Comments on: SQL SERVER – Find Last Day of Any Month – Current Previous Next

By: Subir Sankar Das

Subir Sankar Das — Tue, 30 Apr 2013 11:23:29 +0000

Last Year last month (if today is 30-Apr-2013, it should reflect 30-Apr-2012)

By: Rahul Dewada

Rahul Dewada — Thu, 18 Apr 2013 07:22:01 +0000

Hi Dear,

Very Important article of SQL Developers
Thank you.

By: madhivanan

madhivanan — Fri, 15 Feb 2013 13:07:21 +0000

You can find lot of such methods at the bottom section of http://beyondrelational.com/modules/2/blogs/70/posts/10899/understanding-datetime-column-part-iii.aspx

By: Luis Vela

Luis Vela — Wed, 13 Feb 2013 17:07:22 +0000

Just Create this Stored Procedure in a Data Base
And call it
============================
USE [TestDataBase]
GO
/****** Object: UserDefinedFunction [dbo].[LAST_DAY] Script Date: 11/08/2012 00:48:07 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
– =============================================
– Author: Luis R. Vela Morales
– Create date: 01/11/2012
– Description: De una fecha dada, retorna la
– fecha con el ultimo dia del mes,
– esto decrementando, sin afectar o
– incrementando en ‘n’ meses
– ( -n, 0, n).
– =============================================
CREATE FUNCTION [dbo].[LAST_DAY]
(
– Add the parameters for the function here
@Fecha datetime,
@Intervalo int
)
RETURNS datetime
AS
BEGIN
– Declare the return variable here
DECLARE @Result datetime

– Add the T-SQL statements to compute the return value here
SELECT @Result = DATEADD(day,-day(DATEADD(mm, 1+@Intervalo,@Fecha)),DATEADD(mm, 1+@Intervalo,@Fecha))

– Return the result of the function
RETURN @Result
END

By: madhivanan

madhivanan — Wed, 13 Feb 2013 13:38:04 +0000

declare @date datetime
set @date=’20120101′
select dateadd(month,datediff(month,0,dates)+1,-1) as last_day from
(
select dateadd(month,number,@date) as dates from master..spt_values
where type=’p’ and number between 0 and 6
) as t

By: Satya

Satya — Wed, 30 Jan 2013 10:47:27 +0000

I want exact month end date so

declare @date datetime
set @date=’31-jan-2012′
while @date<='31-jul-2012'
Begin
print @date
set @date= DATEADD(M,1,@date)
End
but i'm getting result like
Jan 31 2012 12:00AM
Feb 29 2012 12:00AM
Mar 29 2012 12:00AM
Apr 29 2012 12:00AM
May 29 2012 12:00AM
Jun 29 2012 12:00AM
Jul 29 2012 12:00AM
Please help me to get exact month end date

By: Pablo Maria

Pablo Maria — Thu, 24 Jan 2013 23:44:55 +0000

Thank you very much for your post !

By: Devashish Das

Devashish Das — Tue, 22 Jan 2013 11:29:12 +0000

–Alter Nate Method
DECLARE @MyDate DATETIME
SET @MyDate = ’26-Jul-2013′

– Previous Month
SELECT DATEADD(d, -1*day(@MyDate), @MyDate)
– Given Month
SELECT DATEADD(d, -1*day(@MyDate), DATEADD(mm,1,@MyDate))
– Next Month
SELECT DATEADD(d, -1*day(@MyDate), DATEADD(mm,2,@MyDate))

By: Devashish Das

Devashish Das — Tue, 22 Jan 2013 11:23:48 +0000

–Alternate method

DECLARE @MyDate DATETIME
SET @MyDate = ’26-Jul-2013′

SELECT DATEADD(d, -1*day(@MyDate), DATEADD(mm,-1,@MyDate))
SELECT DATEADD(d, -1*day(@MyDate), @MyDate)
SELECT DATEADD(d, -1*day(@MyDate), DATEADD(mm,1,@MyDate))

By: harsh

harsh — Mon, 21 Jan 2013 12:09:56 +0000

select GETDATE()- DAY(GETDATE())
or
select EOMONTH(GETDATE(),-1) /* in SQL 2012*/
will give same result

By: Manoj Sahoo

Manoj Sahoo — Mon, 21 Jan 2013 10:45:46 +0000

for Last Date of previous month

select DATEADD(D,-( DATEPART(D,GETDATE())),GETDATE())

By: Dipanjan

Dipanjan — Mon, 31 Dec 2012 07:58:58 +0000

I need a solution …
Here are the details….
Step a) I will select a month and year(eg. January 2012) from UI.
Step b) It should return four months back data (only month number).
for this purpose i am trying to use datediff(m,,) function, this is perfectly working for current year( from May to December month).

but when i am selecting January month it is returning current years September month but i need to get last year’s September month. Same as for February, March, April month.

