL…
Thanks once again
regards,
Naseer Ahmad
–List names of authors who have contributed in
–any book title
SELECT DISTINCT authors.au_id,au_fname
FROM authors,titleauthor
WHERE authors.au_id!=titleauthor.au_id
SELECT au_id, au_fname FROM authors WHERE authors.au_id NOT IN
(SELECT au_id FROM titleauthor)
why the above query did not work as same as the below query??
the above on shows more records then the following.
why we did not do the same work with JOIN as with NOT IN??
Brilliant posts !
hi Pinal,
I want to retrieve only limited data from database like limit is keyword in mysql which retrieve limited data according to our arguments. Like I want to load only 10 records from the database at first display in page. but I don’t want to using top. Because its create problem of paging. So please give me alternate solution for that’d have use row index but in that row index I have to write inner query and my data base I s to heavy.
Sanjay, you can use ROWCOUNT.
SET ROWCOUNT 10
SELECT * FROM table
SET ROWCOUNT 0
Beware of SET ROWCOUNT
It may be removed from future relases of SQL Server
So make use of TOP instead
Very Helpful!
The difference is obvious in the query plans, the Join query is not using the index. You could alter the indices or the query to take advantage of the indices. Also, when you look at the statistics output you can see that the Join query is doing much better than the Not In query based on reads and scans, which in a high volume environment will be a much better indication of performance anyway. My opinion, the percentages shown on query plans are useless, use query plans only to figure out what indices you’re not taking advantage of (i.e. look for table and index scans).
Thanks a lot!!!
You are a star, three days of banging my head against the monitor have come to an end as a result of reading this post.
Thanks
hey Dave great thread, can you please tell me how did analyse the preform of the query,whats the meaning of 80% of the batch,and whats the tool you are using for the analysis??…
hope for the quick reply.
bbye
I am not aware of how you measured resource percentage given “20% resources of execution plan and LEFT JOIN takes 80% resources of execution plan”. I need little more explanation.
Regards,
Pradip
When you execute both query at one time it will show relative cost for each query.
Thanks a lotI consider this site a very good one for me to face the interview questions ahead of me. ,
I have a table, and there is a date column in it, and many records in it.
My query is, i want to retrieve all the dates of a particular calender year which are not there in the table.
i.e., i want to know the dates which are not present in my table and which has a gap of more than 24 hrs
To put it in simple, i want to know the transaction of a particular inventory for which there is no transaction on that particular date, i want to know all the dates of year(with 24 hrs gap)
@Jalan
Either give sample data or give us more details. When you say 24 Hours, is this 24 hours between two successful dates ? Please help us to help you by providing more information.
~ IM.
DATE table
01/01/09 01.00 AM
02/01/09 12.00 PM
04/01/09 02.00 PM
05/01/09 05.00 PM
06/01/09 06.00 PM
07/01/09 09.00 PM
08/01/09 09.00 PM
12/01/09 04.00 PM
Consider these as sample dates, now my output should be
03/01/09
09/01/09
10/01/09
11/01/09
Huh! This was a tricky one. I’m not sure if I still understood this correctly though since I’m not getting that last date 11/01/09 in the results.
CREATE FUNCTION fn_get_days_forward
(
@FirstDay datetime
)
RETURNS @dates TABLE
(
dt DATETIME
)
AS
BEGIN
DECLARE @nextDay DATETIME
SELECT TOP 1 @nextDay = DATEADD(DAY, -1, dt) FROM dates WHERE dt > @FirstDay ORDER BY dt ASC
SET @FirstDay = DATEADD(DAY, 1, @FirstDay)
WHILE @FirstDay < @nextDay
BEGIN
INSERT INTO @dates SELECT @FirstDay
SET @FirstDay = DATEADD(DAY, 1, @FirstDay)
END
RETURN
END
GO
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, days.dt))
FROM dates CROSS APPLY fn_get_days_forward(dt) AS days
Nice Post, I am looking for a method to replace IN/NOT IN
Most of the time I heard Join is better than subqueries
Hey All,
Can anybody tell me how to use not in clause with more tan 1 parameter or any other way.
