Comments on: SQL SERVER – UDF – User Defined Function – Get Number of Days in Month

By: Gourav

Gourav — Fri, 24 Apr 2009 05:32:26 +0000

thanks bro… you hav done it….thank you very very much…
Regards
Gourav

By: Brian Tkatch

Brian Tkatch — Thu, 23 Apr 2009 16:31:30 +0000

@gourav, here’s a quick shot:
CREATE FUNCTION UDFDays(@mm tinyint,@yy smallint,@dyw varchar(9))
RETURNS TABLE
AS
RETURN
WITH
Data(The_Date)
AS
(
SELECT CONVERT(smalldatetime, CAST(@mm as varchar(2)) + ‘/01/’ + CAST(@YY as varchar(4)) , 101)
),
Days_In_Month
AS
(
SELECT The_Date, DATEADD(d, -1, DATEADD(m, 1, The_Date)) Next_Month FROM Data
UNION ALL
SELECT DATEADD(d, 1, The_Date), Next_Month FROM Days_In_Month WHERE The_Date < Next_Month
)
SELECT
DATEPART(d, The_Date) Day_Number
FROM
Days_In_Month
WHERE
DATENAME(dw, The_Date) = @dyw;
GO

By: Gourav

Gourav — Thu, 23 Apr 2009 15:25:29 +0000

Re post:… slight mistake frm my side…

hi.. experts… i need a similar UDF…
my req is…. if i give 3 param’s to the UDF.. like..
“month,year and dayofweek” then i should get a list of that day fom the given month,year

ex. for April 2009 Sunday
UDFDays(@mm,@yy,@dyw)
i.e UDFDays(04,2009,’Sunday’)
then i should get list as..

5
12
19
26
i.e… the dates from the month given for weekday.. like for Apil 2009 Saturday..
i expect..esult as

4
11
18
25

etc…
thanks in advance…

By: Gourav

Gourav — Thu, 23 Apr 2009 14:38:02 +0000

hi.. experts… i need a similar UDF…
my req is…. if i give 3 param’s to the UDF.. like..
“month,year and dayofweek” then i should get a list of that day fom the given month,year

ex. for April 2009 Sunday
UDFDays(@mm,@yy,@dyw)
i.e UDFDays(04,2009,’Sunday’)
then i should get list as..

6
13
20
27

i.e… the dates from the month given for weekday.. like for Apil 2009 Saturday..
i expect..esult as

5
12
19
26

etc…
thanks in advance…

By: SQL SERVER - 2008 - Interview Questions and Answers - Part 2 Journey to SQL Authority with Pinal Dave

Thu, 26 Feb 2009 11:55:56 +0000

[...] A Multi-Statement Table-Value user-defined function returns a table and is also an exceptional alternative to a view as the function can support multiple T-SQL statements to build the final result where the view is limited to a single SELECT statement. Also, the ability to pass parameters into a TSQL select command or a group of them gives us the capability to in essence create a parameterized, non-updateable view of the data in the underlying tables. Within the create function command you must define the table structure that is being returned. After creating this type of user-defined function, It can be used in the FROM clause of a T-SQL command unlike the behavior found when using a stored procedure which can also return record sets. (Read Here For Example) [...]

By: SQLAuthority News - Best Articles on SQLAuthority.com Journey to SQL Authority with Pinal Dave

Tue, 24 Feb 2009 12:10:47 +0000

[...] SQL SERVER – UDF – User Defined Function – Get Number of Days in Month [...]

By: Maheswaran

Maheswaran — Wed, 28 Jan 2009 10:23:32 +0000

I want No.of days in a Month – Here i will give Month(2) and Year(2009),

so, there are two parameters.

Pls Give me the function

By: Mahesh K Rajan

Mahesh K Rajan — Mon, 13 Oct 2008 08:39:18 +0000

We have already some built in functions avail, then why should we go behind all those steps…
Anyway, good logic…
-Mahesh

By: poleswar

poleswar — Mon, 21 Jul 2008 12:23:03 +0000

EXCELLENT …:))

EXACTLY SUITS MY REQUIREMENT

SUPERB

THNX A LOT………

By: Vishwanath

Vishwanath — Mon, 10 Mar 2008 09:51:58 +0000

Just a modification to Doug’s posting :

CREATE FUNCTION [dbo].[ufn_GetDaysInMonth] (@CurrentDate DATETIME )
RETURNS INT
AS
BEGIN
DECLARE @RetDate INT
SET @RetDate = DAY(DATEADD(d, -DAY(DATEADD(m,1,@CurrentDate)),DATEADD(m,1,@CurrentDate)))
RETURN @RetDate
END

– SELECT [dbo].[ufn_GetDaysInMonth] (‘2008/02/25′)

By: Thiru

Thiru — Fri, 12 Oct 2007 03:04:26 +0000

Hi pinaldave,

Thank you very much

By: Doug

Doug — Thu, 20 Sep 2007 15:37:28 +0000

Try this one-liner:
CREATE FUNCTION [dbo].[ufn_GetDaysInMonth](
@CurrentDate DATETIME )
RETURNS INT
AS
BEGIN
RETURN DAY(DATEADD(d, -DAY(DATEADD(m,1,@dt)),DATEADD(m,1,@dt)))
END

By: Munna Sarfraz Ahmad

Munna Sarfraz Ahmad — Mon, 17 Sep 2007 10:49:16 +0000

Hi This User defined function will return the no. of days in a month

CREATE FUNCTION [dbo].[ufn_GetDaysInMonth](
@CurrentDate DATETIME )
RETURNS INT
AS
BEGIN
DECLARE @ReturnDays INT
SET @ReturnDays =
CASE WHEN MONTH(@CurrentDate) IN (1, 3, 5, 7, 8, 10, 12) THEN 31
WHEN MONTH(@CurrentDate) IN (4, 6, 9, 11) THEN 30
ELSE
CASE WHEN (YEAR(@CurrentDate) % 4 = 0 AND YEAR(@CurrentDate) % 100 != 0) OR (YEAR(@CurrentDate) % 400 = 0) THEN 29
ELSE 28
END
END
RETURN @ReturnDays
END

–SELECT dbo.ufn_GetDaysInMonth(GETDATE()) No_Of_Days_In_Month
GO

By: ryan

ryan — Wed, 12 Sep 2007 21:08:02 +0000

Hello, Expert

I’m using Transact-Query, how I select a particular month out of in different years in the database?

The format column field 2005/08/26…….

thanks you
ryan,

By: pinaldave

pinaldave — Mon, 10 Sep 2007 16:09:35 +0000

Thanks Simon,

I have used similar logic many times. I just decided to do something different. You can check other datetime related articles here.

http://blog.sqlauthority.com/tag/sql-datetime/

Regards,
Pinal Dave ( http://www.SQLAuthority.com )

By: Simon Worth

Simon Worth — Mon, 10 Sep 2007 15:38:46 +0000

You really don’t need to do the math, you can just get the last day of the month using built in date functions and assign that to your return variable. This is built in for you so you don’t have to worry about leap years or anything

CREATE FUNCTION [dbo].[udf_GetNumDaysInMonth] ( @myDateTime DATETIME )
RETURNS INT
AS
BEGIN
DECLARE @rtDate INT
SET @rtDate = DATEPART(dd, DATEADD(ms,-3,DATEADD(mm, DATEDIFF(m,0,@myDateTime)+1, 0)))
RETURN @rtDate
END
GO