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SQL SERVER – Find Monday of the Current Week

August 20, 2007 by pinaldave

Very Simple Script which find Monday of the Current Week
SELECT DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0) MondayOfCurrentWeek

Reference : Pinal Dave (http://blog.SQLAuthority.com)

Posted in Pinal Dave, SQL, SQL Authority, SQL DateTime, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQL Utility, T SQL, Technology | 21 Comments

21 Responses

on January 5, 2008 at 12:25 am | Reply Chris Bowie

Your articles are very helpful. Thanks for the public service.
on January 16, 2008 at 4:35 pm | Reply Hemaraj

Your solutions are extremely useful. Thanks a ton brother
on February 13, 2009 at 9:59 am | Reply Srinivasan

Dear Pinal Dev…

I have never found a simpler scripts in date functions any where in the world … Hats offf….
on May 8, 2009 at 8:40 pm | Reply Dan Richardson

simple, to-the-point answers – perfect every time.
Thanks a bunch! :)
on May 14, 2009 at 8:05 pm | Reply Dave M.

Awesome! Perfect solution as always! Many thanks…..
on June 19, 2009 at 6:45 pm | Reply Marius

This does not work. Here is an example:

DECLARE @TODAY DATETIME
SET @TODAY = ‘June 14, 2009′

SELECT

@TODAY AS TODAY,
LAST_MONDAY = DATEADD(wk, DATEDIFF(wk,0,@TODAY), 0)

:-)
on July 15, 2009 at 3:44 pm | Reply Ziplodocus

I believe that is because Sunday is classed as the first day of the week.

Therefore when the date is a Sunday, the Monday of the current week is tomorow.

:)
on August 28, 2009 at 1:00 am | Reply cimnil

How to find Monday of last week?
on August 28, 2009 at 5:41 pm | Reply Brian Tkatch

@cimnil

Find Monday of this week , and use DATEADD to subtract 7 days.
on September 29, 2009 at 3:23 am | Reply vijaianand

Perfect job. Thanks
- on November 10, 2009 at 6:52 pm | Reply ColSchmoll
  
  “I believe that is because Sunday is classed as the first day of the week.”
  
  If I set Monday to be the first day of the week it still doesn’t work.
  
  SET DATEFIRST 1;
  DECLARE @TODAY DATETIME ;
  SET @TODAY = ‘June 14, 2009′ ;
  SELECT
  @TODAY AS TODAY,
  LAST_MONDAY = DATEADD(wk, DATEDIFF(wk,0,@TODAY), 0)
  
  returns:
  
  TODAY LAST_MONDAY
  2009-06-14 00:00:00.000 2009-06-15 00:00:00.000
on November 20, 2009 at 1:31 am | Reply gus

Try this:
DATEADD(wk, DATEDIFF(d, 0, GETDATE()) / 7, 0).

This works because 1/1/1900 (i.e. ’0′) was a Monday so you are basically dividing the days since then by 7 days exactly.

FYI – you can also find the day of the week based on a Monday start date (i.e. Monday = 0, Tuesday = 1, etc.) by using “% 7″ instead of “/ 7″.
on March 10, 2010 at 9:55 pm | Reply DBA100

The statement RETURN (DATEADD(wk, DATEDIFF(wk, 0,@CURRENTDATE),0))
doesn’t return the date of last monday.

I get the value for ,@CURRENTDATE = 11 03 2010, and the whole thing return 08 mar 2010, which is THIS monday, not the last one.

what if I want to run a script in any time and the result must return the date of last monday, last tuesday til last friday.

Any way to do it?
on March 10, 2010 at 9:56 pm | Reply DBA100

The statement RETURN (DATEADD(wk, DATEDIFF(wk, 0,@CURRENTDATE),0))
doesn’t return the date of last monday.

I get the value for ,@CURRENTDATE = 11 03 2010, and the whole thing return 08 mar 2010, which is THIS monday, not the last one.

Any query can give me the date of last monday til last friday, this mean I need 5 days no matter what day I run the script.
on July 6, 2010 at 11:23 pm | Reply Jim

Pinal Dave – Thanks SO much – I have seen your posts before but this one gave me exactly what I wanted. and so simple… a summary for the week beginning on monday was MUCH simpler with this small bit of code! you are the BEST!
on September 3, 2010 at 8:31 am | Reply erwin

nice piece of script. simple yet effective!
on March 2, 2011 at 4:33 am | Reply GS

I tried to find Wednesday of the current week on the same lines, but was not successful. Can you pl. help.
For any given date, I need the Wednesday of that week.

Thanks in advance,
GS
- on March 3, 2011 at 1:54 pm | Reply madhivanan
  
  Try this
  
  select dateadd(week,datediff(week,0,getdate()),0)+2
on August 18, 2011 at 2:53 am | Reply Nagesh

Hi There,

Dave’s tit bit is perfect for defalut date caliculations. i.e. by defauls Sunday is considerded as first day of week in US.

if you want to consider monday as first day of the week you may use the below tit bit.

SET DATEFIRST 1
select (DateAdd(d, – (DatePart(dw,’2011-08-21′) -1), ’2011-08-21′))
on August 25, 2011 at 8:55 pm | Reply DBWhisperer

Since you helped me out here, I’ll pass along what it was exactly you helped me with. This query builds a result set that lists all the weeks in the past year for a view or function:

WITH CTE_PastYearinWeeks
AS (
select
/* Thanks to SQL Authority for below. It gets the number of weeks between now and the beginning of (sql) time and adds it to the beginning of (sql) time, thus setting it to the first day of the week! */
DATEADD(wk, DATEDIFF(wk,0,GETDATE()-365), 0) as DateStart
UNION ALL
SELECT DATEADD(WK,1,DateStart)
FROM CTE_PastYearinWeeks
WHERE DATEADD(WK,1,DateStart) <= GETDATE()
–and DATEPART(YYYY,DateStart) <= DATEPART(YYYY,GETDATE())
)
select DATEPART(YYYY,DateStart) as YearNum
, DATEPART(WK,DateStart) as WeekNum
, SUBSTRING(CONVERT(varchar, DateStart, 107),1,6) + ' – ' + CONVERT(varchar, DATEADD(DD,6,DateStart), 107) as WeekTitle
from CTE_PastYearinWeeks
OPTION (MAXRECURSION 0);
on January 30, 2012 at 3:07 pm | Reply gobi

how to find next week your birthday alert using sql