e..g
select mobileno from table1 where (boxno,fileno) not in(select boxno,fileno from tabel2)
Hi the other day i make a equivalence between compare JOINS, WHERE, NOT IN, AND EXIST, this was in ORACLE 10G:
I- CREACIÓN TABLAS:
CREATE TABLE TB_DEMO_A( ID NUMBER, DESCRIPCION VARCHAR2( 10 ) );
CREATE TABLE TB_DEMO_B( ID NUMBER, DESCRIPCION VARCHAR2( 10 ) );
II- CREACIÓN INSERTS:
INSERT INTO TB_DEMO_A VALUES( 1, ‘PRIMERO’ );
INSERT INTO TB_DEMO_A VALUES( 2, ‘SEGUNDO’ );
INSERT INTO TB_DEMO_A VALUES( 3, ‘TERCERO’ );
INSERT INTO TB_DEMO_A VALUES( 4, ‘CUARTO’ );
INSERT INTO TB_DEMO_B VALUES( 1, ‘PRIMERO’ );
INSERT INTO TB_DEMO_B VALUES( 2, ‘SEGUNDO’ );
INSERT INTO TB_DEMO_B VALUES( 5, ‘QUINTO’ );
INSERT INTO TB_DEMO_B VALUES( 6, ‘SEXTO’ );
III- SELECTS:
SELECT a.* FROM TB_DEMO_A a;
SELECT b.* FROM TB_DEMO_B b;
IV.- AMARRES X CASO:
4.1.- “CONJUNTO A” INTERSECCION “CONJUNTO B”:
4.1.1.- FORMA #1:
SELECT a.*, b.*
FROM TB_DEMO_A a,
TB_DEMO_B b
WHERE a.ID = b.ID;
4.1.1.- FORMA #2:
SELECT a.*, b.*
FROM TB_DEMO_A a
INNER JOIN TB_DEMO_B b
ON a.ID = b.ID;
4.2.- (“CONJUNTO A” INTERSECCION “CONJUNTO B”) + ( “CONJUNTO A” MENOS CONJUNTO B” ):
4.2.1.- FORMA #1:
SELECT a.*, b.*
FROM TB_DEMO_A a,
TB_DEMO_B b
WHERE a.ID = b.ID(+);
4.2.2.- FORMA #2:
SELECT a.*, b.*
FROM TB_DEMO_A a
LEFT JOIN TB_DEMO_B b
ON a.ID = b.ID;
4.3.- (“CONJUNTO A” INTERSECCION “CONJUNTO B”) + ( “CONJUNTO B” MENOS CONJUNTO A” ):
4.3.1.- FORMA #1:
SELECT a.*, b.*
FROM TB_DEMO_A a,
TB_DEMO_B b
WHERE a.ID(+) = b.ID;
4.3.2.- FORMA #2:
SELECT a.*, b.*
FROM TB_DEMO_A a
RIGHT JOIN TB_DEMO_B b
ON a.ID = b.ID;
4.4.- ( “CONJUNTO A” MENOS CONJUNTO B” ):
4.4.1.- FORMA #1:
SELECT a.*, b.*
FROM TB_DEMO_A a,
TB_DEMO_B b
WHERE a.ID = b.ID(+) AND
b.ID IS NULL;
4.4.2.- FORMA #2:
SELECT a.*, b.*
FROM TB_DEMO_A a
LEFT JOIN TB_DEMO_B b
ON a.ID = b.ID
WHERE b.ID IS NULL
4.4.3.- FORMA #3:
SELECT a.*
FROM TB_DEMO_A a
WHERE a.ID
NOT IN ( SELECT b.ID
FROM TB_DEMO_B b
);
4.4.4.- FORMA #4:
SELECT a.*
FROM TB_DEMO_A a
WHERE NOT EXISTS( SELECT b.ID
FROM TB_DEMO_B b
WHERE a.ID = b.ID
);
4.5.- ( “CONJUNTO B” MENOS CONJUNTO A” ):
4.5.1.- FORMA #1:
SELECT a.*, b.*
FROM TB_DEMO_A a,
TB_DEMO_B b
WHERE a.ID(+) = b.ID AND
a.ID IS NULL;
4.5.2.- FORMA #2:
SELECT a.*, b.*
FROM TB_DEMO_A a
LEFT JOIN TB_DEMO_B b
ON a.ID = b.ID
WHERE a.ID IS NULL
4.5.3.- FORMA #3:
SELECT b.*
FROM TB_DEMO_B b
WHERE b.ID
NOT IN ( SELECT a.ID
FROM TB_DEMO_A a
);
4.5.4.- FORMA #4:
SELECT b.*
FROM TB_DEMO_B b
WHERE NOT EXISTS( SELECT a.ID
FROM TB_DEMO_A a
WHERE b.ID = a.ID
);
Diferents Style to Make the same.
