SELECT b.TABLE_NAME,d.COLUMN_NAME,c.Table_name,e.column_name,a.CONSTRAINT_NAME FROM INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS a INNER JOIN
INFORMATION_SCHEMA.CONSTRAINT_TABLE_USAGE b
ON a.CONSTRAINT_NAME=b.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_TABLE_USAGE c ON
a.UNIQUE_CONSTRAINT_NAME=c.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE d ON
d.CONSTRAINT_NAME=a.CONSTRAINT_NAME
INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE e ON
a.UNIQUE_CONSTRAINT_NAME=e.CONSTRAINT_NAME

select new
{
CONSTRAINT_NAME = REF_CONST.CONSTRAINT_NAME,
TABLE_CATALOG = FK.TABLE_CATALOG,
TABLE_SCHEMA = FK.TABLE_SCHEMA,
TABLE_NAME = FK.TABLE_NAME,
COLUMN_NAME = FK_COLS.COLUMN_NAME,
REFERENCED_TABLE_CATALOG = FK2.TABLE_CATALOG,
REFERENCED_TABLE_SCHEMA = FK2.TABLE_SCHEMA,
REFERENCED_TABLE_NAME = FK2.TABLE_NAME,
REFERENCED_COLUMN_NAME = PK_COLS.COLUMN_NAME
};

select new
{
CONSTRAINT_NAME = rc.CONSTRAINT_NAME,
TABLE_CATALOG = tc.TABLE_CATALOG,
TABLE_SCHEMA = tc.TABLE_SCHEMA,
TABLE_NAME = tc.TABLE_NAME,
COLUMN_NAME = kcu.COLUMN_NAME,
REFERENCED_TABLE_CATALOG = tc2.TABLE_CATALOG,
REFERENCED_TABLE_SCHEMA = tc2.TABLE_SCHEMA,
REFERENCED_TABLE_NAME = tc2.TABLE_NAME,
REFERENCED_COLUMN_NAME = kcu2.COLUMN_NAME
};

use xyz

/*

Truncate All tables within a database

*/

Set NoCount ON

Declare @tableName varchar(200)
Declare @tableName1 varchar(200)

set @tableName=”

DECLARE @intFlag INT
Declare @count INT

–Find all child tables and those which have no relations

select ROW_NUMBER() over (order by t.table_name) sno, T.table_name
into #childtables
from INFORMATION_SCHEMA.TABLES T
left outer join INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC
on T.table_name=TC.table_name where (TC.constraint_Type =’Foreign Key’
or TC.constraint_Type is NULL) and
T.table_name not in (‘dtproperties’,'sysconstraints’,'syssegments’)
and Table_type=’BASE TABLE’ and T.table_name > @TableName

–Find all Parent tables

select ROW_NUMBER() over (order by t.table_name) sno,T.table_name
into #parenttables
from INFORMATION_SCHEMA.TABLES T
left outer join INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC
on T.table_name=TC.table_name where TC.constraint_Type =’Primary Key’
and T.table_name ‘dtproperties’and Table_type=’BASE TABLE’
and T.table_name > @TableName

–select * from #childtables
–select * from #parenttables

SET @intFlag = 1
SET @count = ( Select COUNT(*)as countValue from #childtables )

– Truncate All Child tables
WHILE (@intFlag <= @count)
BEGIN
Select @tableName1 = table_name from #childtables where sno = @intFlag
SET @intFlag = @intFlag + 1
Print @tableName1
Exec('Truncate table '+@tableName1)
print @tableName1 + ' truncated successfully '
END

SET @intFlag = 1
SET @count = ( Select COUNT(*)as countValue from #parenttables)

– Truncate All Parent tables
WHILE (@intFlag <= @count)
BEGIN
Select @tableName1 = table_name from #parenttables where sno = @intFlag
SET @intFlag = @intFlag + 1
Print @tableName1
Exec('Truncate table '+@tableName1)
print @tableName1 + ' truncated successfully '

END

Set NoCount Off

i got the answer, i think this might help you.

— To display table does not having foreign key—

SELECT SCHEMA_NAME(t.schema_id) AS schema_name
,t.name AS table_name
FROM sys.tables t
WHERE object_id NOT IN
(
SELECT parent_object_id
FROM sys.foreign_keys
WHERE type_desc = ‘Foreign_KEY_CONSTRAINT’ — or type = ‘PK’
–where type = ‘FK’
);

I want to display the table which does not have foreign key.
Actually i have a db with 143 tables. Now i want to know the table which does not have any foreign key relationship as i have perform delete query on those tables.
Awaiting your response desperately.
Thank you

- Ferruccio Guicciardi

Thanks for the query. Similar kind of queries i had written but with sys.foreign_keys views instead of REFERENTIAL_CONSTRAINTS.

Is there any other query to be written to show the hierarchial relationships between the tables exists in a DB. The DB diagram would show the logical representation but most of the times we dont have the prvileges to view.

So far i have worked in Oracle, it has the level pseudo column and a hierarchial query joining with dictionary table would give you all the details. In this we can filter with the table names. So that it would be easier to analyse the tables relation as a module wise.

Can you help me in this?

Regards
Mohamed

Is there any other query to be written to show the hierarchial relationships between the tables exists in a DB. The DB diagram would show the logical representation but most of the times we dont have the prvileges to view.

So far i have worked in Oracle, it has the level pseudo column and a hierarchial query joining with dictionary table would give you all the details. In this we can filter with the table names. So that it would be easier to analyse the tables relation as a module wise.

Can you help me in this?

Regards
Mohamed

plz let me know were i m going wrong
thanks in advances

EXEC sp_help ‘table_name’

Msg 547, Level 16, State 0, Line 1
The INSERT statement conflicted with the FOREIGN KEY constraint “FK__t22__e_id__4FD1D5C8″. The conflict occurred in database “master”, table “dbo.t11″, column ‘e_id’.
The statement has been terminated.

create table emp
(e_id int primary key,
e_name varchar(255))

insert table emp values(1,’aa’);
insert table emp values(2,’bb’)

then i created new table:

create table dept
(d_id int primary key,
d_name varchar(255),
e_id int foreign key references emp(e_id))

with this st. it works well:
insert table dept values(11,’computer’,1);

this st. creats problem:
insert table dept values(33,’marketing’,3);

so plz help on this problem

select tbl.constraint_name
, tbl.constraint_type
, tbl.table_schema
, tbl.table_name
, col.column_name
, col3.table_schema as ref_table_name
, col3.table_name as ref_table_name
, col3.column_name as ref_column_name
from information_schema.table_constraints tbl with(nolock)
left join information_schema.constraint_column_usage col with(nolock) on tbl.constraint_name = col.constraint_name
left join information_schema.referential_constraints col2 with(nolock) on tbl.constraint_name = col2.constraint_name
left join information_schema.constraint_column_usage col3 with(nolock) on col2.unique_constraint_name = col3.constraint_name
order by tbl.table_name

select object_name(constid) FKey_Name, object_name(fkeyid) Child_Table, c1.name FKey_Col,
object_name(rkeyid) Parent_Table, c2.name Ref_KeyCol
from sysforeignkeys s
inner join syscolumns c1
on ( s.fkeyid = c1.id
and s.fkey = c1.colid )
inner join syscolumns c2
on ( s.rkeyid = c2.id
and s.rkey = c2.colid )