In Sql Server the way to get recordsets for pagination is also unnecessarily complex TOP X and order-by, OVER PARTITION etc is ridiculous, in MySQL its as simple as LIMIT offset count.

select distinct a,b,c,database from
(
select a,b,c,’A’ as database from tableA
union
select a,b,c,’B’ as database from tableB
) as Everything

with tableA and tableB having lots of data in common, and I expect this query to give all the rows with different value of a.

Where’s the logical error? Is there any way to have this simple query done in SQLServer?

I would like to know wether the distinct can be applied to each column in a table or not… if so can you please
explain..

e.g.

I have a table containing a firstname, lastname, salary, designation, dob, doj,

—-
I would like to apply distinct keyword for all the column in a table.

Thanks in Advance,
Prithviraj MK

In my file I need to have a 100 records with all the columns but each record should have a DISTINCT PayerID.
How would I do that ?

If you are using SQL 2005 and above, you can use following:

;with cte as(
SELECT Row_NUMBER() OVER(PARTITION BY Person ORDER BY Person) AS RowID,
*
from table
)
select *
from cte
where RowID > 1

It will list out all records that you need to delete. If you are sure that you can delete this. use this query:

;with cte as(
SELECT Row_NUMBER() OVER(PARTITION BY Person ORDER BY Person) AS RowID,
*
from table
)
DELETE
from cte
where RowID > 1

For more information: http://www.sqlyoga.com/2009/03/sql-server-find-duplicate-rows-with.html

Thanks,
Tejas

i have to select only one person record and delet his duplicate entries … that person records at a time

Need more details.

Do you have duplicate records for the same PayerID with different combinations of ID< Category, Status and CreateDate. If there exusts multiple records for same PayerID, I dont think, you can achieve your tasks by a simple select statement.

Please provide some sample data.

Input and what kind of output you are expecting.

~ IM.

I have a situation where I’m asked for a sample of 100 records from a 10,000 record table. The table has the following columns ( ID, PayerID, Category, Status, CreateDate )

In my Sample file I need to have a 100 records with all the columns but each record should have a DISTINCT PayerID.

Explain to me please on how would you solve this?

Thanx

Kinara

One way to do that is use GROUP BY, But there is a serious problem with GROUP BY, which I hate saying but true, You have to include all the columns in GROUP BY clause what you have mentioned in SELECT clause.

Anyways your best choice would be to use OVER PARTITION BY in your select query, this is a new feature in sql server 2005.

OVER PARTITION BY will serves your purpose. This is just like GROUP BY but here you have freedom to exclude columns that you do not want to include in GROUP BY clause.

GROUP BY is nothing but grouping or distinct (for that match of columns) in a way.

Find simple example of OVER PARTITION BY here,

http://www.sqlteam.com/article/sql-sever-2005-using-over-with-aggregate-functions

~ IM.

I have a similar problem but cant fix it can you please help me, problem is:

I have a table with following columns: basketid, lookup_value, date_time.

I only want to return distinct basketid and lookup value rows and also want to include date_time row as well. but it is not distinct. any solutions please. Group by and distinct does not solve my problem.

Thank you

MySQL can easily do this with the following code:
“SELECT DISTINCT Roles, FirstName, LastName FROM UserNames”