Thanks for the advice – very practical performance analysis approach. Any idea how this might correlate to the set size in the subquery or join?
good article………………….
‘Show result
Select ’02′,ccd01emp,ccd01ano,ccd01mes,ccd01subd,
ccd01numer,ccd01ord,ccd01cta,ccd01deb,ccd01hab,ccd01con
from ccd Where
ccd01emp=’01′
And ccd01ano=’2011′
And ccd01mes=’05′
And ccd01cta Not in (Select ccm01cta from ccm01cta Where
ccm01emp=’01′
And ccm01aa=’2011′)
‘Not Show result
Select ’02′,ccd01emp,ccd01ano,ccd01mes,ccd01subd,
ccd01numer,ccd01ord,ccd01cta,ccd01deb,ccd01hab,ccd01con
from ccd left outer Join ccm01cta
On ccd01cta = ccm01cta
Where
ccd01emp=’01′
And ccm01emp=’01′
And ccd01ano=’2011′
And ccm01aa=’2011′
And ccd01mes=’05′
And isnull(ccm01cta,”)=”
‘
I’m trying to change this subquery into a join and was hoping I might get a comment back here. :)
CODE:
SELECT col1, col2, col3
FROM dbo.myTable AS T1
WHERE (col2 = 2) AND (col3 = 1) OR
(col2 = 1) AND (col3 = 2)
AND (col1 NOT IN (SELECT col1
FROM dbo.myTable
WHERE (col2 = 2) AND (col3 = 1)))
Figured it out, was simpler than I thought :)
CODE:
SELECT col1, col2, col3
FROM dbo.myTable AS T1
WHERE (col2 = 2) AND (col3 = 1) OR
(col2 = 1) AND (col3 = 2)
AND (col1 NOT IN (SELECT col1
FROM dbo.myTable
WHERE (col2 = 2) AND (col3 = 1)))
Is the same as…
CODE:
SELECT col1, col2, col3
FROM dbo.myTable AS T1 LEFT OUTER JOIN
dbo.myTable AS T2 ON T1.col1 = T2.col1
WHERE (T1.col2 = 2) AND (T1.col3 = 3) OR
(T1.col2 = 1) AND (T2.col3 = 2) AND (T2.col1 IS NULL)
The reason I wanted to find a way to convert this subquery into a join was that I am trying to create this as an indexed view. Figured I’d post this response in hopes that it may help someone else in the future. :)
Blah… typo…
Last line should be:
(T1.col2 = 1) AND (T1.col3 = 2) AND (T2.col1 IS NULL)
Bit tricky.
