SELECT TOP (1) PERCENT A.hist_dt, A.acc_type_cd, A.acc_no, A.current_balance, B.hist_dt AS Expr1
FROM ecslcall.dbo.investor_nav_hist AS A INNER JOIN
(SELECT hist_dt, acc_type_cd, acc_no, current_balance, div_income, deposit
FROM ecslcall.dbo.investor_nav_hist) AS B ON A.acc_no = B.acc_no AND A.hist_dt < B.hist_dt
WHERE (A.acc_no = 308) AND (B.hist_dt = CONVERT(DATETIME, '2011-05-22 00:00:00', 102))
ORDER BY A.hist_dt DESC

N: the number of records you want to get

Request you to all please find below mentioned query, if i am wrong then feel free to let me know… while i have tried this query and it’s giving rite output….

it will show sixth highest salary…

SELECT TOP 1 salary FROM (SELECT DISTINCT TOP 6 salary FROM Table ORDER BY salary DESC) a ORDER BY salary

Here we go

DECLARE @string varchar(500)
DECLARE @Xml XML
SET @string=’BIS001,BIS002,BIS009,BIS010,BIS003′
SET @xml = ‘
‘ + REPLACE(@string, ‘,’, ”) + ” +
”
SELECT top 1 x.v.value(‘.’,'VARCHAR(100)’)
FROM @xml.nodes(‘/IDs/ID’) x(v)
order by x.v.value(‘.’,'VARCHAR(100)’) desc

-Ravi

I would like to know how this query is executes .i am unable to understand how this query is joining E1 , E2 .
as i knows first inner query will be fired but it will not have any info about E1 because it is in outer query.
I will prefer
SELECT *
FROM HumanResources.EmployeePayHistory E1
WHERE (4-1) = (SELECT COUNT(DISTINCT(E2.Rate))
FROM HumanResources.EmployeePayHistory E2
WHERE E2.Rate > E1.Rate)

this query to get n th record because it is less depent on DB functions it is using general function .

Use this
SELECT * FROM Employee e1 WHERE (N-1) = (SELECT COUNT(DISTINCT(p2.salary))
FROM Employee e2 WHERE e2.salary > e1.salary)

can you try this, where i’m trying to find the third highest salary

select top 1 *
from (select top 3 *
from emp_table
order by salary desc)
order by salary

Thank you for trying this. Can u pls help me out if their is any other query, as the result is not as expected.

This is not what i need.

Suppose i have a table with following data

EmpNo Empname sal

1 X 100

2 y 300

3 a 50

4 b 200

5 c 500

6 d 250

Here i want 3rd record i.e 3 a 50, using the sal column.

If i use ur query i will get 4 b 200 or if the order is changed u may get 6 d 250.
In which the result was not as i expected.
I just want the nth record it may or may not have duplicates

use this query for any record you want to find in the table.

SELECT TOP A salary FROM (SELECT TOP (n) salary FROM employee ORDER BY salary DESC)
AS E ORDER BY salary ASC

top(n) give the total no of records

a desire top value

another way

select t.* from (select row_number() over(order by salary) as row_id, salary from sal)
t where t.row_id = 24

give the which nth record you want