I need help in A stored procedure.
I have to calculate a parameter only on week days,
For eg if i give input date to be 10th october(Sunday) and today is 28th october.

I have to calculate these parameters for 5 weekdays..
So if i give A date which is a sunday then it should automatically skip that day and should calculate from Monday to friday.

Another eg. Suppose the input date is a wednesday, then calculate the parameters for wednesday, thursday, friday, moday and tuesday.

Skipping the Saturday and sunday.

Could you please suggest a way out of this.

:D

– Drop function if exists
IF EXISTS (SELECT * FROM dbo.sysobjects WHERE [id] = OBJECT_ID(N’[dbo].[IsHolliday]‘) AND xtype IN (N’FN’, N’IF’, N’TF’)) DROP FUNCTION [dbo].[IsHolliday]
GO

– Create function
CREATE FUNCTION dbo.IsHolliday
– +————————————————————————–+
– | Function : IsHolliday |
– | Author : Martin Grape |
– | Version : 1.1 |
– | Description : Returns 1 for holliday and 0 for all other days |
– | Parameters : @IsHolliday – Date to check |
– | Returns : 0 (workday) or 1 (holliday) |
– | Other : This is calculation for Swedish hollidays |
– | Example : SELECT dbo.IsHolliday(’2010-04-04′) –> 1 |
– +————————————————————————–+
(
@IsHolliday DATETIME
)
RETURNS INT
AS
BEGIN
— Declare variables
DECLARE @IsHollidayResult INT
DECLARE @IsHollidayYear INT
DECLARE @IsHollidayMonth INT
DECLARE @IsHollidayDay INT
DECLARE @IsHollidayMonthDay VARCHAR(5)
DECLARE @IsHollidayEasterDate DATETIME

— Declare variables
SET @IsHollidayYear = YEAR(@IsHolliday)
SET @IsHollidayMonth = MONTH(@IsHolliday)
SET @IsHollidayDay = DAY(@IsHolliday)
SET @IsHollidayMonthDay = RIGHT(CONVERT(CHAR(10), @IsHolliday, 120), 5)

— Set starting values
SET @IsHollidayResult = 0

— Check for set dates (this is for Sweden)
SET @IsHollidayResult = CASE WHEN @IsHollidayMonthDay IN (’01-01′, ’01-06′, ’05-01′, ’12-25′, ’12-26′) THEN 1 ELSE @IsHollidayResult END
SET @IsHollidayResult = CASE WHEN @IsHollidayResult = 0 AND @IsHollidayMonthDay = ’06-06′ AND @IsHollidayYear > 2004 THEN 1 ELSE @IsHollidayResult END

— Return if a set date
IF @IsHollidayResult = 1 BEGIN
RETURN @IsHollidayResult
END

— Calculate easter date
SET @IsHollidayEasterDate = CONVERT(DATETIME, CONVERT(CHAR(4), @IsHollidayYear) + ‘-’ +
RIGHT(’00′ + CONVERT(VARCHAR, CONVERT(INT, ((((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) + (((32 + 2 * ((CONVERT(INT, @IsHollidayYear / 100)) % 4) + 2 * (CONVERT(INT, (@IsHollidayYear % 100) / 4)) – (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) – ((@IsHollidayYear % 100) % 4)) % 7)) – 7 * (CONVERT(INT, ((@IsHollidayYear % 19) + 11 * (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) + 22 * (((32 + 2 * ((CONVERT(INT, @IsHollidayYear / 100)) % 4) + 2 * (CONVERT(INT, (@IsHollidayYear % 100) / 4)) – (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) – ((@IsHollidayYear % 100) % 4)) % 7))) / 451)) + 114) / 31)), 2) + ‘-’ +
RIGHT(’00′ + CONVERT(VARCHAR, (((((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) + (((32 + 2 * ((CONVERT(INT, @IsHollidayYear / 100)) % 4) + 2 * (CONVERT(INT, (@IsHollidayYear % 100) / 4)) – (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) – ((@IsHollidayYear % 100) % 4)) % 7)) – 7 * (CONVERT(INT, ((@IsHollidayYear % 19) + 11 * (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) + 22 * (((32 + 2 * ((CONVERT(INT, @IsHollidayYear / 100)) % 4) + 2 * (CONVERT(INT, (@IsHollidayYear % 100) / 4)) – (((19 * (@IsHollidayYear % 19) + (CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) / 4)) – (CONVERT(INT, ((CONVERT(INT, @IsHollidayYear / 100)) – (CONVERT(INT, (CONVERT(INT, @IsHollidayYear / 100)) + 8) / 25) + 1) / 3)) + 15) % 30)) – ((@IsHollidayYear % 100) % 4)) % 7))) / 451)) + 114) % 31) + 1), 2))

