Comments on: SQL SERVER – 2005 – Find Index Fragmentation Details – Slow Index Performance

By: george Gopie

george Gopie — Fri, 21 Aug 2009 13:19:27 +0000

Pinal,

Why the script would not return any indexes and their statistics e.g % fragmented? Doe this mean ther are none indexes in this datbase thar are fragmented even a small percent. DO i need to run something else before i run this script.

By: willBen

willBen — Wed, 10 Jun 2009 11:49:59 +0000

Pinal Dave, you sir, are, a legend.

By: Musab

Musab — Tue, 30 Dec 2008 09:38:24 +0000

Try rebuilding the index it will improve it

By: AdminByDefault

AdminByDefault — Tue, 30 Sep 2008 12:55:29 +0000

I have tried to defrag the tables in my databases but have discovered that some indexes will not improve better than 85% total fragmentation. How can I overcome this problem? Or is this something that I should not be concerned with?

By: Yusuf

Yusuf — Fri, 15 Aug 2008 14:43:10 +0000

Can we merge the following into the output
1. Indexed Columns
2. Included Columns

By: DiegoP

DiegoP — Tue, 27 May 2008 16:20:12 +0000

You can replace DB_ID() with the database ID:

You can do this to find out the ID:

USE yourdatabase
SELECT DB_ID() AS [Database ID];
GO

By: PAN

PAN — Fri, 23 May 2008 03:46:40 +0000

I tried teh above script but it give sme this error-
Msg 102, Level 15, State 1, Line 4
Incorrect syntax near ‘(‘.

Do I have to replace the exact Database name etc somewhere in this script.

By: Vince

Vince — Thu, 08 May 2008 17:51:02 +0000

This modification of the original will return the Parent table name.
USE [your DB]
GO
SELECT ps.database_id, ps.OBJECT_ID, ps.index_id, si.name, ps.avg_fragmentation_in_percent,
(SELECT distinct so.name FROM sys.objects so INNER JOIN sys.indexes ON so.object_id = si.object_id) ParentTable
FROM sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL, NULL) AS ps
INNER JOIN sys.indexes si ON ps.OBJECT_ID = si.OBJECT_ID
AND ps.index_id = si.index_id
WHERE ps.database_id = DB_ID() AND si.name is not null AND
ps.avg_fragmentation_in_percent > 30 — min % to return
ORDER BY ps.avg_fragmentation_in_percent desc
GO

By: mal

mal — Mon, 14 Apr 2008 12:00:06 +0000

select tbl.[name] TableName,
ind.[name] IndexName,
mn.index_type_desc IndexType,
mn.avg_fragmentation_in_percent [FRAG_%]
from sys.dm_db_index_physical_stats (null, null, null, null, null )as mn
inner join sys.tables tbl on tbl.[object_id] = mn.[object_id]
inner join sys.indexes ind on ind.[object_id] = mn.[object_id]
where [database_id] = db_id(‘dbSynthetics’)
order by mn.avg_fragmentation_in_percent desc

By: BravehearT1326

BravehearT1326 — Tue, 08 Apr 2008 14:37:40 +0000

Hi there – any chance of amending the above script to show the actual table name where the index resides…..

Thanks

By: Dirty Noodle

Dirty Noodle — Mon, 31 Mar 2008 15:44:08 +0000

Can you write the sample script in SQL 2000? Thanks!