You should fetch first record before entering in to the loop. Next fetch statement should come after select @PhoneNum = @PhoneNum + (@telno + ‘ ‘) statement

That should return you good results

Just add an aggregate to salid. Because it is always one value, using an aggregate won’t change anything. Also, the HAVING can be just COUNT(*). No reason to mention salary, the GROUP BY on salary takes care of that:

WITH
salary(salid, salary)
AS
(
SELECT 1, 10 UNION ALL
SELECT 2, 20 UNION ALL
SELECT 3, 40 UNION ALL
SELECT 4, 10 UNION ALL
SELECT 5, 50 UNION ALL
SELECT 6, 40
)
SELECT
MAX(salid),
salary
FROM
salary
GROUP BY
salary
HAVING
COUNT(*) = 1

hi

i have s salary table

salid salary

1 10
2 20
3 40
4 10
5 50
6 40

i want out put like this
id salary

2 20
4 50
note:-no need to display repated values in above column 10 and 40 is repated values except repated values i wnt to display remaining values

plz help me

HERE is Query

select * from test where val in (select val from test group by val having count(val)=1)

CREATE TABLE TestOne
(
CourseName varchar(100),
Semester varchar(100),
StudentNumber varchar(100),
StudentName varchar(100),
Date datetime,
AttendanceStatus varchar(20)
)

insert into TestOne values(‘BA’,'I Semester’,'BC985233′,’RAJA’,'2009-07-08′,’P')
insert into TestOne values(‘BA’,'I Semester’,'AC232233′,’Sathish’,'2009-07-08′,’A')
insert into TestOne values(‘BA’,'I Semester’,'BC985233′,’RAJA’,'2009-07-10′,’A')
insert into TestOne values(‘BA’,'I Semester’,'AC232233′,’Sathish’,'2009-07-10′,’P')
insert into TestOne values(‘BA’,'I Semester’,'BC985233′,’RAJA’,'2009-07-15′,’P')
insert into TestOne values(‘BA’,'I Semester’,'AC232233′,’Sathish’,'2009-07-15′,’A')
insert into TestOne values(‘BA’,'I Semester’,'BC985233′,’RAJA’,'2009-07-20′,’P')
insert into TestOne values(‘BA’,'I Semester’,'AC232233′,’Sathish’,'2009-07-20′,’P')
insert into TestOne values(‘BA’,'II Semester’,'BC985233′,’RAJA’,'2009-07-25′,’A')
insert into TestOne values(‘BA’,'II Semester’,'AC232233′,’Sathish’,'2009-07-25′,’P')
insert into TestOne values(‘BA’,'II Semester’,'BC985233′,’RAJA’,'2009-07-30′,’P')
insert into TestOne values(‘BA’,'II Semester’,'AC232233′,’Sathish’,'2009-07-30′,’A')

DECLARE @listCol VARCHAR(2000)
DECLARE @query VARCHAR(4000)
DECLARE @query1 VARCHAR(4000)

SELECT @listCol = STUFF(( SELECT DISTINCT ‘],[' + convert(nvarchar,date,111) FROM TestOne
ORDER BY '],[' + convert(nvarchar,date,111) FOR XML PATH('')), 1, 2, '') + ']‘

–print @listCol
SET @query =
‘SELECT * FROM
(SELECT StudentName,StudentNumber,CourseName,Semester,[Date]
, AttendanceStatus
FROM TestOne) src
PIVOT (max(AttendanceStatus) FOR [Date]
IN (‘+@listCol+’)) AS pvt’

EXECUTE (@query)

Sir, Please have some patience. You asked the same question at-least 5 times in this blog. I understand this issue could be urgent but please ask your question once and have patience, your question will be answered.

Now My Response to your question.

There is no straight forward method to do this insert a new column between two existing column in a table.

Method1: Use SQL Server Management Studio (SSMS, SQL Server 2005).
Step1: Go to Object Explorer
Step2: Expand Databases
Step3: Expand Tables
Step4: Right Click Table Name Click Design /Modify.
Step5: Right Click on Table structure and click Insert Column, Check the position where you want to Insert.
Step6: Click Save.

Note: Before you Save, make sure you check, Generate Change Script (This will be one of the option in SSMS header). This will show you SQL Script that SQL Server will execute to make this change.

Method2: Drop and recreate table, In the new table script add the new column.

~ IM.

please tel me the query

thank u

thank u

SET NOCOUNT ON;

DECLARE @OrderComments Table(OrderNo INT, Comment VARCHAR(256))
INSERT INTO @OrderComments VALUES(101, ‘Hello,’)
INSERT INTO @OrderComments VALUES(101, ‘my’)
INSERT INTO @OrderComments VALUES(101, ‘friends.’)
INSERT INTO @OrderComments VALUES(102, ‘This is another’)
INSERT INTO @OrderComments VALUES(102, ‘comment’)

DECLARE @orderNo INT
DECLARE @comments VARCHAR(4000)
DECLARE @comment VARCHAR(256)

DECLARE orderList CURSOR FOR
SELECT DISTINCT OrderNo FROM @OrderComments

OPEN orderList
FETCH NEXT FROM orderList INTO @orderNo

WHILE @@FETCH_STATUS = 0
BEGIN
SET @comments = ”
DECLARE commentList CURSOR FOR
SELECT Comment FROM @OrderComments WHERE OrderNo = @orderNo

OPEN commentList
FETCH NEXT FROM commentList INTO @comment

WHILE @@FETCH_STATUS = 0
BEGIN
SET @comments = @comments + ‘ ‘ + @comment
FETCH NEXT FROM commentList INTO @comment
END

PRINT CAST(@orderNo AS VARCHAR(50)) + ‘: ‘ + @comments

CLOSE commentList
DEALLOCATE commentList

FETCH NEXT FROM orderList INTO @orderNo
END

CLOSE orderList
DEALLOCATE orderList

Here is another solution to your gender table question (2005v required):

select identity (int,1,1) id, s
into #t
from (
select ‘m’ s union all
select ‘m’ s union all
select ‘f’ s union all
select ‘m’ s union all
select ‘f’ s union all
select ‘f’ s union all
select ‘m’ s) t;

with cte as (select id, id – row_number() over (partition by s order by id) diff, s from #t)
select s from cte group by diff, s order by max(id);

drop table #t;

Regards,
Blass

Here is another solution to your gender table question (2005v required):

select identity (int,1,1) id, s
into #t
from (
select ‘m’ s union all
select ‘m’ s union all
select ‘f’ s union all
select ‘m’ s union all
select ‘f’ s union all
select ‘f’ s union all
select ‘m’ s) t;

with cte as (select id – row_number() over (partition by s order by id) diff, s from #t)
select s from cte group by diff, s;

drop table #t;

Regards,
Blass

saved records structure is

part_no indt_no
P1 i1,i2

i want output like part_no+indt_no means(p1i1 in one row,p1i2 in second row )

plz help.

Orderno Comment

101 Hello,
101 How are you

I would like to have the comments appear on a single row. For example:

Orderno Comment
101 Hello, How are you

Please Help!

please help me

i want to find out

max(sum(stMarks))

but it not work, please help me

Regards

jawad

Thank you very much

by
G.Srinivasan, M.Sc(cs)