i mean, the result should be in a table like that..

Number
3
323
111

not scalar varchar value…

Thanks

Reply to Asif,

@Asif

CREATE FUNCTION [dbo].[UFN_Eliminate_Alphabet] (@string varchar(max))
RETURNS int
AS
BEGIN
DECLARE @result varchar(50)
DECLARE @position int
SET @position = 1
SET @result = ”

WHILE @position <= DATALENGTH(@string)
BEGIN
SELECT @result = @result + case when (ASCII(SUBSTRING(@string, @position, 1))) between 48 and 57 then SUBSTRING(@string, @position, 1)
else ''
end
SET @position = @position + 1
END
RETURN ( select convert ( int, @result))
END
GO
– Sample to Execute
select [dbo].[UFN_Eliminate_Alphabet]('abc64h5n5u')
GO
CREATE FUNCTION [dbo].[UFN_Eliminate_Numbers] (@string varchar(max))
RETURNS varchar (max)
AS
BEGIN
DECLARE @result varchar(50)
DECLARE @position int
SET @position = 1
Set @result = ''
WHILE @position <= DATALENGTH(@string)
BEGIN
SELECT @result = @result + case when ASCII(SUBSTRING(@string, @position, 1)) between 97 and 122 then SUBSTRING(@string, @position, 1)
when ASCII(SUBSTRING(@string, @position, 1)) between 65 and 90 then SUBSTRING(@string, @position, 1)
else ''
end
SET @position = @position + 1
END
RETURN ( select @result As ID )
END
GO
– Sample to Execute
select [dbo].[UFN_Eliminate_Numbers]('abc64h5n5u')
GO

First function

CREATE FUNCTION [dbo].[UFN_Eliminate_Alphabet] (@string varchar(max))
RETURNS int
AS
BEGIN
DECLARE @result varchar(50)
DECLARE @position int
SET @position = 1
SET @result = ”

WHILE @position <= DATALENGTH(@string)
BEGIN
SELECT @result = @result + case when (ASCII(SUBSTRING(@string, @position, 1))) between 48 and 57 then SUBSTRING(@string, @position, 1)
else ''
end
SET @position = @position + 1
END
RETURN ( select convert ( int, @result))
END
GO
– Sample to Execute
select [dbo].[UFN_Eliminate_Alphabet]('abc64h5n5u')

~IM

@Asif

CREATE FUNCTION [dbo].[UFN_Eliminate_Alphabet] (@string varchar(max))
RETURNS int
AS
BEGIN
DECLARE @result varchar(50)
DECLARE @position int
SET @position = 1
SET @result = ”

WHILE @position <= DATALENGTH(@string)
BEGIN
SELECT @result = @result + case when (ASCII(SUBSTRING(@string, @position, 1))) between 48 and 57 then SUBSTRING(@string, @position, 1)
else ''
end
SET @position = @position + 1
END
RETURN ( select convert ( int, @result))
END
GO
– Sample to Execute
select [dbo].[UFN_Eliminate_Alphabet]('abc64h5n5u')
GO
CREATE FUNCTION [dbo].[UFN_Eliminate_Numbers] (@string varchar(max))
RETURNS varchar (max)
AS
BEGIN
DECLARE @result varchar(50)
DECLARE @position int
SET @position = 1
Set @result = ''
WHILE @position <= DATALENGTH(@string)
BEGIN
SELECT @result = @result + case when ASCII(SUBSTRING(@string, @position, 1)) between 97 and 122 then SUBSTRING(@string, @position, 1)
when ASCII(SUBSTRING(@string, @position, 1)) between 65 and 90 then SUBSTRING(@string, @position, 1)
else ''
end
SET @position = @position + 1
END
RETURN ( select @result As ID )
END
GO
– Sample to Execute
select [dbo].[UFN_Eliminate_Numbers]('abc64h5n5u')
GO

Please provide sample output.

account
1235abcd7412
abcfd52a1a2
ghti5214ve3
asif214bv2

nofixed length account column plz show me easy query

thanks
asif

select substring ( ‘50.00 on 04/06/2009′, 1, charindex (‘.’, ‘50.00 on 04/06/2009′)+2)

~IM

Because the minimum digit is 0 and maximum digit is 9.

Regards,
IM.

what is the purpose of 9 here?

Moreno

Please replace the middle part of the query with this, I dont know how the query is changed, this is not the one I posted… I executed this query atleast 10 times befire posting…. There must be something wrong happened while posting my reply,

anyways I apologize for any inconvenience caused,

Please replace this query in the end of the code

– This is Actual Script
declare @var int
declare @var2 int
declare @car varchar(100)
declare @len int
declare @res varchar(100)
declare @result varchar(100)
declare @store varchar(100)
set @var = 1
while @var < = ( select count(*) from #result)
begin
select @car = names from #result where id = @var
set @result = ”
set @len = 1
while @len 64 and ascii(@store) 64 and ascii (@store) < 123 — This is the correct script

set @result = @res+@result
end
set @len= @len+1
end
if @result ”
begin
insert into #results select reverse(@result)
end
set @var= @var+1
end
select * from #results
drop table #results
drop table #result
drop table example123
– End of Script

Hope this helps.
Imran.

I am sure there must be be another good way of doing the same thing…. I came up with this… This is HIGHLY performance killing query… since this is a while loop under while loop.

Its your choice if you want to use this…

This does exactly what you want.

Here you go…

– This is your main table
create table example123 ( names varchar(max))
go
– Inserting Sample Data
insert into example123 values ( ‘AK48148′)
insert into example123 values ( ‘D144432′)
insert into example123 values ( ‘MT23432′)
insert into example123 values ( ‘DT55544′)
insert into example123 values ( ‘12345′) — This will not be displayed in the output since it do no have any letter in it

– This is the output or result table
create table #results ( names varchar(100))
go
– This is our sample original table
create table #result ( id int identity, names varchar(100))
go
– We are copying your data into this sample original table
insert into #result select names from example123
go
– This is Actual Script
declare @var int
declare @var2 int
declare @car varchar(100)
declare @len int
declare @res varchar(100)
declare @result varchar(100)
declare @store varchar(100)
set @var = 1
while @var < = ( select count(*) from #result)
begin
select @car = names from #result where id = @var
set @result = ”
set @len = 1
while @len < = ( select len(@car) from #result where id = @var)
begin
select @store = substring ( @car, @len, len(@car)) from #result where id = @var
if ascii( @store) 64
begin
select @res = char(Ascii (@store)) from example123 where ascii( @store) 64
set @result = @res+@result
end
set @len= @len+1
end
if @result ”
begin
insert into #results select reverse(@result)
end
set @var= @var+1
end
select * from #results
drop table #results
drop table #result
drop table example123
– End of Script

I am not sure if there is any function already to do this, if you want to change the code, you are more than welcome, if something better can written for same, please post

Hope this helps,
Imran.

So I want a function that just extract the letters from it.
I would appreciate your time.

Thanks

First of all, thank you for taking time to write t-sql and publish it.

Second, I would like to point out that substring is 1 based instead of 0 based (in SQL 2000 Sp3 at least but should remain the same for other versions as well)

What does it mean? Little beside that 0 based loop one time more than it really need. (One loop is wasted)

The fix? Set @count = 1 for the starting condition instead of @count=0

person A at 2006 345 15:24 See attachment from Ron Holden person B at 2006 361 16:20 Refer to AR 113831.

i would like output will be like : 2006 345 15:24

I ready appreciate for all your helped and supported. I looking forward to hear from you soon.

Big Thanks,

Tammy