Please help.

By: Gopal Singh

Gopal Singh — Sat, 10 Nov 2012 06:33:49 +0000

Thnks sir providing code for getting last date of previous month in sql server.

By: Luis Vela

Luis Vela — Thu, 08 Nov 2012 06:52:30 +0000

USE [TestDataBase]
GO
/****** Object: UserDefinedFunction [dbo].[LAST_DAY] Script Date: 11/08/2012 00:48:07 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
– =============================================
– Author: Luis R. Vela Morales
– Create date: 01/11/2012
– Description: De una fecha dada, retorna la
– fecha con el ultimo dia del mes,
– esto decrementando, sin afectar o
– incrementando en ‘n’ meses
– ( -n, 0, n).
– =============================================
CREATE FUNCTION [dbo].[LAST_DAY]
(
– Add the parameters for the function here
@Fecha datetime,
@Intervalo int
)
RETURNS datetime
AS
BEGIN
– Declare the return variable here
DECLARE @Result datetime

– Add the T-SQL statements to compute the return value here
SELECT @Result = DATEADD(day,-day(DATEADD(mm, 1+@Intervalo,@Fecha)),DATEADD(mm, 1+@Intervalo,@Fecha))

– Return the result of the function
RETURN @Result
END

By: Luis Vela

Luis Vela — Wed, 07 Nov 2012 20:26:29 +0000

DECLARE @MyDate datetime
SET @MyDate=’15/03/1977′
DECLARE @Interval int
SET @Interval=0

SELECT DATEADD(day,-day(@MyDate),DATEADD(mm, 1+@Interval,@MyDate))

By: tsonev8

tsonev8 — Wed, 07 Nov 2012 13:43:44 +0000

Hi. Thanks for the post.

This returns 2012-10-31 23:59:59.000

How to make it to return 2012-10-31 00:00:00 000 ?

By: Abhishek Dwivedi

Abhishek Dwivedi — Fri, 21 Sep 2012 09:07:12 +0000

Awesome! Thanks a lot, this is what I was looking for.

-Abhi

By: Velmurugan

Velmurugan — Fri, 14 Sep 2012 07:42:21 +0000

Hi,

I am trying yo replicate the ‘n’th week and nth day of that week from the defined calender table. can anyone help me in writing query for the same, thanks..

Velmurugan

By: madhivanan

madhivanan — Thu, 06 Sep 2012 09:45:56 +0000

Look at the examples posted at the bottom of this post and you will have an idea
http://beyondrelational.com/modules/2/blogs/70/posts/10899/understanding-datetime-column-part-iii.aspx

By: Shine

Shine — Wed, 05 Sep 2012 13:27:59 +0000

i need to get the tranaction details happend between current date and same date of prevoius month.how can i .pls help

By: JimmyMcWizard

JimmyMcWizard — Fri, 31 Aug 2012 21:55:35 +0000

There’s a way shorter method in SQL Server 2012:

SELECT [MonthEnd] = EOMONTH()

Enjoy.

By: Mike

Mike — Fri, 24 Aug 2012 14:23:15 +0000

I use this code to return the last friday in any month:

SELECT DATEADD(day, (DATEDIFF (day, ’2010-01-01′, (SELECT DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0)))) / 7) * 7, ’2010-01-01′) AS “LAST_FRIDAY_OF_MONTH”

By: Amit

Amit — Thu, 26 Jul 2012 09:10:23 +0000

How do I find the last 12 months from a given date including the current month. For example:
If the given date is 15-Jan-2012
It should return; jan 2012, dec 2011, nov 2011, oct 2011, sept 2011, aug 2011, july 2011, june 2011, may 2011, apr 2011, mar 2011, feb 2011

or if the given date is 31-Dec-2011
It should return; dec 2011, nov 2011, oct 2011, sept 2011, aug 2011, july 2011, june 2011, may 2011, apr 2011, mar 2011, feb 2011, jan 2011

By: Fred

Fred — Sun, 15 Jul 2012 15:47:24 +0000

Thanks a lot mate.

By: Bill G

Bill G — Tue, 03 Jul 2012 20:27:12 +0000

thanks dude; i was trying to write a sql script.