select ID,case
when (select distinct 1 from table2 where table1.ID=table2.ID)=1
then value+’ EXIST’
else
value+’ NOT EXIST’
end
as status
from table1

any better solution would be appreciable..

Thanks,
Deepak

I want to fetch the records from table1 having primary key ID but 1 column value depends on the condition and condition is : if ID is available in another table then column value should be “ColumnValue EXIST” if Not in another table then “ColumnValue NOT EXIST”.

Means I want to append some text to that column based on condition.

Thanks,
Deepak

Employee Address

1 Dorababu 1 XYZ
2 Vivekh 1 XYZ
3 Kaashyap 2 ABC

I would like to display all the employees who is having same address, I tried using joins but I am getting duplicates can some one help me

Your solution worked perfectly for me with a minor tweak to meet my desired outcome. Thank you!

I have a list of product widgets, and we get the same product from different factories. I want to know how many are duped accross which facttories

ProductName, FactoryName
Smith Widget, Factory1
Smith Widget, Factory2
Smith Widget, Factory3
Dave Widget, Factory1
Dave Widget, Factory4
Claire Widget, Factory1
Claire Widget, Factory2
Claire Widget, Factory3
Claire Widget, Factory4

A) What I want is a SQL statement that gives a list of those Widgets that are suppled from Factory1 and Factory3

So for Factory 1 and Factory 3

Product,
Smith Widget,
Claire Widget

B) What would be amazing is

Name, Duplicates
“Factory 1 & Factory 2″, 2 Dups
“Factory 2 & Factory 3″, 2 Dups
“Factory 1 & Factory 3″, 2 Dups
“Factory 1 & Factory 4″, 1 Dups
“Factory 2 & Factory 4″, 0 Dups
“Factory 3 & Factory 4″, 1 Dups

SELECT Field1, Field2, MIN(Field3) AS Min, MAX(Field3) AS Max, COUNT(*) AS TotalCount
FROM (SELECT Field1, Field2, Field3
FROM Tablename
WHERE [Criteria here]
GROUP BY Field1, Field2, Field3) AS FilteredDetail
GROUP BY Field1, Field2
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC

select column1,column2,column3 from
(
select *,row_number() over (partition by column1 order by column1) as sno from table
) as t
where sno=1

Request you to take some time from your busy schedule to provide the guidelines (Solution) for my query above.

Thanks

id Created date

12343 05/15/2012
12345 05/15/2012
12121 05/16/2012
12369 05/19/2012
12371 05/19/2012
12343 05/22/2012
12888 05/22/2012
12411 05/25/2012
12121 06/06/2012
12125 06/06/2012

Total Record Create Date
2 05/15/2012
1 05/16/2012
2 05/19/2012
1 05/22/2012 (Repeat ID 12343 so not count that id)
1 05/25/2012
1 06/06/2012 (Repeat ID 121121 so not count that id)

Can you help me by providing the solution to my above query. It is some what urgent. Please…

My query’s Present Output
column1 column2 column3
abc xyz pqr
abc – klm
ijk – uvw
plo – ujn
yhk ttg wea
yhk – erf

Expected Output
column1 column2 column3
abc xyz pqr
ijk – uvw
plo – ujn
yhk ttg wea

Can someone help me. Thanks in advance.

Q_ID, Q_Status_CD, Q_MatchKey, Q_Fulfilled

I want to find all records with more than one matching Matchkey so I can use:

SELECT Q_ID, Q_Status_CD, Q_MatchKey, Q_Fulfilled_DT
FROM MyTable
WHERE Q_Fulfilled_DT Is NULL
Having Count(Q_Matchkey) > 1

This works fine for showing all duplicates. Where I am struggling is that I need to update the Q_FULFILLED_DT field on the FIRST entry with a date as well as set the Q_STATUS_CD = 1 (valid), then on all other records set the Q_STATUS_CD = 2 (in-valid). I found a work around to do this by first setting all duplicates to invalid, then finding the duplicates and by using MIN(Q_ID) to isolate the first record and then I reset the Status and Fulfilled date fields on that individual record.

This solution would be fine, except this is part of a weekly SQL job and it resets all duplicates each week and therefore places a duplicate order for that first record each week by changing the fulfilled date to the current week. I want to only update the first record when there isn’t one with a Fulfilled date already in the duplicate set. I’m not sure if this makes sense.

Delete from Employee_Profile where EmpNo NOT IN
(select EmpNo from Boss_Employee_Profile
where EmpNo =’21097′ , ’21097A’)

Sometimes, you need to find out a given column is duplicated for a given other column: if you have different values for the same value
(mostly a foreign key).

In this case, you count a nested select:

SELECT ID, COUNT(field) AS duplicate
FROM (SELECT DISTINCT ID, field
FROM Table) s
GROUP BY ID
HAVING (COUNT(field) > 1)