Select *
from (Select *, DENSE_RANK() OVER (ORDER BY Salary DESC) AS Ranks from #T1) a
WHERE Ranks = N

Thanks,
-Amol.

Here’s an explanation of how the following query works:

For each row, this query makes a cartesian product with other rows of the table. Then according to the inner query syntax, it compares the salaries. Then, the number comparison in the first outer query makes sure that only those records are picked which satisfy the criteria. E.g.

Let’s say u got 3 records, with salaries 10, 20 and 30. So, the cartesian product is something like,
1) For row with sal 10 –> 10-10, 10-20, 10-30
2) For row with sal 20 –> 20-10, 20-20, 20-30
3) For row with sal 30 –> 30-10, 30-20, 30-30

Now apply the condition, e1.sal 10-10, 10-20, 10-30 (3)
2) For row with sal 20 –> 20-10, 20-20, 20-30 (2)
3) For row with sal 30 –> 30-10, 30-20, 30-30 (1)

Now the outer condition, 2<= (the count arrived at above). So only 2) and 3) get selected. Hence, it shows salaries according to outer query for these two i.e. 20 and 30.

PS: This is inefficient and should be avoided. Prefer rank() in Oracle

Hope it helps.

where 2<=(select count(*) from
emp e2 where e1.sal <= e2.sal)

group by deptno;

can u explain this query how its work

explain where condiation also ????

u can work on this…

select max(e1.sal), e1.deptno from emp e1

where 2<=(select count(*) from
emp e2 where e1.sal <= e2.sal)

group by deptno;

u might get ur solution….i supose…just work on this

u can work on this…

select max(e1.sal), e1.deptno from emp e1

where 2<=(select count(*) from
emp e2 where e1.sal <= e2.sal)

group by deptno;

u might get ur solution….i supose…just work on this

thankx..

very goood.

would you please help me to sort it out ?
anyone’s help will be greatly appreciated..

Thanks and regards
Deba

SELECT sal FROM
(SELECT sal, RANK(ORDER BY sal DESC) rn)
WHERE rn = rank-you-want

This will report all people at that level. If, however, you want one and only one, ROW_NUMBER():

SELECT sal FROM
(SELECT sal, ROW_NUMBER() OVER(ORDER BY sal DESC) rn)
WHERE rn = rank-you-want

SQL> SELECT TOP 1 sal
2 FROM (
3 SELECT DISTINCT TOP 6 sal
4 FROM emp
5 ORDER BY sal DESC) a
6 ORDER BY sal;
SELECT TOP 1 sal
*
ERROR at line 1:
ORA-00923: FROM keyword not found where expected

SQL> SELECT sal
2 FROM (
3 SELECT DISTINCT TOP 6 sal
4 FROM emp
5 ORDER BY sal DESC) a
6 ORDER BY sal;
SELECT DISTINCT TOP 6 sal
*
ERROR at line 3:
ORA-00923: FROM keyword not found where expected

Thanks guys … for valuable posts … keep posting … its a good sign for us … we can share and solve others problems too….

regards,

Raj

Just check this query . It will give 4th highest salary from the list of employee salaries.

SELECT MIN(empsal) AS Empsalary
FROM emp
WHERE (empsal IN
(SELECT DISTINCT TOP (4) empsal
FROM emp AS emp_1
ORDER BY empsal DESC))

notice that emp_1 is created while executing the query. Its automatically generated one.

No need to confuse with the ‘ a ‘ . Its just a alias name given for the table particularly in the case of sub queries. Be aware that we written a sub query to achieve the result.

If u didn’t specify the name in SQL Server 2000/2005 , it wont give any effect to the result but just observe that when u execute the query system will automatically attach table name_1 alias name to the table.

I hope u got somewhat clear idea.

Regards,

Raj

Which variable you are talking about, I dont see any variable.

Please post your complete question.

~IM.

in this query u used a

SELECT TOP 1 Sal
FROM (
SELECT DISTINCT TOP 2 Sal
FROM Emp
ORDER BY Sal DESC) a
ORDER BY Sal

why did u use that a variable can u explain me..

thanks in advance
regards
Srinu Ganaparthi

i am new to SQl.. so could u please help me out in finding the second highest and third highest sal .
And please explain me the query what it does.
example :

1> SELECT * from employee e1 WHERE 1=(SELECT COUNT(DISTINCT salary) from employee e2 WHERE e1.salary SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP 6 salary
FROM employee
ORDER BY salary DESC) a
ORDER BY salary
what u mean by TOP1. Is it a column name in the table or to display in the out put.
please do explain me the querry.

Thanks in advance…………..

Regards,
Deepak