— Easter
IF @IsHolliday = @IsHollidayEasterDate – 2 OR
@IsHolliday = @IsHollidayEasterDate OR
@IsHolliday = @IsHollidayEasterDate + 1 BEGIN
RETURN 1
END

— Ascension Day
IF @IsHolliday = DATEADD(dd, 39, @IsHollidayEasterDate) BEGIN
RETURN 1
END

— Whitsun
IF @IsHolliday = DATEADD(dd, 49, @IsHollidayEasterDate) OR
(@IsHolliday = DATEADD(dd, 50, @IsHollidayEasterDate) AND @IsHollidayYear < 2005) BEGIN
RETURN 1
END

— Midsummer
IF @IsHolliday = DATEADD(dd, 7 – DATEPART(dw, CONVERT(CHAR(4), @IsHollidayYear) + '-06-20'), CONVERT(CHAR(4), @IsHollidayYear) + '-06-20') BEGIN
RETURN 1
END

— Halloween
IF @IsHolliday = DATEADD(dd, 7 – DATEPART(dw, CONVERT(CHAR(4), @IsHollidayYear) + '-10-31'), CONVERT(CHAR(4), @IsHollidayYear) + '-10-31') BEGIN
RETURN 1
END

RETURN 0
END
GO

CREATE FUNCTION dbo.udfGetPrevNextWorkDay
(
@StartDate DATETIME,
@bGetPrevious BIT = 0,
@bExcludeHolidays BIT = 1,
@MultipleDayCount INT = 0
)
RETURNS DATETIME
AS
BEGIN

DECLARE @EndDate DATETIME, @Day NVARCHAR(10), @DayCount INT
SET @Day = DATENAME(weekday, @StartDate)

IF @MultipleDayCount > 0
BEGIN
DECLARE @MultipleDayIndex INT, @MultipleDayDate DATETIME
SET @MultipleDayDate = @StartDate
SET @MultipleDayIndex = 1

WHILE @MultipleDayIndex < @MultipleDayCount
BEGIN
SELECT @MultipleDayDate = dbo.udfGetPrevNextWorkDay(@MultipleDayDate, @bGetPrevious, @bExcludeHolidays, 0)
SET @MultipleDayIndex = @MultipleDayIndex + 1
END
RETURN @MultipleDayDate
END

–To find Previous working day
IF @bGetPrevious = 1
BEGIN
SELECT @DayCount =
CASE @Day WHEN 'Sunday' THEN -2
WHEN 'Monday' THEN -3
ELSE -1
END
END

–To find Next working day
IF @bGetPrevious = 0
BEGIN
SELECT @DayCount =
CASE @Day WHEN 'Friday' THEN 3
WHEN 'Saturday' THEN 2
ELSE 1
END
END

SET @EndDate = DATEADD(d,@DayCount,@StartDate)

IF (@bExcludeHolidays = 1) AND (EXISTS(SELECT * FROM tblzcdIndexHoliday WHERE IndexHolidayCelebrationDate = @EndDate))
BEGIN
SELECT @EndDate = dbo.udfGetPrevNextWorkDay(@EndDate, @bGetPrevious, @bExcludeHolidays, 0)
END

RETURN ISNULL(@EndDate, @StartDate)
END

IF EXISTS(SELECT * FROM tblHolidays WHERE HolidayDate = @EndDate)
BEGIN
SELECT @EndDate = dbo.udf_GetPrevNextWorkDay(@EndDate, @strPrevNext)
END

for example(table form): this shoul be the output:

customer—-trans_amt—-payments—trans_date—-balance
robert——–200————–10———-1-1-09———-190
robert——–200————–50———-1-5-09———-140
robert——–200————–60———-1-7-09———-80

i want to get balance for every trans_date

please help me
thanks

robert

for example(table form): this shoul be the output:

customer trans_amt payments trans_date balance
robert 200 10 1-1-09 190
robert 200 50 1-5-09 140
robert 200 60 1-7-09 80

i want to get balance for every trans_date

please help me
thanks

robert

Works well for me…

I need a help from u.

I am having a field name issueDate datatype as smalldatetime.
I need this field and also the previous date

ex: Item id ItemName IssueDate
1023 XXXX 12/02/2009
1023 XXXX 13/02/2009

I need the answer is diff between the 13/02/2009(LastDate) – 12/02/2009(previous date)

How would I modify this Function to do this?

You mean this ??

select datename(dd,getdate()+8)
Result: 25

select datename (dw,getdate() +8)
Result : Friday –(if today is July 17, Thursday)

I am looking for a function through which I can calculate a particular working day. let say I want to know the 8th working day from todays date.

Any help??? its urgent..

Thanks in advance.

Rahul

When I tried using date diff between Quarters for different Years it does not work.. any help here is appreciated

Good-Luck!

for example if substring(eventstartdttm, 0,9) returns 30th Jan 2008 then I need it to say Wednesday. Is there a function that can help me do that? Thanks

Warm Regards,
Chitra