if exists(select a.PRODH from MVKE as a inner join ZSD_FREIGHT_BOL as b on SUBSTRING(a.PRODH,1,18)=b.PRODH and REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material)
begin
if not exists(select VRKME from MVKE where REPLACE(LTRIM(REPLACE(MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material and VRKME=”)
begin
if exists(select KUNNR from KNMT where cast(cast(KUNNR as int) as varchar(20))=@CustCode and REPLACE(LTRIM(REPLACE(MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material)
begin
select distinct(c.BSSKZ) as NominalVar,REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′) as MaterialNo,a.MAKTX as MaterialDesc,
b.KDMAT as CustPartNo,d.VRKME as SkuUM,e.MEINH as ExtUM from MAKT as a
inner join KNMT as b on REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(b.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MLGN as c on REPLACE(LTRIM(REPLACE(c.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MVKE as d on REPLACE(LTRIM(REPLACE(d.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join ZSD_FREIGHT_BOL as e on e.PRODH=SUBSTRING(d.PRODH,1,18)
inner join MARM as f on REPLACE(LTRIM(REPLACE(f.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
where a.SPRAS=’E’ and CAST(CAST(b.KUNNR as int) as varchar(20))=@CustCode and REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material
end
else
begin
select distinct(c.BSSKZ) as NominalVar,REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′) as MaterialNo,a.MAKTX as MaterialDesc,
‘—-’ as CustPartNo,d.VRKME as SkuUM,e.MEINH as ExtUM from MAKT as a
–inner join KNMT as b on REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(b.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MLGN as c on REPLACE(LTRIM(REPLACE(c.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MVKE as d on REPLACE(LTRIM(REPLACE(d.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join ZSD_FREIGHT_BOL as e on e.PRODH=SUBSTRING(d.PRODH,1,18)
inner join MARM as f on REPLACE(LTRIM(REPLACE(f.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
where a.SPRAS=’E’ and REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material
end
end
else
begin
if exists(select KUNNR from KNMT where cast(cast(KUNNR as int) as varchar(20))=@CustCode and REPLACE(LTRIM(REPLACE(MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material)
begin
select distinct(c.BSSKZ) as NominalVar,REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′) as MaterialNo,a.MAKTX as MaterialDesc,
b.KDMAT as CustPartNo,M.MEINS as SkuUM,e.MEINH as ExtUM from MAKT as a
inner join KNMT as b on REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(b.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MLGN as c on REPLACE(LTRIM(REPLACE(c.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MVKE as d on REPLACE(LTRIM(REPLACE(d.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join ZSD_FREIGHT_BOL as e on e.PRODH=SUBSTRING(d.PRODH,1,18)
inner join MARM as f on REPLACE(LTRIM(REPLACE(f.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MARA as M on REPLACE(LTRIM(REPLACE(M.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
where a.SPRAS=’E’ and CAST(CAST(b.KUNNR as int) as varchar(20))=@CustCode and REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material
end
else
begin
select distinct(c.BSSKZ) as NominalVar,REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′) as MaterialNo,a.MAKTX as MaterialDesc,
‘—-’ as CustPartNo,M.MEINS as SkuUM,e.MEINH as ExtUM from MAKT as a
–inner join KNMT as b on REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(b.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MLGN as c on REPLACE(LTRIM(REPLACE(c.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MVKE as d on REPLACE(LTRIM(REPLACE(d.MATNR,’0′,’ ‘)),’ ‘,’0′)=REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join ZSD_FREIGHT_BOL as e on e.PRODH=SUBSTRING(d.PRODH,1,18)
inner join MARM as f on REPLACE(LTRIM(REPLACE(f.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
inner join MARA as M on REPLACE(LTRIM(REPLACE(M.MATNR,’0′,’ ‘)),’ ‘,’0′)= REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)
where a.SPRAS=’E’ and REPLACE(LTRIM(REPLACE(a.MATNR,’0′,’ ‘)),’ ‘,’0′)=@Material
end
end
end
____________________________-
Any one Please help me to simplify this query and i joined more than 6 tables it will take more time to execute the process. Anyone Please help me to favour……..
Thanks in advance
I do agree with you that we need to use not in instead left join yet Sometime I came across situation where not in gives incorrect result I prefer to use not exist construct as it works as per one can think.
Further left join give correct result in case if you use not in and inner query column contain a null then we doesn’t get any result in outer query.
Very very good !!!!
It helps me alot, the answer to your cuestion is: “depens of the amount of data” in my case I compare two tables with some hundreds of million of records…. if is your case, JOIN must be your choice.
Hi,
Just curious is find out how would one optimize this query then:-
Update INVOICE_MASTER
SET DISCOUNT_AMOUNT = 0 , DISCOUNT_PERCENTAGE = 0
where TENDERED in (2,4)
and SALES_TYPE = ‘Cash’
and INVOICE_NO not in (select INVOICE_NO from INVOICE_TENDERS where TENDER_TYPE = ‘DISCOUNT’)
Many Thanks in advance
can anyone explain me the case when should i use which join.Because most of the time i did normal joins using where clauses so i am not use to any other kind of join
@Dhiraj – your question is confusing. Maybe this will help you:
Use an INNER JOIN when you want only records that are related in both tables.
Use a LEFT JOIN when you want all records in the left table.
Use a RIGHT JOIN when you want all records in the right table.
Personally, I never use RIGHT JOIN. I’ve written thousands of queries with just INNER or LEFT.
Hope this helps.
HI pinal, SQL guru, i am your lovable fan in SQL sever 2005
Can you answer or suggest my question?
is Any Alter Way of Leftouter join method Available in Sequel?
Can anyone give me the method of alter way of left outer join Because when we create a indexed view we could not able create index on theat view due to statement contains FULL JOIN or LEFT JOIN or RIGHT JOIN. So i searched the web fully it gives suggestion using UNION Instead of left join,I mentioned query below. So could you give me any other method is available to replace LEFT JOIN with that other than UNION? Is it full to reduce optimization cost when we use UNION instead of LEFT JOIN? Quick suggestions are highly appreciated………….buddys………
———————-My original table using left join method—————–
SELECT tablea.*,
CASE
WHEN tableb.tablebcolumn1 IS NULL THEN 0
ELSE 1
END IsHosted
FROM tablea
LEFT JOIN tableb ON tablea.column=tableb.column
———–Example of alter way of using UNIONALL instead of leftouterjoin ———
SELECT tablea.,
CASE
WHEN tableb.tablebcolumn1 IS NULL THEN 0
ELSE 1
END IsHosted
FROM tablea where tablea.column IN (select tableb.column from tableb) UNION ALL SELECT tablea.,
CASE
WHEN tableb.tablebcolumn1 IS NULL THEN 0
ELSE 1
END IsHosted
FROM tablea where tablea.column NOT IN (select tableb.column from tableb)
————————————————————————————– Note: Due to security reason i did not give original table name. i gave table name of tablea and tableb………as my originaltable name
I am just curious why sometimes ‘IN’ and ‘NOT IN’ give different result than ‘JOIN’
Sometimes, using IN/NOT IN with the same table work but doesn’t with another table (same table structure)
select email from [temp].[dbo].SETA where email not in (select email from [temp].[dbo].SETA) — OK
select email from [temp].[dbo].SETA where email not in (select email from [temp].[dbo].SETB) — return nothing both ‘not in’ and ‘in’
Hi, I am Meenakshi, I have one query
How to write the query for having more than 1000 static values in IN clause?
Or any alternative solution to IN clause?
In this scenario, I would import the list into a sql table using the Import Wizard, then use an inner join on the table that contains the data. If you need help writing the query you can contact me.
[...] Better Performance – LEFT JOIN or NOT IN? First of all answer this question : Which method of T-SQL is better for performance LEFT JOIN or NOT IN when writing a query? The answer is : It depends! It all depends on what kind of data is and what kind query it is etc. In that case just for fun guess one option LEFT JOIN or NOT IN. [...]